Rút gọn bt
A= ( x+2/x-2 - x-2/x+12) : ( x^3/8-x^3 + 1)
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25 tháng 9 2021 lúc 16:17
1)Rút gọn bt
a)3x2(x+1)(x-1)-(x2-1)(x4+x2+1)+(x2-1)3
b)(x+y+z)3+(x-y-z)3+(y-x-z)3+(z-y-x)3
2)Phân tích đa thức thành nhân tử:
(x-1)(x+2)(x+3)(x+6)-6(x2+5x)2+45
1)
a) \(=3x^2\left(x^2-1\right)-\left(x^3-1\right)+x^8-3x^4+3x^2-1\)
\(=3x^4-3x^2-x^3+1+x^8-3x^4+3x^2-1=x^8-x^3\)
2)
\(=\left(x^2+5x-6\right)\left(x^2+5x+6\right)-6\left(x^2+5x\right)+45\)
\(=\left(x^2+5x\right)^2-6\left(x^2+5x\right)-36+45\)
\(=\left(x^2+5x\right)^2-6\left(x^2+5x\right)+9=\left(x^2+5x-3\right)^2\)
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Rút gọn,tìm ĐKXĐ:
1/ x-1-x^3-x/x^2+1(1/x^2-2x+1+1/1-x^2)
2/ 3x^2+6x+12/x^3-8
2: ĐKXĐ: \(x\ne2\)
\(\dfrac{3x^2+6x+12}{x^3-8}=\dfrac{3\left(x^2+2x+4\right)}{\left(x-2\right)\left(x^2+2x+4\right)}=\dfrac{3}{x-2}\)
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rút gọn rồi tính C=(x/2-y)^3-6(y-x/2)^2+12(y-x/3)-8 với x=206; y=1
\(C=\left(\frac{x}{2}-y\right)^3-3.2.\left(\frac{x}{2}-y\right)^2+3.2^2\left(\frac{x}{2}-y\right)-2^3=\left(\frac{x}{2}-y-2\right)^3\)
với \(x=206,y=1\Rightarrow C=\left(\frac{x}{2}-y-2\right)^3=\left(\frac{206}{2}-1-2\right)^3=1000\text{ }000\)
rút gọn (x+1)2 -2(x-3)(x+3)+(x-2)2 tại x=12
\(=x^2+2x+1-2x^2+18+x^2-4x+4\\ =-2x+23=-2\cdot12+23=-24+23=-1\)
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rút gọn B=(x+y)^3 +3(x-y)(x+y)^2+3(x-y)^2(x+y)+(x-y)^3
C=8(x/2 +y)3-6(x+2y)2x+12(x+2y)x2-8x3
D=(x-y)3-(3(x-y)2/2)y+(3(x-y)/4)y^2-y3/8
\(B=\left(x+y\right)^3+3\left(x-y\right)\left(x+y\right)^2+3\left(x-y\right)^2\left(x+y\right)+\left(x-y\right)^3\)
\(=\left(x+y\right)^3+3\cdot\left(x+y\right)^2\cdot\left(x-y\right)+3\cdot\left(x+y\right)\cdot\left(x-y\right)^2+\left(x-y\right)^3\)
\(=\left[\left(x+y\right)+\left(x-y\right)\right]^3\)
\(=\left(x+y+x-y\right)^3\)
\(=\left(2x\right)^3\)
\(=8x^3\)
\(---\)
\(C=8\left(x+2y\right)^3-6\left(x+2y\right)^2x+12\left(x+2y\right)x^2-8x^3\) (sửa đề)
\(=\left[2\left(x+2y\right)\right]^3-3\cdot\left(x+2y\right)^2\cdot2x+3\cdot\left(x+2y\right)\cdot\left(2x\right)^2-\left(2x\right)^3\)
\(=\left[2\left(x+2y\right)-2x\right]^3\)
\(=\left(2x+4y-2x\right)^3\)
\(=\left(4y\right)^3\)
\(=64y^3\)
\(---\)
\(D=\left(x-y\right)^3-3\cdot\dfrac{\left(x-y\right)^2}{2}\cdot y+3\cdot\dfrac{\left(x-y\right)}{4}\cdot y^2-\dfrac{y^3}{8}\)
\(=\left(x-y\right)^3-3\cdot\left(x-y\right)^2\cdot\dfrac{y}{2}+3\cdot\left(x-y\right)\cdot\left(\dfrac{y}{2}\right)^2-\left(\dfrac{y}{2}\right)^3\)
\(=\left[\left(x-y\right)-\dfrac{y}{2}\right]^3\)
\(=\left(x-y-\dfrac{y}{2}\right)^3\)
\(=\left(x-\dfrac{3}{2}y\right)^3\)
#\(Toru\)
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rút gọn các biểu thức sau
\(B=\dfrac{3\text{x}^2+6\text{x}+12}{x^3-8\dfrac{ }{ }}\)
C=\(\left(\dfrac{x+1}{2\text{x}-2}+\dfrac{3}{x^2-1}-\dfrac{x+3}{2\text{x}+2}\right).\dfrac{4\text{x}^2-4}{5}\)
E=\(\dfrac{x^2-10\text{x}+25}{x^2-5\text{x}}\)
c: \(E=\dfrac{\left(x-5\right)^2}{x\left(x-5\right)}=\dfrac{x-5}{x}\)
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Phân tích các đa thức sau thành nhân tử
a)2x^2 + 6x=
b) x^4 + 3x^3 + x +3=
c) 64- x^2 - y^2 + 2xy=
Rứt gọn bt
A= ( x+ 5) ( x+ 1)+ (x-2) (x^2+ 2xx +4)- (x^2+ x-2)
giúp mình nhanh với
\(a,=2x\left(x+3\right)\\ b,=x^3\left(x+3\right)+\left(x+3\right)=\left(x^3+1\right)\left(x+3\right)\\ =\left(x+1\right)\left(x+3\right)\left(x^2-x+1\right)\\ c,=64-\left(x-y\right)^2=\left(8-x+y\right)\left(8+x-y\right)\\ A=x^2+6x+5+x^3-8-x^2-x+2\\ A=x^3+5x-1\)
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a) 2x2+6x=2x(x+3)
b) x4+3x3+x+3=(x4+x)+(3x3+3)=x(x3+1)+3(x3+1)=(x+3)(x3+1)
c) 64-x2-y2+2xy=-(x2-2xy+y2)+82=8-(x+y)2=(8+x+y)(8-x-y)
A= (x+5)(x+1)+(x-2)(x2+2xx+4)-(x2+x-2)
A= x2+6x+5+x3-8-x2-x+2
A= x3+(x2-x2)+(6x-x)+(5-8+2)
A= x3+5x-1
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rút gọn biểu thức x^10-x^8-x^7+x^6+x^5+x^4-x^3-x^2+1/x^30+x^24+x^18+x^12+x^6+1
Rút gọn biểu thức.
a)A=(x+2)3+(x-2)3-2x(x2+12)
b)B=(xy+2)3-6(xy+2)2+12(xy+2)-8
a) A = (x + 2)³ + (x - 2)³ - 2x(x² + 12)
= x³ + 6x² + 12x + 8 + x³ - 6x² + 12x - 8 - 2x² - 24x
= (x³ + x³) + (6x² - 6x² - 2x²) + (12x + 12x - 24x) + (8 - 8)
= 2x³ -2x²
b) B = (xy + 2)³ - 6(xy + 2)² + 12(xy + 2) - 8
= (xy + 2 - 2)³
= (xy)³
= x³y³
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