/ là phần

1) \(x-36:18=12\)

\(\Rightarrow x-2=12\)

\(\Rightarrow x=14\)

2) \(\left(x-36\right):18=12\)

\(\Rightarrow x-36=216\)

\(\Rightarrow x=252\)

32.(18-12)-18.(32-12)

32.6-18.10

192-180

12

32.(18 - 12) - 18(32 - 12) = 32.18 - 18.32 - 32.12 + 18.12 = (18 - 32).12 = (-14).12 = (-4).6.7 = (-4).42 = 168

\(\frac{15-\frac{15}{7}-\frac{15}{12}-\frac{15}{98}}{18-\frac{18}{7}-\frac{18}{12}-\frac{18}{98}}\)= \(\frac{15-15\left(\frac{1}{7}+\frac{1}{12}+\frac{1}{98}\right)}{18-18\left(\frac{1}{7}+\frac{1}{12}+\frac{1}{98}\right)}\)=\(\frac{15\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}{18\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}\)= \(\frac{15}{18}\)=\(\frac{5}{6}\)

cảm ơn nhìu

\(\frac{15-\frac{15}{7}-\frac{15}{12}-\frac{15}{98}}{18-\frac{18}{7}-\frac{18}{12}-\frac{18}{98}}=\frac{15\left(1+\frac{1}{7}+\frac{1}{12}+\frac{1}{98}\right)}{18\left(1+\frac{1}{7}+\frac{1}{12}+\frac{1}{98}\right)}=\frac{15}{18}=\frac{5}{6}\)

a: =8/5-2/3=24/15-10/15=14/15

12/20-6/18=3/5-1/3=9/15-5/15=4/15

b: 18/21-12/27=6/7-7/9=54/63-49/63=5/63

8/12-20/50=2/3-2/5=10/15-6/15=4/15

\(a,\dfrac{8}{5}-\dfrac{18}{27}=\dfrac{8}{5}-\dfrac{2}{3}=\dfrac{14}{15}\\ \dfrac{12}{20}-\dfrac{6}{18}=\dfrac{3}{5}-\dfrac{1}{3}=\dfrac{4}{15}\\ b,\dfrac{18}{21}-\dfrac{12}{27}=\dfrac{6}{7}-\dfrac{4}{9}=\dfrac{26}{63}\\ \dfrac{8}{12}-\dfrac{20}{50}=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{4}{15}\)

b: 12/20+6/18=3/5+1/3=9/15+5/15=14/15

c: 8/12+20/30=2/3+2/3=4/3

d: 10/12+12/36=5/6+2/6=7/6

\(15-\frac{15}{7}-\frac{15}{12}-\frac{1}{98}\)

\(=15\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)\)

\(=15x\frac{449}{588}=\frac{2245}{196}\)

\(18-\frac{18}{7}-\frac{18}{12}-\frac{18}{98}\)

\(=18\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)\)

\(=18x\frac{449}{588}=\frac{1347}{98}\)

\(x-\dfrac{x}{12}+\dfrac{x}{\dfrac{18}{7}}-\dfrac{7}{12}+\dfrac{7}{18}=-\dfrac{4}{7}\)

\(\Rightarrow x\left(1-\dfrac{1}{12}+\dfrac{1}{\dfrac{18}{7}}\right)=-\dfrac{4}{7}+\dfrac{7}{12}-\dfrac{7}{18}\)

\(\Rightarrow x\left(\dfrac{216-18+7}{12.18}\right)=\dfrac{-864+882-588}{7.12.18}\)

\(\Rightarrow x\left(\dfrac{205}{12.18}\right)=\dfrac{-570}{7.12.18}\)

\(\Rightarrow x=\dfrac{-570}{7.12.18}.\dfrac{12.18}{205}\)

\(\Rightarrow x=\dfrac{-114}{287}\)