4 + 9/10 = ? giúp ạ :((
Bài 1:Tính
-5-{-[-(-7)+(-10)]-[5-(-12)]}-[(-3)-(-9)-(+4)-5]
7-{12-[-(-3)+(-10)-(-11)]-[-(-9)+(-8)-(+12)]}-(-4)
Giúp mình vs ạ,mình đang cần gấp!!
(13/-10 - -4/13)+11/10 A=-5/9+8/15+ -2/11 + 4/-9 + 7/15 B=10/17-5/13- -7/17 - 8/13+11/25 (3/4-1/6):2/3 (31/10-5/2).3-2 Giải chi tiết giúp bngoc ạ cmon trước💖
a: =-5/9-4/9+8/15+7/15-2/11=-2/11
b: =10/17+7/17-5/13-8/13+11/25
=11/25
c: =(9/12-2/12)*3/2=7/12*3/2=21/24=7/8
d: =(31/10-25/10)*3-2
=3/5*3-2
=9/5-2
=-1/5
Mn giúp tớ với ạ!
\(P=\frac{2^{19}\times27^3+15\times4^9\times9^4}{6^9\times2^{10}+12^{10}}\)
VIẾT ĐỀ BÀI RỒI = A
A=B/C
B= 219 . 273 + 15 .49 . 94
B= 219 . (33)3 + 5.3 (22)9 . (32)4
B= 219 . 39 +5.3 .218 . 38
B=2
K VÀ KẾT BẠN NHA
\(P=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
\(P=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)
\(P=\frac{2^{18}.3^9\left(2+5\right)}{2^{18}.3^9\left(2+2^2.3\right)}\)
\(P=\frac{7}{14}=\frac{1}{2}\)
tính nhanh
a) \(\dfrac{4}{9}\) x \(\dfrac{3}{5}\) + \(\dfrac{4}{9}\) x \(\dfrac{8}{5}\) - \(\dfrac{4}{9}\) x \(\dfrac{2}{10}\)
b) 312 : 13 + 325 : 13 - 247 : 13
( ghi chi tiết giúp mk ạ )
a) 4/9 x ( 3/5 + 8/5 - 2/10 )
= 4/9 x 1
=4/9
b) ( 312 + 325 - 247 ) : 13
= 390 : 13
= 30
a)4/9 x 3/5 + 4/9 x 8/5 - 4/9 x 2/10
=4/9x(3/5+8/5-2/10)
= 4/9x1
=4/9
b,312 : 13 + 325 : 13 - 247 : 13
=(312+325-247) : 13
= 390 : 3
= 130
\(\left(\frac{9}{19}.\frac{2}{3}+\frac{1}{2}\right).\left(\frac{10}{13}-\frac{2}{4}.\frac{1}{3}\right)\)
\(=\left(\frac{6}{19}+\frac{1}{2}\right).\left(\frac{10}{13}-\frac{1}{6}\right)\)
\(=\frac{31}{38}.\frac{47}{78}=\frac{1457}{2964}\)
(2x-4).(3x)=0
(3x-9).(10-2x)=0
Giúp e với ạ
cái thứ nhất =2
cái thứ 2 bằng3
1) \(\left(2x-4\right)\cdot3x=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-4=0\\3x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=0\end{cases}}\)
2) \(\left(3x-9\right)\left(10-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3x-9=0\\10-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=5\end{cases}}\)
Thỏa mãn điều kiện \(\left(2x-4\right)\)hoặc \(3x\)= 0
\(\Rightarrow\hept{\begin{cases}x=2\\x=0\end{cases}}\)
Tương tự như phần dưới , thỏa mãn điều kiện \(\left(3x-9\right)\)hoặc \(\left(10-2x\right)\)= 0
\(\Rightarrow\hept{\begin{cases}x=3\\x=5\end{cases}}\)
Tính:
-15-(+9)
4-(-7)
-12+(-13)
-(-13)-(-10)
-4-(+7)
(-9)-(-13)
-(-12)+0
0-(+7)
0-(-3)
15-17
-18+12
-5-18
-(-15)+(-15)
Giúp e vs ạ
...=-15-9=-24
...=4+7=11
...=-12-13=-25
...=13+10=23
...=-4-7=-11
...=-9+13=4
...=12+0=12
...=0-7=-7
...=0+3=3
...=15-17=-2
...=-6
...=-23
...=15-15=0
-15-(+9) = -24
4-(-7) = 11
-12+(-13) = -25
-(-13)-(-10) = 23
-4-(+7) = -11
(-9)-(-13) = 4
-(-12)+0 = 12
0-(+7) = -7
0-(-3) = 3
15-17 = -2
-18+12 = -6
-5-18 = -23
-(-15)+(-15) = 0
Giúp mình với ạ Bài 1 Tính 1) 2/9 + -3/4 + 5/30 2) -7/12 - 11/18 3) 7/8 - -5/16 4) 3/8 - -9/10 - 5/16
1)` 2/9 + -3/4 + 5/30= (40+(-135) + 30 )/180 = -65/180 = -13/36`
2) `-7/12 - 11/18=(-21)/36 - 22/36 = -43/36 `
3) `7/8 - (-5)/16=14/16- (-5)/16 = 19/16 `
4) `3/8 - (-9)/10 - 5/16= (30- (-72) -25)/80=77/80`
1)\(\dfrac{2}{9}+\dfrac{-3}{4}+\dfrac{5}{30}\)
\(=\dfrac{2.20}{9.20}+\dfrac{-3.45}{4.45}+\dfrac{5.6}{30.6}\)
\(=\dfrac{40}{180}+\dfrac{-135}{180}+\dfrac{30}{180}\)
\(=\dfrac{40+\left(-135\right)+30}{180}\)
\(=\dfrac{-65}{180}\)
\(=\dfrac{-13}{36}\)
2)\(\dfrac{-7}{12}-\dfrac{11}{18}\)
\(=\dfrac{-7.3}{12.3}-\dfrac{11.2}{18.2}\)
\(=\dfrac{-21}{36}-\dfrac{22}{36}\)
\(=\dfrac{-21-22}{36}\)
\(=\dfrac{-43}{36}\)
3)\(\dfrac{7}{8}-\dfrac{-5}{16}\)
\(=\dfrac{7.2}{8.2}-\dfrac{-5}{16}\)
\(=\dfrac{14}{16}-\dfrac{-5}{16}\)
\(=\dfrac{14-\left(-5\right)}{16}\)
\(=\dfrac{19}{16}\)
4)\(\dfrac{3}{8}-\dfrac{-9}{10}-\dfrac{5}{16}\)
\(=\dfrac{3.10}{8.10}-\dfrac{-9.8}{10.8}-\dfrac{5.5}{16.5}\)
\(=\dfrac{30}{80}-\dfrac{-72}{80}-\dfrac{25}{80}\)
\(=\dfrac{30-\left(-72\right)-25}{80}\)
\(=\dfrac{77}{80}\)
a,(0,8)5:(0,4)6 b, (-25)7:323 c, \(\dfrac{4^2.4^3}{2^{10}}\) d,\(\dfrac{9^5.5^7}{45^7}\)
Giúp em với ạ e cảm ơn nhiều ạ!
a,(0,8)5:(0,4)6 = (\(\dfrac{0,8}{0,4}\))5 : 0,4 = 25:0,4 = 80
b, (-25)7: 323 - \(\dfrac{6103515625}{3276}\) = - 186264,5149
c, \(\dfrac{4^2.4^3}{2^{10}}\) = \(\dfrac{4^5}{2^{10}}\) = \(\dfrac{2^{10}}{2^{10}}\) = 1
d, \(\dfrac{9^5.5^7}{45^7}\) = \(\dfrac{9^5.5^7}{9^7.5^7}\) = \(\dfrac{1}{81}\)
\(\dfrac{\left(0.8\right)^5}{\left(0.4\right)^4}\)=\(\dfrac{\left(2.0,4\right)^5}{\left(0.4^4\right)}\)=\(\dfrac{2^5.\left(0.4\right)^5}{\left(0,4\right)^4}\)=\(2^5\).\(\left(0.4\right)^1\)=12,8
b)câu b không biết có sai đề không nhưng đáp án câu b là -186264,5149
c) \(\dfrac{4^2.4^3}{2^{10}}\)=\(\dfrac{4^5}{\left(2^2\right)^5}\)=\(\dfrac{4^5}{4^5}\)=1
d)\(\dfrac{9^5.5^7}{45^7}\)=\(\dfrac{9^5.5^5.5^2}{45^7}\)=\(\dfrac{45^5.5^2}{45^7}\)=\(\dfrac{5^2}{45^2}\)=\(\left(\dfrac{5}{45}\right)^2\)=\(\left(\dfrac{1}{9}\right)^2\)=\(\dfrac{1}{81}\)