(2x - 1)4 = 2,5 + 6
Thực hiện các phép nhân hai đa thức sau:
a) 5x3 – 2x2 + 4x – 4 và x3 + 3x2 – 5
b) -2,5.x4 + 0,5x2 + 1 và 4x3 – 2x + 6
a) (5x3 – 2x2 + 4x – 4) . ( x3 + 3x2 – 5)
= 5x3 . ( x3 + 3x2 – 5) - 2x2 . ( x3 + 3x2 – 5) + 4x . ( x3 + 3x2 – 5) – 4 . ( x3 + 3x2 – 5)
= 5x3 . x3 + 5x3 . 3x2 + 5x3 . (-5) – [ 2x2 . x3 + 2x2 . 3x2 +2x2 . (-5)] + [4x . x3 + 4x. 3x2 + 4x . (-5)] – [ 4x3 + 4.3x2 + 4.(-5)]
= 5x6 + 15x5 – 25x3 – (2x5 + 6x4 – 10x2) + 4x4 + 12x3 – 20x – (4x3 + 12x2 – 20)
= 5x6 + 15x5 – 25x3 – 2x5 - 6x4 + 10x2 + 4x4 + 12x3 – 20x – 4x3 - 12x2 + 20
= 5x6 + (15x5 – 2x5 ) + (- 6x4 + 4x4 ) + (-25x3 + 12x3 – 4x3 ) + (10x2 - 12x2 ) – 20x + 20
= 5x6 + 13x5 – 2x4 – 17x3 -2x2 – 20x + 20
b) (-2,5.x4 + 0,5x2 + 1) . (4x3 – 2x + 6)
= -2,5.x4 . (4x3 – 2x + 6) + 0,5x2 . (4x3 – 2x + 6) + 1. (4x3 – 2x + 6)
= (-2,5.x4) . 4x3 + (-2,5.x4 ) . (-2x) + (-2,5.x4 ) . 6 + 0,5x2 . 4x3 + 0,5x2 . (-2x) + 0,5x2 . 6 + 4x3 – 2x + 6
= -10x7 + 5x5 – 15x4 + 2x5 – x3 + 3x2 + 4x3 – 2x + 6
= -10x7 + ( 5x5 + 2x5 ) - 15x4 + (– x3 + 4x3 ) + 3x2 – 2x + 6
= -10x7 +7x5 - 15x4 + 3x3 + 3x2 – 2x + 6
1. Tìm x
a) 2x-3/x+1=21/16
4. Tìm x trong tỷ lệ thức a) 2x:6=5:3
b) 3_1/2: (3x-2)=1/12:4/21
C) 2,5:3x=5:0,6
Bài 1: Tìm x biết
1) |5x - 3| = |7 - x|
2) 2 |3 x - 1| - 3x = 7
3) |2x + 3| + 4 = -2x
4) |x + 3/4| - 1/3 = 0
5) 1,6 - |x + 1,5| = 0
6) |x - 1,5| + |2,5 - x| = 0
1) \(|5x-3|=|7-x|\)
\(\Leftrightarrow\orbr{\begin{cases}5x-3=7-x\\5x-3=x-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}6x=10\\4x=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}}\)
Vậy...
2) \(2.|3x-1|-3x=7\)
\(\Leftrightarrow2.|3x-1|=7+3x\)
\(\Leftrightarrow\orbr{\begin{cases}2.\left(3x-1\right)=7+3x\\2.\left(3x-1\right)=-7-3x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}6x-2=7+3x\\6x-2=-7-3x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}3x=9\\9x=-5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=\frac{-5}{9}\end{cases}}\)
Vậy...
5) \(\text{1,6 - |x + 1,5| = 0}\)
\(|x + 1,5| = 1,6-0\)
\(\text{|x + 1,5| = 1,6}\)
\( |x | = 1,6-1,5\)
\(|x|=0,1\)
a) (5x-1) . ( 2x-1/3)=0
b) ( -0,6x-1/2) .3/4-(-1)=1/3
c) ( 4x-9) ( 2,5+-7/3x)=0
d) 1/4x-1+1/3.(5/2x-6)-( 3/8x +)=4,5
\(\left(5x-1\right)\left(\frac{2x-1}{3}\right)=0\)
\(\Leftrightarrow\left(\frac{\left(5x-1\right)\left(2x-1\right)}{3}\right)=0\)
\(\Leftrightarrow\left(5x-1\right)\left(2x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}5x-1=0\\2x-1=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{1}{2}\end{cases}}\)
Vậy \(x=\frac{1}{5}\)hoặc\(x=\frac{1}{2}\)
b) \(\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}-\left(-1\right)=\frac{1}{3}\)
\(\Leftrightarrow\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}=\frac{-2}{3}\)
\(\Leftrightarrow\left(-0,6x-\frac{1}{2}\right)=\frac{-8}{9}\)
\(\Leftrightarrow-0,6x=\frac{-7}{18}\)
\(\Rightarrow x=\frac{35}{54}\)
tìm x
a) x/7 = 6/21
b)2/3x -1/2=1/10
c)1/4+1/3 : x = -5
d)3x+17=2
đ)2/3x +1/4 =7/12
2x+3/10= 11/6 . 6/11
x : 4 1/3 = -2,5
a) x/7 = 6/21
x/7 = 2/7
=>x=2
b)2/3x -1/2=1/10
2/3x = 1/10+1/2
2/3x = 3/5
x=3/5:2/3
x=9/10
c)1/4+1/3 : x = -5
d)3x+17=2
đ)2/3x +1/4 =7/12
2x+3/10= 11/6 . 6/11
x : 4 1/3 = -2,5
a) x/7 = 6/21
x/7 = 2/7
=>x=2
b)2/3x -1/2=1/10
2/3x = 1/10+1/2
2/3x = 3/5
x=3/5:2/3
x=9/10
c)1/4+1/3 : x = -5
d)3x+17=2
đ)2/3x +1/4 =7/12
2x+3/10= 11/6 . 6/11
x : 4 1/3 = -2,5
tìm x , biết :
a . ( x -2,5 ) : 2 1/2 - 2,5 = -1 1/4
b . ( 2,5 x - 3,6 ) : 1 5/7 = -1
c . ( 3 3/4 - 2x ) . 1 1/3 = 2 1/9
a: \(\Leftrightarrow\left(x-\dfrac{2}{5}\right):\dfrac{3}{2}=-\dfrac{5}{4}+\dfrac{5}{2}=\dfrac{5}{4}\)
\(\Leftrightarrow x-\dfrac{2}{5}=\dfrac{5}{4}\cdot\dfrac{3}{2}=\dfrac{15}{8}\)
hay x=91/40
b: \(\Leftrightarrow\left(2.5x-3.6\right)=-1\cdot\dfrac{12}{7}=\dfrac{-12}{7}\)
=>2,5x=66/35
hay x=132/175
c: \(\Leftrightarrow\left(\dfrac{15}{4}-2x\right)=\dfrac{19}{9}:\dfrac{4}{3}=\dfrac{19}{9}\cdot\dfrac{3}{4}=\dfrac{19}{12}\)
=>2x=15/4-19/12=45/12-19/12=26/12
=>x=13/12
-4/15+2x=1,25 (2,5-x):1/4=-5/2
a: =>2x=5/4+4/15=91/60
=>x=91/120
b: =>2,5-x=-5/2*1/4=-5/8=-0,625
=>x=3,125
a) 2x+27= -11
b)3x+26= 6
c) x: 4 một phần hai=2,5
đ)3 phần 4 x=1 phần 2
a, 2x + 27 = -11
=> 2x = -11 - 27
=> 2x = -38
=> x = -38 : 2
=> x = -19
vậy___
b, 3x + 26 = 6
=> 3x = 6 - 26
=> 3x = -20
=> x = -20/3
vậy___
c, \(x\div4\frac{1}{2}=2,5\)
\(\Rightarrow x\div4,5=2,5\)
\(\Rightarrow x=4,5\cdot2,5\)
\(\Rightarrow x=11,25\)
vậy___
\(\frac{3}{4x}=\frac{1}{2}\) đk: x khác 0
\(\Rightarrow\frac{3}{4x}=\frac{3}{6}\)
=> 4x = 6
=> x = 4/6 = 2/3
vậy___
a) 2x + 27 = -11
2x = -11 - 27 =-28
=> \(x=-\frac{28}{2}=-14\)
B) 3x + 26 = 6
3x = 6 - 26 = -20
\(x=-\frac{20}{3}\)
C) ko rõ đề
D) \(\frac{3}{4x}=\frac{1}{2}\)
\(3\cdot2=4x\)
6= 4x
=> x = \(\frac{6}{4}=\frac{3}{2}\)
hok tốt .
a) 2x + 27 = -11
=> 2x = -11 - 27
=> 2x = -38
=> x = -38 : 2
=> x = -19
b) 3x + 26 = 6
=> 3x = 6 - 26
=> 3x = -20
=> x = \(\frac{-20}{3}\)
c) x : \(4\frac{1}{2}\)= 2,5
=> x : \(\frac{9}{2}\)= \(\frac{5}{2}\)
=> x = \(\frac{5}{2}.\frac{9}{2}\)
=> x = \(\frac{45}{4}\)
d) \(\frac{3}{4}x=\frac{1}{2}\)
=> x = \(\frac{1}{2}:\frac{3}{4}\)
=> x = \(\frac{1}{2}.\frac{4}{3}\)
=> x = \(\frac{2}{3}\)
Tìm X trong các tỉ lệ thức sau:
a)3,8:(2X)=1/4:8/3
b)(0,25X):3=5/6:0,125
c)0,01:2,5=(0,75X):0,75
d)4/3:0,8=2/3:(0,1X)
Giữ lời hứa nka Nguyễn Mạnh Tân!
Hứa k r lm cko! Bài dài lắm
Tìm x trong các tỉ lệ thức sau:
a, 3,8 : ( 2x ) = 1/4 : 8/3
b, ( 0,25x ) : 3 = 5/6 : 0,125
c, 0,01 : 2,5 = ( 0,75x ) : 0,75
d, 4/3 : 0,8 = 2/3 : ( 0,1x )
( 0,25x ) : 3 = 5/6 : 0,125
( 1/4x ) : 3 = 5/6 : 1/8
( 1/4x ) : 3 = 5/6 x 8
( 1/4x ) : 3 = 20/3
1/4x = 20/3 x 3
1/4x = 20
x = 20 : 1/4
x = 80
0,01 : 2,5 = ( 0,75x ) : 0,75
1/100 : 25/10 = (3/4x) : 3/4
1/100 x 10/25 = (3/4x) : 3/4
=>(3/4x) : 3/4 = 1/250
3/4x = 1/250 x 3/4
3/4x = 3/1000
x = 3/1000 : 3/4
x = 1/250
4/3 : 0,8 = 2/3 : ( 0,1x )
<=>2/3 : (0,1x) = 4/3 : 0,8
2/3 : (0,1x) = 4/3 : 4/5
2/3 : (0,1x) = 4/3 x 5/4
2/3 : (0,1x) = 5/3
2/3 : (1/10x) = 5/3
1/10x = 2/3 : 5/3
1/10x = 2/3 x 3/5
1/10x = 2/5
x = 2/5 : 1/10
x = 2/5 x 10
x = 4