\(480:\left(75+7^2-8.3:5\right)+2021^0\)

\(=480:\left(75+49-\dfrac{24}{5}\right)+1\)

\(=480:\left(124-\dfrac{24}{5}\right)+1\)

\(=480:\dfrac{596}{5}+1\)

\(=\dfrac{600}{149}+1=\dfrac{749}{149}\)

a: =545x80-80x445

=8000

\(\frac{75}{100}=\frac{3}{4}=\frac{6}{8}< \frac{7}{8}\)

\(\frac{7}{8}< 1< \frac{3}{2}\)

\(\frac{60}{108}=\frac{5}{9}=\frac{15}{27}>\frac{15}{37}\)

\(\frac{15}{37}=\frac{30}{74}< \frac{31}{74}< \frac{31}{54}\)

\(\frac{0}{16}=\frac{0}{21}\)

Xét \(1-\frac{1965}{1967}=\frac{2}{1967}>\frac{2}{1975}=1-\frac{1973}{1975}\Rightarrow\frac{1965}{1967}< \frac{1973}{1975}\)

\(a,=-2\sqrt{5}+9\sqrt{5}-24\sqrt{5}-\sqrt{5}=-18\sqrt{5}\)

\(b,=2\sqrt{3}-5\sqrt{3}+4\sqrt{3}-7\sqrt{3}=-6\sqrt{3}\)

\(c,=3\sqrt{3}+7\sqrt{3}-9\sqrt{3}+11\sqrt{3}=12\sqrt{3}\)

a) Ta có: \(-\sqrt{20}+3\sqrt{45}-6\sqrt{80}-\dfrac{1}{5}\sqrt{125}\)

\(=-2\sqrt{5}+9\sqrt{5}-24\sqrt{5}-\dfrac{1}{5}\cdot5\sqrt{5}\)

\(=-17\sqrt{5}-\sqrt{5}=-18\sqrt{5}\)

b) Ta có: \(2\sqrt{3}-\sqrt{75}+2\sqrt{12}-\sqrt{147}\)

\(=2\sqrt{3}-5\sqrt{3}+4\sqrt{3}-7\sqrt{3}\)

\(=-6\sqrt{3}\)

a: \(2\sqrt{8\sqrt{3}}-\sqrt{2\sqrt{3}}-\sqrt{9\sqrt{12}}\)

\(=2\sqrt{4\cdot2\sqrt{3}}-\sqrt{2\sqrt{3}}-\sqrt{9\cdot2\sqrt{3}}\)

\(=4\sqrt{2\sqrt{3}}-\sqrt{2\sqrt{3}}-3\sqrt{2\sqrt{3}}\)

=0

b: \(\sqrt{3}+\sqrt{7-4\sqrt{3}}\)

\(=\sqrt{3}+\sqrt{\left(2-\sqrt{3}\right)^2}\)

\(=\sqrt{3}+\left|2-\sqrt{3}\right|\)

\(=\sqrt{3}+2-\sqrt{3}\)

=2

c: \(\sqrt{\left(\sqrt{7}-4\right)^2}-\sqrt{28}+\sqrt{63}\)

\(=\left|\sqrt{7}-4\right|-2\sqrt{7}+3\sqrt{7}\)

\(=4-\sqrt{7}+\sqrt{7}\)

=4

d: \(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):\sqrt{10}\)

\(=\dfrac{\sqrt{10}\left(15\sqrt{5}+5\sqrt{20}-3\sqrt{45}\right)}{\sqrt{10}}\)

\(=15\sqrt{5}+5\sqrt{20}-3\sqrt{45}\)

\(=15\sqrt{5}+5\cdot2\sqrt{5}-3\cdot3\sqrt{5}\)

\(=16\sqrt{5}\)

e: \(\sqrt{3}-2\sqrt{48}+3\sqrt{75}-4\sqrt{108}\)

\(=\sqrt{3}-2\cdot4\sqrt{3}+3\cdot5\sqrt{3}-4\cdot6\sqrt{3}\)

\(=\sqrt{3}-8\sqrt{3}+15\sqrt{3}-24\sqrt{3}\)

\(=-16\sqrt{3}\)

\(1,\sqrt{432}-\sqrt{363}+\sqrt{48}-\sqrt{75}+\sqrt{108}-\sqrt{147}\)

\(=\sqrt{12^2.3}-\sqrt{11^2.3}+\sqrt{4^2.3}-\sqrt{5^2.3}+\sqrt{6^2.3}-\sqrt{7^2.3}\)

\(=12\sqrt{3}-11\sqrt{3}+4\sqrt{3}-5\sqrt{3}+6\sqrt{3}-7\sqrt{3}\)

\(=\sqrt{3}.\left(12-11+4-5+6-7\right)\)

\(=-\sqrt{3}\)

\(2,6\sqrt{60}-5\sqrt{8}+3\sqrt{15}+4\sqrt{32}+3\sqrt{128}-2\sqrt{1250}\)

\(=6.2\sqrt{15}-5.2\sqrt{2}+3\sqrt{15}+4.4\sqrt{2}+3.8\sqrt{2}-2.25\sqrt{2}\)

\(=12\sqrt{15}+3\sqrt{15}-10\sqrt{2}+16\sqrt{2}+24\sqrt{2}-50\sqrt{2}\)

\(=\sqrt{15}.\left(12+3\right)+\sqrt{2}.\left(-10+16+24-50\right)\)

\(=15\sqrt{15}-20\sqrt{2}\)

1/ \(\sqrt{432}-\sqrt{363}+\sqrt{48}-\sqrt{75}+\sqrt{108}-\sqrt{147}\)

\(=12\sqrt{3}-11\sqrt{3}+4\sqrt{3}-5\sqrt{3}+6\sqrt{3}-7\sqrt{3}\)

\(=\left(12-11+4-5+6-7\right)\sqrt{3}\)

\(=-\sqrt{3}\)

2/ \(6\sqrt{60}-5\sqrt{8}+3\sqrt{15}+4\sqrt{32}+3\sqrt{128}-2\sqrt{1250}\)

\(=12\sqrt{15}-10\sqrt{2}+3\sqrt{15}+16\sqrt{2}+24\sqrt{2}-50\sqrt{2}\)

\(=\left(12+3\right)\sqrt{15}+\left(-10+16+24-50\right)\sqrt{2}\)

\(=15\sqrt{15}-20\sqrt{2}\)

a: \(5\sqrt{2}-8\sqrt{3}+30\sqrt{3}-6\sqrt{3}=5\sqrt{2}+16\sqrt{3}\)

b: \(=14\sqrt{3}-\dfrac{3}{32}\cdot8\sqrt{3}+\dfrac{4}{18}\cdot9\sqrt{3}-\dfrac{1}{10}\cdot10\sqrt{3}\)

\(=14\sqrt{3}-\dfrac{3}{4}\sqrt{3}+2\sqrt{3}-1\sqrt{3}=\dfrac{57}{4}\sqrt{3}\)

c: \(=\dfrac{-1}{2}\cdot6\sqrt{3}+\dfrac{1}{15}\cdot5\sqrt{3}-\dfrac{1}{22}\cdot11\sqrt{3}+2\sqrt{3}\)

\(=-3\sqrt{3}+\dfrac{1}{3}\sqrt{3}-\dfrac{1}{2}\sqrt{3}+2\sqrt{3}=-\dfrac{7}{6}\sqrt{3}\)

d: \(=\dfrac{5}{8}\cdot4\sqrt{3}-\dfrac{1}{33}\cdot11\sqrt{3}+\dfrac{3}{14}\cdot7\sqrt{3}-\dfrac{1}{4}\cdot8\sqrt{3}\)

\(=\dfrac{5}{2}\sqrt{3}-\dfrac{1}{3}\sqrt{3}+\dfrac{3}{2}\sqrt{3}-2\sqrt{3}=\dfrac{5}{3}\sqrt{3}\)

KQ =7

=480:[75+(49-8.3):5]+1

=480:[75+(49-24):5]+1

=480:[75+25:5]+1

=480:[75+5]+1

=480:80+1

=6+1

=7

ko xem dc de ban oi :/

2

\(\left(-67\right)+125+\left(-33\right)+75\)

\(=\left[\left(-67\right)+\left(-33\right)\right]+\left(125+75\right)\)

\(=100+200=300\)

_______

\(86.\left(-108\right)+86.9-86\)

\(=86.\left[\left(-108\right)+9-1\right]\)

\(=86.\left(-100\right)=-8600\)

_______

\(23.\left(-16\right)-23.84+300\)

\(=23.\left[\left(-16\right)-84\right]+300\)

\(=23.\left(-100\right)+300\)

\(=-2300+300\)

\(=-2000\)

______

\(235-5\left[\left(5^3-3^3\right):14\right]\)

\(=235-5\left[\left(125-27\right):14\right]\)

\(=235-5\left[98:14\right]\)

\(=235-5.7\)

\(=235-35\)

\(=200\)

_______

\(95-\left(129-74\right):5+2022^0\)

\(=95-55:5+1\)

\(=95-11+1\)

\(=84+1=85\)

\(#NqHahh\)