Tính giá trị của biểu thức
A = \(\dfrac{5}{26}.\dfrac{17}{23}+\dfrac{5}{23}.\dfrac{9}{26}\)
Tính hợp lí:
\(\dfrac{-5}{23}\).\(\dfrac{17}{26}\)+\(\dfrac{5}{23}\).\(\dfrac{9}{-26}\)
\(\dfrac{-5}{23}\cdot\dfrac{17}{26}+\dfrac{5}{23}\cdot\dfrac{9}{-29}\)
= \(\dfrac{5}{23}\cdot\dfrac{-17}{26}+\dfrac{5}{23}\cdot\dfrac{-9}{29}\)
= \(\dfrac{5}{23}\left(\dfrac{-17}{26}+\dfrac{-9}{26}\right)\)
= \(\dfrac{5}{23}\cdot\left(-1\right)=\dfrac{-5}{23}\)
\(\dfrac{-5}{23}.\dfrac{17}{26}+\dfrac{5}{23}.\dfrac{9}{-26}=\dfrac{-5}{23}.\left(\dfrac{17}{26}+\dfrac{9}{26}\right)\)
\(=\dfrac{-5}{23}.\left(\dfrac{17+9}{26}\right)=\dfrac{-5}{23}.\dfrac{26}{26}\)
\(=\dfrac{-5}{23}.1=\dfrac{-5}{23}\)
>; <; = ?
a) \(\dfrac{21}{23}\) ? \(\dfrac{19}{23}\) \(\dfrac{8}{5}\) ? \(\dfrac{49}{30}\) \(\dfrac{20}{36}\) ? \(\dfrac{5}{9}\)
b) \(\dfrac{11}{15}\) ? \(\dfrac{11}{17}\) \(\dfrac{26}{13}\) ? 2 3 ? \(\dfrac{16}{5}\)
c) \(\dfrac{8}{9}\) ? 1 1 ? \(\dfrac{31}{27}\) \(\dfrac{8}{9}\) ? \(\dfrac{31}{27}\)
a) \(\dfrac{21}{23}>\dfrac{19}{23}\)
\(\dfrac{8}{5}=\dfrac{49}{30}\)
\(\dfrac{23}{36}>\dfrac{5}{9}\)
b) \(\dfrac{11}{15}>\dfrac{11}{17}\)
\(\dfrac{26}{13}=2\)
\(3< \dfrac{16}{5}\)
c) \(\dfrac{8}{9}< 1\)
\(1< \dfrac{31}{27}\)
\(\dfrac{8}{9}< \dfrac{31}{27}\)
tính giá trị biểu thức
a) A= \(\dfrac{16^5.15^5}{2^{10}.3^5.5^4}\)
b) B= \(\dfrac{2^{15}.3+2^{19}.10}{2^{12}.26}\)
c) C= \(\dfrac{9^5.30^3}{3^{15}.5^3.6^2}\)
d) D= \(\dfrac{3^{11}.4+3^{11}.5}{3^3.9^5}\)
giúp mik mik sẽ tik cho nhé
a: \(A=\dfrac{16^5\cdot15^5}{2^{10}\cdot3^5\cdot5^4}=\dfrac{2^{20}\cdot3^5\cdot5^5}{2^{10}\cdot3^5\cdot5^4}=2^{10}\cdot5=5120\)
b: \(B=\dfrac{2^{15}\cdot3+2^{19}\cdot10}{2^{12}\cdot26}=\dfrac{2^{15}\left(3+2^4\cdot10\right)}{2^{13}\cdot13}=2^2\cdot\dfrac{163}{13}=\dfrac{652}{13}\)
Bài 2 Tính nhanh
a) \(\dfrac{5}{23}\) x \(\dfrac{17}{26}\) + \(\dfrac{5}{23}\) x \(\dfrac{10}{26}\) - \(\dfrac{5}{23}\)
b) \(\dfrac{1}{7}\) x \(\dfrac{5}{9}\) + \(\dfrac{5}{9}\) x \(\dfrac{2}{7}\) + \(\dfrac{5}{9}\) x \(\dfrac{1}{7}\) + \(\dfrac{5}{9}\) x \(\dfrac{3}{7}\)
a)\(\dfrac{5}{23}.\dfrac{17}{26}+\dfrac{5}{23}.\dfrac{10}{26}-\dfrac{5}{23}\)
\(=\dfrac{5}{23}\left(\dfrac{17}{26}+\dfrac{10}{26}-1\right)\)
\(=\dfrac{5}{23}.\left(\dfrac{27}{26}-1\right)\)
\(=\dfrac{5}{23}.\dfrac{1}{26}\)
\(=\dfrac{5}{598}\)
b)\(\dfrac{1}{7}.\dfrac{5}{9}+\dfrac{5}{9}.\dfrac{2}{7}+\dfrac{5}{9}.\dfrac{1}{7}+\dfrac{5}{9}.\dfrac{3}{7}\)
\(=\dfrac{5}{9}.\left(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{1}{7}+\dfrac{3}{7}\right)\)
\(=\dfrac{5}{9}.1=\dfrac{5}{9}\)
a)\(\dfrac{5}{23}.\dfrac{17}{26}+\dfrac{5}{23}.\dfrac{10}{26}-\dfrac{5}{23}\)
\(=\dfrac{5}{23}.\left(\dfrac{17}{26}+\dfrac{10}{26}-1\right)\)
\(=\dfrac{5}{23}.\left(\dfrac{27}{26}-\dfrac{26}{26}\right)\)
=\(\dfrac{5}{23}.\dfrac{1}{26}\)
\(=\dfrac{5}{598}\)
b)\(\dfrac{1}{7}.\dfrac{5}{9}+\dfrac{5}{9}.\dfrac{2}{7}+\dfrac{5}{9}.\dfrac{1}{7}+\dfrac{5}{9}.\dfrac{3}{7}\)
\(=\dfrac{5}{9}.\left(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{1}{7}+\dfrac{3}{7}\right)\)
\(=\dfrac{5}{9}.\left(\dfrac{7}{7}\right)\)
=\(\dfrac{5}{9}.1\)
\(=\dfrac{5}{9}\)
a)\(=\dfrac{5}{23}\cdot\left(\dfrac{17}{26}+\dfrac{10}{26}-1\right)=\dfrac{5}{23}\cdot\dfrac{1}{26}=\dfrac{5}{598}\)
b)\(=\dfrac{5}{9}\cdot\left(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{1}{7}+\dfrac{3}{7}\right)=\dfrac{5}{9}\cdot1=\dfrac{5}{9}\)
Hi Hi
Bài 3: Tính hợp lí các giá trị biểu thức sau
A= \(49\dfrac{8}{23}=-\left(5\dfrac{7}{32}+14\dfrac{8}{23}\right)\)
B=\(71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{57}\right)\)
a: \(A=49+\dfrac{8}{23}-14-\dfrac{8}{23}-5-\dfrac{7}{32}=30-\dfrac{7}{32}=\dfrac{953}{32}\)
b:
Sửa đề: \(B=71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{51}\right)\)
\(B=71+\dfrac{38}{45}-43-\dfrac{8}{45}+1+\dfrac{17}{51}\)
\(=71-43+1+1\)
=28+2=30
Bài 3: Tính hợp lí các giá trị biểu thức sau:
A=\(49\dfrac{8}{23}-\left(5\dfrac{7}{32}+14\dfrac{8}{23}\right)\)
B=\(71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{57}\right)\)
a: \(A=49+\dfrac{8}{23}-14-\dfrac{8}{23}-5-\dfrac{7}{32}=30-\dfrac{7}{32}=\dfrac{953}{32}\)
b:
Sửa đề: \(B=71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{51}\right)\)
\(B=71+\dfrac{38}{45}-43-\dfrac{8}{45}+1+\dfrac{17}{51}\)
\(=71-43+1+1\)
=28+2=30
tính giá trị của biểu thức
a) \(log_2\dfrac{9}{10}\)+ \(log_330\)
b) \(log_3\dfrac{5}{9}\) - \(2log_3\sqrt{5}\)
c) \(log_2\dfrac{16}{3}+2log_2\sqrt{6}\)
\(log_2\dfrac{9}{10}+log_330=\) ? bạn chắc đề đúng chứ, 2 cơ số ko giống nhau, rút gọn cũng được nhưng nó sẽ không gọn trên thực tế.
\(log_3\dfrac{5}{9}-2log_3\sqrt{5}=log_3\dfrac{5}{9}-log_35=log_3\left(\dfrac{1}{9}\right)=log_33^{-2}=-2\)
\(log_2\dfrac{16}{3}+2log_2\sqrt{6}=log_2\dfrac{16}{3}+log_26=log_2\left(\dfrac{16}{3}.6\right)=log_232=log_22^5=5\)
Thực hiện phét tính B=\(\dfrac{155-\dfrac{10}{7}-\dfrac{5}{11}+\dfrac{5}{23}}{403-\dfrac{26}{7}-\dfrac{13}{11}+\dfrac{13}{23}}+\dfrac{\dfrac{-3}{5}-\dfrac{3}{13}+0,9}{\dfrac{2}{5}+\dfrac{2}{13}-\dfrac{6}{10}}\)
a)\(\dfrac{-3}{7}+\dfrac{15}{26}-\left(\dfrac{2}{13}-\dfrac{3}{7}\right)\)
b)\(2.\dfrac{3}{7}+\left(\dfrac{2}{9}-1\dfrac{3}{7}\right)-\dfrac{5}{3}:\dfrac{1}{9}\)
c)\(\dfrac{-11}{23}.\dfrac{6}{7}+\dfrac{8}{7}.\dfrac{-11}{23}-\dfrac{1}{23}\)
d)\(\left(\dfrac{377}{-231}-\dfrac{123}{89}+\dfrac{34}{791}\right).\left(\dfrac{1}{6}-\dfrac{1}{8}-\dfrac{1}{24}\right)\)
nhanh lên giúp mình vs
a) Ta có: \(\dfrac{-3}{7}+\dfrac{15}{26}-\left(\dfrac{2}{13}-\dfrac{3}{7}\right)\)
\(=\dfrac{-3}{7}+\dfrac{15}{26}-\dfrac{2}{13}+\dfrac{3}{7}\)
\(=\dfrac{15}{26}-\dfrac{4}{26}\)
\(=\dfrac{11}{26}\)
b) Ta có: \(2\cdot\dfrac{3}{7}+\left(\dfrac{2}{9}-1\dfrac{3}{7}\right)-\dfrac{5}{3}:\dfrac{1}{9}\)
\(=\dfrac{6}{7}+\dfrac{2}{9}-\dfrac{10}{7}-\dfrac{5}{3}\cdot9\)
\(=\dfrac{-4}{7}+\dfrac{2}{9}-15\)
\(=\dfrac{-36}{63}+\dfrac{14}{63}-\dfrac{945}{63}\)
\(=\dfrac{-967}{63}\)
c) Ta có: \(\dfrac{-11}{23}\cdot\dfrac{6}{7}+\dfrac{8}{7}\cdot\dfrac{-11}{23}-\dfrac{1}{23}\)
\(=\dfrac{-11}{23}\cdot\left(\dfrac{6}{7}+\dfrac{8}{7}\right)-\dfrac{1}{23}\)
\(=\dfrac{-11}{23}\cdot2-\dfrac{1}{23}\)
\(=-1\)
d) Ta có: \(\left(\dfrac{377}{-231}-\dfrac{123}{89}+\dfrac{34}{791}\right)\cdot\left(\dfrac{1}{6}-\dfrac{1}{8}-\dfrac{1}{24}\right)\)
\(=\left(\dfrac{-377}{231}-\dfrac{123}{89}+\dfrac{34}{791}\right)\cdot\left(\dfrac{4}{24}-\dfrac{3}{24}-\dfrac{1}{24}\right)\)
\(=\left(\dfrac{-377}{231}-\dfrac{123}{89}+\dfrac{34}{791}\right)\cdot0\)
=0
Bài 1 : thực hiện các phép tính ( tính hợp lí nếu có thể ):
a ,\(\dfrac{7}{2}.\dfrac{8}{13}+\dfrac{8}{13}.\dfrac{-5}{2}+\dfrac{8}{13}\)
b , \(\dfrac{-5}{17}.\dfrac{-9}{23}+\dfrac{9}{23}.\dfrac{-22}{17}+11\dfrac{9}{23}\)
Bài 2 : tìm x , biết :
a , \(\dfrac{7}{8}+x=\dfrac{3}{5}\)
b , \(\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-4}{24}\)
Bài 2 :
a, \(x=\dfrac{3}{5}-\dfrac{7}{8}=\dfrac{24-30}{40}=-\dfrac{6}{40}=-\dfrac{3}{20}\)
b, \(2x-1=-2\Leftrightarrow x=-\dfrac{1}{2}\)