\(\begin{array}{l}a)\dfrac{x}{6} = \dfrac{{ - 3}}{4}\\x = \dfrac{{( - 3).6}}{4}\\x = \dfrac{{ - 9}}{2}\end{array}\)

Vậy \(x = \dfrac{{ - 9}}{2}\)

\(\begin{array}{l}b)\dfrac{5}{x} = \dfrac{{15}}{{ - 20}}\\x = \dfrac{{5.( - 20)}}{{15}}\\x = \dfrac{{ - 20}}{3}\end{array}\)

Vậy \(x = \dfrac{{ - 20}}{3}\)

\(\dfrac{x}{-15}=\dfrac{-60}{x}\Rightarrow x^2=\left(-60\right)\times\left(-15\right)=900\)

Vậy x²=900=>x=30

\(\dfrac{x}{-15}=\dfrac{-60}{x}\\ x.x=-60.\left(-15\right)\\ x^2=900\\ x^2=30^2=\left(-30\right)^2\\ \Rightarrow x=\pm30\)

\(\dfrac{x}{-15}=-\dfrac{60}{x}\)

\(\Leftrightarrow x.x=-15.\left(-60\right)\)

\(\Leftrightarrow x^2=900\)

\(\Rightarrow x^2=\left(\pm30\right)^2\)

\(\Rightarrow x=30\) hoặc \(x=-30\)

Vì \(\dfrac{x}{{2,5}} = \dfrac{{10}}{{15}}\) nên x. 15 = 2,5 . 10 \( \Rightarrow 15.x = 25 \Rightarrow x = \dfrac{{25}}{{15}} = \dfrac{5}{3}\)

Vậy \(x = \dfrac{5}{3}\)

`x/(-4) = (-11)/2`

`=> 2x=-4.(-11)`

`=> 2x=44`

`=>x=44:2`

`=>x=22`

`---`

`(15-x)/(x+9) =3/5`

`=> (15-x).5=(x+9).3`

`=> 75-5x =3x+27`

`=> -5x -3x=27 -75`

`=> -8x=-48`

`=>x=-48:(-8)`

`=>x=6`

a) x−4=−112−4x​=2−11​

x=(−11).(−4)2x=2(−11).(−4)​

$x=22$.

b) 15−xx+9 =35x+915−x​ =53​

$(15-x).5=(x+9).3$

$75-5x=3x+27$

$8x=48$

$x=6$.

a)\(x=[\left(-4\right)\times\left(-11\right)]\div2=22\)

b)\(\dfrac{15-12}{\left(-4\right)+9}=\dfrac{3}{5}\)

Ta có : \(\dfrac{5}{3} = \dfrac{x}{9} \Rightarrow 5.9 = 3x \Leftrightarrow 45 = 3x \Rightarrow x = 45:3\)

\( \Rightarrow \) x = 15

Vậy x = 15

bạn ghi rõ đề câu b ra đi ạ

a)\(\dfrac{x}{27}=-\dfrac{2}{3,6}\)

\(\Rightarrow\)\(3,6x=27.(-2)\)

\(\Leftrightarrow\)\(3,6x=54\)

\(x=-15\)

a, \(\dfrac{x}{-3}\)= \(\dfrac{7}{4}\) ⇒ x = \(\dfrac{7}{4}\)x (-3) ⇒ x = - \(\dfrac{21}{4}\)

b, \(\dfrac{x+9}{15-x}\) = \(\dfrac{2}{3}\)  ⇒ 3(x+9)  = 2( 15-x) ⇒ 3x + 27 = 30 - 2x

⇒ 3x + 2x = 30 - 27 ⇒

 5x = 3 ⇒ x = 3 : 5 ⇒ x = \(\dfrac{3}{5}\)

Xãa â

a) x=7.(-3):4

x= (-21):4

x= -5.25

Bài 4 câu c) và x-y+y hay x-y+z vậy bạn

1 a) \(\dfrac{\left(-2\right)}{5}\)= \(\dfrac{-6}{15}\); \(\dfrac{15}{-6}\)= \(\dfrac{5}{-2}\); \(\dfrac{-6}{-2}\)= \(\dfrac{15}{5}\); \(\dfrac{-2}{-6}\)= \(\dfrac{5}{15}\)

1.b)bn làm tương tự như bài 1 a)

Tìm x trong tỉ lệ thức

a)