10 A = 10 16 + 10 10 16 + 1 = 1 + 9 10 16 + 1 10 B = 10 17 + 10 10 17 + 1 = 1 + 9 10 17 + 1

Vì  9 10 16 + 1 > 9 10 17 + 1 nên  10 A > 10 B

Vậy A > B

\(B=10^{32}-1=\left(10-1\right)\left(10+1\right)\left(10^2+1\right)\left(10^4+1\right)\left(10^8+1\right)\left(10^{16}+1\right)\left(10^{32}+1\right)>\left(10+1\right)\left(10^2+1\right)\left(10^4+1\right)\left(10^8+1\right)\left(10^{16}+1\right)\left(10^{32}+1\right)=A\)Vậy B>A 

sua lai :

1015/1016<1016/1015

nen :1+1015/1016<1+1016/1015

\(1+\frac{1005}{1006}

\(\frac{1015}{1016}

a: 7/8>7/10

b: 16/5>16/7

c: 8/7>1

d: 15/11>1

e: 4/9<1<9/4

f: 11/10>1>10/11

a: 7/8>7/10

b: 16/5>16/7

c: 8/7>1

d: 15/11>1

e: 4/9<1<9/4

f: 11/10>1>10/11

Này, sau viết đề có tâm tí nhé. Nói thẳng, ko hiểu ''---'' của bn là j ?

Làm bài này, lớp 6 nên làm cách quy đồng cho dễ 

Ta có : \(\frac{241}{250}\)và \(\frac{362}{357}\)

Ta được : \(\frac{241}{250}=\frac{86037}{89250}\) và \(\frac{362}{357}=\frac{90500}{89250}\)

Vì \(86037< 90500\)Mà \(\frac{86037}{89250}< \frac{90500}{89250}\)

Suy ra : \(\frac{241}{250}< \frac{362}{357}\)

2²⁵⁰ > 3¹⁰⁰

Ta có :

`2^250 = ( 2^2 )^{125} = 4^{125}`

Do `3^{100} < 4^{100}<4^{125} => 3^{100}<4^{125}=>2^{250}>3^{100}`

Vậy `2^{250}>3^{100}`

Xét 2⁵>2⁴=16 mà 16>9=3²

⇒ 2⁵>3²

⇒ (2⁵)⁵⁰>(3²)⁵⁰

⇒ 2²⁵⁰>3¹⁰⁰

Vậy 2²⁵⁰>3¹⁰⁰

\(4^{250}=\left(2^2\right)^{250}=2^{500}=\left(2^5\right)^{100}=32^{100}\)

Vì \(32^{100}>25^{100}\)nên \(4^{250}>25^{100}\)

Ta có :

\(C=4^{250}=\left(4^5\right)^{50}=1024^{50}\)

\(D=6^{200}=\left(6^4\right)^{50}=1296^{50}\)

Vì : \(1024^{50}< 1296^{50}\Rightarrow C< D\)

dấu > nha bn...

~~ tk mk ik ~~

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-241/250 < -362/357( hay -86037/89250 < -90500/89250)
Chắc chắn đấy!
 

kk nhầm rùi
-247/250> -362/357( hay-86037/89250 > -90500/89250)