Bỏ dấu ngoặc rồi tính:

a) (123 - 27)+ (27+ 13-123) -= 123 - 27 + 27 + 13 - 123 = 13

​​b) (175 + 25 + 13)-(-15 + 175 + 25) = 175 + 25 + 13 + 15 - 175 - 25 = 28

c) (2012 - 119 + 29) - (-119 + 29) = 2012 - 119 + 29 + 119 - 29 = 20122

​​d) -(55 - 80 + 91) - (2012 + 80 - 91) = - 55 + 80 - 91 - 2012 - 80 + 91 = - 2067

e) 123 + [54 + (-123) + 46] = 123 + 54 - 123 + 46 = 100

f) - 64 + [(-110 + 64 + 71] = -64 -110 +64 + 71 = -39

a) \(9^{21}.9^{33}=9^{21+33}=9^{54}\)

b) \(19^{11}.19.19=19^{11+1+1}=19^{13}\)

c) \(25^2.5^2.125=5^4.5^2.5^3=5^{4+2+3}=5^9\)

d) \(t^{2021}.t^2.\left(t^2\right)^2=t^{2021}.t^2.t^4=t^{2021+2+4}=t^{2027}\)

e) \(123^{14}:123^{13}=123^{14-13}=123\)

f) \(64^2:8^3=\left(8^2\right)^2:8^3=8^4:8^3=8^{4-3}=8=2^3\)

g) \(6^{10}:6^3:36=6^{10}:6^3:6^2=6^{10-3-2}=6^5\)

h) \(m^{20}:m^{10}.m^{10}=m^{20-10+10}=m^{20}\)

c: =2012-119+29+119-29

=2012

a) Ta có:

\(A=\dfrac{-68}{123}\cdot\dfrac{-23}{79}=\dfrac{68}{123}\cdot\dfrac{23}{79}\)

\(B=\dfrac{-14}{79}\cdot\dfrac{-68}{7}\cdot\dfrac{-46}{123}=-\left(\dfrac{14}{79}\cdot\dfrac{68}{7}\cdot\dfrac{46}{123}\right)\)

\(C=\dfrac{-4}{19}\cdot\dfrac{-3}{19}\cdot...\cdot\dfrac{0}{19}\cdot...\cdot\dfrac{3}{19}\cdot\dfrac{4}{19}=0\)

Suy ra A là số hữu tỉ dương, B là số hữu tỉ âm và C là 0.

Vậy A > C > B.

b) Ta có:

\(\dfrac{B}{A}=\dfrac{-\left(\dfrac{14}{79}\cdot\dfrac{68}{7}\cdot\dfrac{46}{123}\right)}{\dfrac{68}{123}\cdot\dfrac{23}{79}}=-\dfrac{14}{79}\cdot\dfrac{68}{7}\cdot\dfrac{46}{123}\cdot\dfrac{123}{68}\cdot\dfrac{79}{23}\)

\(\dfrac{B}{A}=-\dfrac{14\cdot68\cdot46\cdot123\cdot79}{79\cdot7\cdot123\cdot68\cdot23}=-\left(2\cdot2\right)=-4\)

Vậy B : A = -4

Câu 1:

a) Ta có: 2n+1 là số lẻ∀n

⇒\(\left(-1\right)^{2n+1}=-1\)

Ta có: \(\left(-25\right)\cdot21\cdot\left(-2\right)^2\cdot\left(-\left|-3\right|\right)\cdot\left(-1\right)^{2n+1}\)

\(=-25\cdot21\cdot4\cdot\left(-3\right)\cdot\left(-1\right)\)

\(=75\cdot84\cdot\left(-1\right)\)

\(=-6300\)

b) Ta có: \(\left(-5\right)^3\cdot67\cdot\left(-\left|-2^3\right|\right)\cdot\left(-1\right)^{2n}\)

\(=-125\cdot67\cdot\left(-8\right)\)

\(=1000\cdot67=67000\)

c) Ta có: \(35\cdot18-5\cdot7\cdot28\)

\(=35\cdot18-35\cdot28\)

\(=35\cdot\left(18-28\right)=35\cdot\left(-10\right)=-350\)

d) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)

\(=24\cdot16-24\cdot5-24\cdot16+16\cdot5\)

\(=-24\cdot5+16\cdot5\)

\(=5\cdot\left(-24+16\right)=5\cdot\left(-8\right)=-40\)

e) Ta có: \(29\cdot\left(19-13\right)-19\cdot\left(19-13\right)\)

\(=6\cdot\left(29-19\right)=6\cdot10=60\)

g)Sửa đề: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)

Ta có: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)

\(=31\cdot\left(-18-81-1\right)\)

\(=31\cdot\left(-100\right)=-3100\)

h) Ta có: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)

\(=-12\cdot\left(47+52+1\right)\)

\(=-12\cdot100=-1200\)

k) Ta có: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)

\(=13\cdot45-3\cdot45\)

\(=45\cdot\left(13-3\right)=45\cdot10=450\)

m) Ta có: \(-48+48\cdot\left(-78\right)+48\cdot\left(-21\right)\)

\(=48\cdot\left(-1-78-21\right)\)

\(=48\cdot\left(-100\right)=-4800\)

n) Ta có: \(135\cdot\left(171-123\right)-171\cdot\left(135-123\right)\)

\(=135\cdot171-135\cdot123-171\cdot135+171\cdot123\)

\(=123\cdot\left(-135+171\right)=123\cdot36=4428\)

✔

đúng rồi

Đ

1 câu hay 2 câu vậy bn

123 . 19 + 123 . 52 + 123 . 29

= 123 . ( 19 + 52 + 29 )

= 123 . 100

= 12300

123( 19 + 52 + 29)

= 123 . 100

= 12300

= 123. (19+52+29)

= 123. 100

= 12300