1) 5 + (-4) = 1

2) (-8) + 2 = -6

3) 8 + (-2) = 6

4) 11 + (-3) = 8

5) (-11) + 2 = -9

6) (-7) + 3 = -4

7) (-5) + 5 = 0

8) 11 + (-12) = -1

9) (-18) + 20 = 2

10) (15) + (-12) = 3

11) (-17) + 17 = 0

12) 16 + (-2) = 14

13) (30) + (-14) = 16

14) (-19) + 20 = 1

15) (-18) + 15 = -3

16) (10) + (-6) = 4

17) (-28) + 14 = -14

18) 15 + (-30) = -15

19) (15) + (-4) = 11

20) (-21) + 11 = -10

21) 8 + (-22) = -14

22) (-15) + 4 = -11

23) (-3) + 2 = -1

24) 17 + (-14) = 3

25) 17 + (-14) = 3

thế này đọc đc mới đỉnh

\(\left(-\dfrac{5}{4}\right).\dfrac{7}{9}+\left(-\dfrac{5}{4}\right).\dfrac{2}{9}=\left(-\dfrac{5}{4}\right).\left(\dfrac{7}{9}+\dfrac{2}{9}\right)=\left(-\dfrac{5}{4}\right).1=-\dfrac{5}{4}\)

-5/4

\(=\dfrac{29}{2^6}+\dfrac{34}{2}=\dfrac{29}{64}+17=\dfrac{1117}{64}\)

Cứu với mn ơi huhu !!

\(\dfrac{3}{x-3}-\dfrac{6x}{x^2-9}=\dfrac{3\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}-\dfrac{6x}{\left(x-3\right)\left(x+3\right)}=\dfrac{3x+9}{\left(x-3\right)\left(x+3\right)}-\dfrac{6x}{\left(x-3\right)\left(x+3\right)}=\dfrac{3x+9-6x}{\left(x-3\right)\left(x+3\right)}=\dfrac{-3x+9}{\left(x-3\right)\left(x+3\right)}=\dfrac{-3\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}=\dfrac{-3}{x+3}\)

lỗi rồi

 Thực hiện phép tính :

3               6x

___   -   ________

x- 3         x^2 - 9

\(\left\{240-\left[76-\left(9-3\right)^2\right]\right\}:50\)

\(=\left[240-\left(76-6^2\right)\right]:50\)

\(=\left[240-\left(76-36\right)\right]:50\)

\(=\left(240-40\right):50\)

\(=200:50\)

\(=4\)

_______________

\(\dfrac{4^6\cdot3^4\cdot9^5}{6^{12}}\)

\(=\dfrac{2^{12}\cdot3^4\cdot3^{10}}{6^{12}}\)

\(=\dfrac{2^{12}\cdot3^{14}}{2^{12}\cdot3^{12}}\)

\(=\dfrac{1\cdot3^2}{1\cdot1}\)

\(=3^2\)

\(=9\)

(-35) + 19 + 35 + (-9) +1

=[(-35)+35] + [19+(-9)] +1

=10 + 1

=11

\(\left(-35\right)+19+35+\left(-9\right)+1\)

\(=\left(-35+35\right)+\left[19+\left(-9\right)\right]+1\)

\(=10+1\)

\(=11\)