Bạn dùng công thức này mà làm nhé :\(\frac{n}{a\times\left(a+n\right)}=\frac{1}{a}-\frac{1}{a+n}\)

Ví dụ :\(\frac{2}{3\times5}=\frac{1}{3}-\frac{1}{5};\frac{3}{4\times7}=\frac{1}{4}-\frac{1}{7};\frac{5}{6\times11}=\frac{1}{6}-\frac{1}{11}\)

a: =5*1,4-4*1,5+3*1,3

=7-6+3,9=4,9

b: =1/3*7+3/4*18-2/3*20

=7/3+54/4-40/3

=-11+54/4

=2,5

c: =5/6*17-1/2*16+2/5*15

=85/6-8+6

=85/6-2

=73/6

d: =15*4/5+12*3/4-18*4/9

=12+9-8

=12+1=13

có cần chi tiết ko bn

109/60

14/15

53/63

7/8

2/5

a, 2/5 + 2/3 + 3/4=109/60

b, 8/5 - 18/27=14/15

c, 2/7 + 5/9=53/63

d, 5/16 + 7/16 + 3/24=7/8

e, 2/3 - 4/15=2/5

a) \(\dfrac{-15+9+11}{16}=\dfrac{5}{16}\)

b) \(\dfrac{2}{3}\left(1,4+1,6-1,2\right)=\dfrac{2}{3}\times\dfrac{9}{5}=\dfrac{6}{5}\)

c) \(3\dfrac{2}{15}\left(\dfrac{3}{5}+\dfrac{2}{5}\right)-\dfrac{31}{15}=\dfrac{47}{15}-\dfrac{31}{15}=\dfrac{16}{15}\)

giúp với

D

D

D

(\(5^{16}\)+\(16^5\))(\(3^{17}\) -\(3^{10}\))(\(2^4\) -\(4^2\) )

=(\(5^{16}\) +\(16^5\))(\(3^{17}\) -\(3^{10}\))(16-16)

=(\(5^{16}\)+\(16^5\) )(\(3^{17}\) - \(3^{10}\)) .0

=0

Đề bài là tính hả bạn?

\(\dfrac{3}{5}+\dfrac{3}{16}+\dfrac{13}{16}=\dfrac{3}{5}+1=\dfrac{6}{5}\)

\(=\dfrac{3}{5}+\dfrac{16}{16}=\dfrac{3}{5}+1=\dfrac{8}{5}\)