tìm x:
a.x^10=x
b.x^18 - x^3=0
c.(x-5)^4=(x-5)^6
d.(2x-15)^5=(2x-15)^3
Bài 1: Tìm x
a) 3(x-1)^2.3x(x-5)=0
b) (x+3)^2-5x-15=0
c) 2x^5-4x^3+2x=0
a) \(3\left(x-1\right)^2\cdot3x\left(x-5\right)=0\)
\(\Rightarrow9x\left(x-1\right)^2\left(x-5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\\x-5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\\x=5\end{matrix}\right.\)
b) \(\left(x+3\right)^2-5x-15=0\)
\(\Rightarrow\left(x+3\right)^2-5\left(x+3\right)=0\)
\(\Rightarrow\left(x+3\right)\left(x+3-5\right)=0\)
\(\Rightarrow\left(x+3\right)\left(x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)
c) \(2x^5-4x^3+2x=0\)
\(\Rightarrow2x\left(x^4-2x^2+1\right)=0\)
\(\Rightarrow2x\left[\left(x^2\right)^2-2\cdot x^2\cdot1+1^2\right]=0\)
\(\Rightarrow2x\left(x^2-1\right)^2=0\)
\(\Rightarrow2x\left(x-1\right)^2\left(x+1\right)^2=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\\x=-1\end{matrix}\right.\)
\(\text{#}Toru\)
3) Tìm x của N biết a) 80 - ( 2 + 2x ) : 2 = 40 b) 11^2 - 121 = 0 c) 5^x+3 - 7 × 5^2 = 5^2 × 18 d) x^10 = x e) x^10 = 1^x g) ( 2x - 15 )^5 = ( 2x - 15 )^3 4) Thực hiện phép tính a) 5^3 ÷ 5^2 + 2^2 × 3 b) 4^3 × 125 - 125 ÷ 5^2 c) 6^2 × 28 + 72 × 6^2 d) 5^6 ÷ 5^4 + 3 × 3^2 - 80 e) 2^3 × 19 - 2^3 × 14 × 1^2021
Tìm x, biết:
1) 14x - 5 = 8x + 10
2) 15 + 5x = 3x + 30
3) 2x - 5 = 15- 3x
4) 2 ( 3x + 5 ) + 3 ( x + 1 ) = 6x + 20
5) 4 ( x - 3 0 + 5 ( x - 3 ) = 18
1) 14x-8x=10+5
x(14-8)=15
x6=15
x=15/6
2)5x-3x=30-15
2x=15
x=15/2
3)làm tương tự
1) x=2,5
2) x=7,5
3) x=4
4) x=7/3
5) x=8,25
1 tìm x thuộc Z
-2x-40=(5-x)-(-15+60)
2.(x-5)-3(x+7)=14
-7.(5-x)-2(x-10)=15
x+18=2-2x
-2x - 40 = (5 - x) - (-15 + 60)
-2x - 40 = (5 - x) - 45
-2x - 40 = -40 - x
-2x - x = 40 - 40
-3x = 0
x = 0
2(x - 4) - 3(x + 7) = 14
2x - 8 - 3x - 21 = 14
-x - 29 = 14
-x = 14 + 29
-x = 43
x = -43
-7(5 - x) - 2(x - 10) = 15
-35 + 7x - 2x + 20 = 15
-15 + 5x = 15
5x = 15 + 15
5x = 30
x = 6
\(-2x-40=\left(5-x\right)-\left(-15+60\right)\)
\(\Leftrightarrow\)\(-2x-40=5-x+15-60\)
\(\Leftrightarrow\)\(-2x-40=-x-40\)
\(\Leftrightarrow\)\(-2x+x=40-40\)
\(\Leftrightarrow\)\(x=0\)
Vậy....
\(x+18=2-2x\)
\(2x+x=2-18\)
\(3x=-20\)
\(x=-20:3\)
\(x=\frac{-20}{3}\)
1) 4x-(2x-5)=21
2) 14x+5=8x+10
3) 15+5x=3x+30
4) 2x-5=15-3x
5) 2(3x+5)+3(x+1)=6x+20
6) 4(x-3)+5(x-3)=18
1) 4x-(2x-5)=21
4x-2x+5=21
2x+5=21
2x=21 -5
2x=16
x=16/2
x=8
2)14x+5=8x+10
14x-8x=10-5
6x=5
x=5/6
3) 15+5x=3x+30
5x-3x=30-15
2x=15
x=15/2
Vậy x=15/2
Tìm số tự nhiên x biết:
a) (10-2x).(3x-18)=0 b) 10 + 2x = 165: 216 c) 28 - 2.(x - 4)2=10 d) (15-x)3.(x2 + 16) = 0 e) 52x - 3 - 2.52 = 52 . 3
f) (8 - x3).(x2 + 16) = 0 j) (2x + 5) + (2x + 10) +(2x + 15) +...+(2x + 95) = 77520
Giúp mình 4 câu này với :<
Bài 1: Tìm x
a) 2x(x - 3) + x - 3 = 0
b) x2 (x - 6) - x2 + 36 = 0
c) 5 - 6x + x2 = 0
d) x(x + 5) + x(x + 15) = 0
Cảm ơn các bạn nhaaaa
a: Ta có: \(2x\left(x-3\right)+x-3=0\)
\(\Leftrightarrow\left(x-3\right)\left(2x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{1}{2}\end{matrix}\right.\)
b: Ta có: \(x^2\left(x-6\right)-x^2+36=0\)
\(\Leftrightarrow\left(x-6\right)\left(x^2-x-6\right)=0\)
\(\Leftrightarrow\left(x-6\right)\left(x-3\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=3\\x=-2\end{matrix}\right.\)
Tìm số nguyên x, biết:
1) -16 + 23 + x = - 16
2) 2x – 35 = 15
3) 3x + 17 = 12
4) (2x – 5) + 17 = 6
5) 10 – 2(4 – 3x) = -4
6) - 12 + 3(-x + 7) = -18
Tìm số nguyên x, biết:
1) -16 + 23 + x = - 16
7+x=-16
x=-16-7
x=-23
2) 2x – 35 = 15
2x=15+35
2x=50
x=50:2
x=25
3) 3x + 17 = 12
3x=12-17
3x=-5
x=-5/3
4) (2x – 5) + 17 = 6
2x-5=6-17
2x-5=-11
2x=-11+5
2x=-6
x=-6:2
x=-3
5) 10 – 2(4 – 3x) = -4
2(4-3x)=10-(-4)
2(4-3x)=14
4-3x=14:2
4-3x=7
3x=4-7
3x=-3
x=-3:3
x=-1
6) - 12 + 3(-x + 7) = -18
3(-x+7)=-18-(-12)
3(x+7)=-6
x+7=-6:3
x+7=-2
x=-2-7
x=-9
tự đi mà làm
giải các phương trình sau
a)3x-6=0 b)(3x+2)(4x-5)=0
c)2x-5/3 +x-3/5 =4x+3/15 d)5/x-3 +4/x+3 =x-5/x bình-9
a) 3x-6=0
3x=6 => x=2
b) (3x+2)(4x-5)=0
=> 3x+2=0 => x=-2/3
hoặc 4x-5=0 => x=5/4
câu c ,d thiếu dấu '=" để thành 1 pt rồi bạn
c) \(\dfrac{2x-5}{3}+\dfrac{x-3}{5}=\dfrac{4x+3}{15}\)
=> 10x -25 +3X-9=4X+3
=>9x=37
=>x=37/9
d) \(\dfrac{5}{x-3}+\dfrac{4}{x+3}=\dfrac{x-5}{x^2-9}\) ĐK (x khác 3,-3)
=>5x+15+4x-12=x-5
=>8x=-8
=>x=-1