1,\(\dfrac{-1}{8}+\dfrac{-5}{16}\)= ;2,\(\dfrac{-3}{8}-\dfrac{1}{-3}\);3,\(\dfrac{2}{3}×\dfrac{-5}{7}\)
mn giúp em vs ạ,cảm ơn mn rất nhìu ạ
(mn kèm lời giải hộ em ạ )
Những câu hỏi liên quan
\(\dfrac{-5}{21}+(\dfrac{-16}{21}+1)\)
\(\dfrac{-3}{8}.\dfrac{1}{6}+\dfrac{3}{-8}.\dfrac{5}{6}+\dfrac{-10}{16}\)
a)
\(\dfrac{-5}{21}+\left(\dfrac{-16}{21}+1\right)=\dfrac{-5}{21}+\dfrac{-16}{21}+1\)=\(-1+1=0\)
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`(-5)/21+((-16)/21+1)`
`=(-5)/21-16/21+1`
`=-1+1=0`
`(-3)/8*1/6+3/(-8)*5/6+(-1)/16`
`=-3/8*(1/6+5/6)-10/16`
`=-3/8-10/16`
`=-6/16-10/16=-16/16=-1`
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\(\dfrac{-3}{8}.\dfrac{1}{6}+\dfrac{-3}{8}.\dfrac{5}{6}+\dfrac{-10}{16}\)
=\(\dfrac{-3}{8}.\left(\dfrac{1}{6}+\dfrac{5}{6}\right)+\dfrac{-10}{16}\)
=\(\dfrac{-3}{8}+\dfrac{-5}{8}=-1\)=
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SGK Kết nối tri thức với cuộc sống - Trang 84
24 tháng 8 2023 lúc 1:07
Đ, S?a) dfrac{1}{2}-dfrac{1}{8}dfrac{3}{8} b) dfrac{7}{10}-dfrac{1}{5}dfrac{6}{5} c) dfrac{5}{4}+dfrac{5}{12}dfrac{5}{16} d) dfrac{3}{6}+dfrac{2}{3}dfrac{7}{6}
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Đ, S?
a) \(\dfrac{1}{2}-\dfrac{1}{8}=\dfrac{3}{8}\) 
b) \(\dfrac{7}{10}-\dfrac{1}{5}=\dfrac{6}{5}\) 
c) \(\dfrac{5}{4}+\dfrac{5}{12}=\dfrac{5}{16}\) 
d) \(\dfrac{3}{6}+\dfrac{2}{3}=\dfrac{7}{6}\) 
a) Đ
b) S
\(\dfrac{7}{10}-\dfrac{1}{5} \\ =\dfrac{7}{10}-\dfrac{2}{10}\\ =\dfrac{5}{10}=\dfrac{1}{2}\)
c) S
\(\dfrac{5}{4}+\dfrac{5}{12}\\ =\dfrac{15}{12}+\dfrac{5}{12}\\ =\dfrac{20}{12}=\dfrac{5}{3}\)
d) Đ
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SGK Chân trời sáng tạo - Tập 2 - Trang 54
28 tháng 10 2023 lúc 22:58
Tính:dfrac{1}{3}+dfrac{2}{9} dfrac{1}{2}+dfrac{3}{8} dfrac{5}{12}+dfrac{2}{3}dfrac{5}{16}+dfrac{3}{8} dfrac{4}{15}+dfrac{3}{5} dfrac{8}{63}+dfrac{7}{10}
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Tính:
\(\dfrac{1}{3}+\dfrac{2}{9}\) \(\dfrac{1}{2}+\dfrac{3}{8}\) \(\dfrac{5}{12}+\dfrac{2}{3}\)
\(\dfrac{5}{16}+\dfrac{3}{8}\) \(\dfrac{4}{15}+\dfrac{3}{5}\) \(\dfrac{8}{63}+\dfrac{7}{10}\)
\(\dfrac{1}{3}+\dfrac{2}{9}=\dfrac{3}{3\times3}+\dfrac{2}{9}=\dfrac{3}{9}+\dfrac{2}{9}=\dfrac{5}{9}\)
\(\dfrac{1}{2}+\dfrac{3}{8}=\dfrac{4}{2\times4}+\dfrac{3}{8}=\dfrac{4}{8}+\dfrac{3}{8}=\dfrac{7}{8}\)
\(\dfrac{5}{12}+\dfrac{2}{3}=\dfrac{5}{12}+\dfrac{2\times4}{3\times4}=\dfrac{5}{12}+\dfrac{8}{12}=\dfrac{13}{12}\)
\(\dfrac{5}{16}+\dfrac{3}{8}=\dfrac{5}{16}+\dfrac{3\times2}{8\times2}=\dfrac{5}{16}+\dfrac{6}{16}=\dfrac{11}{16}\)
\(\dfrac{4}{15}+\dfrac{3}{5}=\dfrac{4}{15}+\dfrac{3\times3}{5\times3}=\dfrac{4}{15}+\dfrac{9}{15}=\dfrac{13}{15}\)
\(\dfrac{8}{63}+\dfrac{7}{10}=\dfrac{8\times10}{63\times10}+\dfrac{7\times63}{10\times63}=\dfrac{80}{630}+\dfrac{441}{630}=\dfrac{521}{630}\)
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4 tháng 3 2022 lúc 8:17
Tính:a) dfrac{-7}{8} . dfrac{3}{5} - dfrac{2}{5} . dfrac{7}{8} + 3dfrac{7}{8}b) -1,6 : ( 1 + dfrac{2}{3} )c) dfrac{6}{7} + dfrac{5}{8} : 5 - dfrac{3}{16} . ( -2 )^2d) dfrac{1^2}{1.2} . dfrac{2^2}{2.3} . dfrac{3^2}{3.4} . dfrac{4^2}{4.5}
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Tính:
a) \(\dfrac{-7}{8}\) . \(\dfrac{3}{5}\) - \(\dfrac{2}{5}\) . \(\dfrac{7}{8}\) + \(3\dfrac{7}{8}\)
b) -1,6 : ( 1 + \(\dfrac{2}{3}\) )
c) \(\dfrac{6}{7}\) + \(\dfrac{5}{8}\) : 5 - \(\dfrac{3}{16}\) . ( -2 )\(^2\)
d) \(\dfrac{1^2}{1.2}\) . \(\dfrac{2^2}{2.3}\) . \(\dfrac{3^2}{3.4}\) . \(\dfrac{4^2}{4.5}\)
a: \(=\dfrac{-7}{8}\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+3+\dfrac{7}{8}=\dfrac{-7}{8}+\dfrac{7}{8}+3=3\)
b: \(=-\dfrac{8}{5}:\dfrac{5}{3}=-\dfrac{24}{25}\)
c: \(=\dfrac{6}{7}+\dfrac{1}{8}-\dfrac{3}{4}=\dfrac{6}{7}+\dfrac{1}{8}-\dfrac{6}{8}=\dfrac{6}{7}-\dfrac{5}{8}=\dfrac{48}{56}-\dfrac{35}{56}=\dfrac{13}{56}\)
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Bài 1: Thực hiện phép tính:
a, left(dfrac{7}{20}+dfrac{11}{15}-dfrac{15}{12}right):left(dfrac{11}{20}-dfrac{26}{45}right)
b, dfrac{5-dfrac{5}{3}+dfrac{5}{9}-dfrac{5}{27}}{8-dfrac{8}{3}+dfrac{8}{9}-dfrac{8}{27}}:dfrac{15-dfrac{15}{11}+dfrac{15}{121}}{16-dfrac{16}{11}+dfrac{16}{121}}
c, dfrac{dfrac{1}{9}-dfrac{5}{6}-4}{dfrac{7}{12}-dfrac{1}{36}-10}
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Bài 1: Thực hiện phép tính:
a, \(\left(\dfrac{7}{20}+\dfrac{11}{15}-\dfrac{15}{12}\right):\left(\dfrac{11}{20}-\dfrac{26}{45}\right)\)
b, \(\dfrac{5-\dfrac{5}{3}+\dfrac{5}{9}-\dfrac{5}{27}}{8-\dfrac{8}{3}+\dfrac{8}{9}-\dfrac{8}{27}}:\dfrac{15-\dfrac{15}{11}+\dfrac{15}{121}}{16-\dfrac{16}{11}+\dfrac{16}{121}}\)
c, \(\dfrac{\dfrac{1}{9}-\dfrac{5}{6}-4}{\dfrac{7}{12}-\dfrac{1}{36}-10}\)
\(a,\left(\dfrac{7}{20}+\dfrac{11}{15}-\dfrac{15}{12}\right):\left(\dfrac{11}{20}-\dfrac{26}{45}\right).\)
\(=\left(\dfrac{21}{60}+\dfrac{44}{60}-\dfrac{75}{60}\right):\left(\dfrac{99}{180}-\dfrac{104}{180}\right).\)
\(=\left(\dfrac{65}{60}-\dfrac{75}{60}\right):\left(-\dfrac{5}{180}\right).\)
\(=-\dfrac{10}{60}:\left(-\dfrac{5}{180}\right).\)
\(=-\dfrac{1}{6}:\left(-\dfrac{1}{36}\right).\)
\(=-\dfrac{1}{6}.\left(-36\right).\)
\(=\dfrac{-1.\left(-36\right)}{6}=\dfrac{36}{6}=6.\)
Vậy......
\(b,\dfrac{5-\dfrac{5}{3}+\dfrac{5}{9}-\dfrac{5}{27}}{8-\dfrac{8}{3}+\dfrac{8}{9}-\dfrac{8}{27}}:\dfrac{15-\dfrac{15}{11}+\dfrac{15}{121}}{16-\dfrac{16}{11}+\dfrac{16}{121}}.\)
\(=\dfrac{5\left(1-\dfrac{1}{3}+\dfrac{1}{9}-\dfrac{1}{27}\right)}{8\left(1-\dfrac{1}{3}+\dfrac{1}{9}-\dfrac{1}{27}\right)}:\dfrac{15\left(1-\dfrac{1}{11}+\dfrac{1}{121}\right)}{16\left(1-\dfrac{1}{11}+\dfrac{1}{121}\right)}.\)
\(=\dfrac{5}{8}:\dfrac{15}{16}.\)
\(=\dfrac{5}{8}.\dfrac{16}{15}=\dfrac{5.16}{8.15}=\dfrac{1.2}{1.3}=\dfrac{2}{3}.\)
Vậy......
c, (làm tương tự câu b).
~ Học tốt!!! ~
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24 tháng 7 2023 lúc 9:59
\(\dfrac{15}{16}\div\dfrac{5}{8}\times\dfrac{3}{4}\)
\(\dfrac{21}{4}\times\dfrac{16}{14}\times\dfrac{1}{2}\times\dfrac{8}{3}\)
\(\dfrac{15}{16}:\dfrac{5}{8}\times\dfrac{3}{4}\)
\(=\dfrac{15}{16}\times\dfrac{8}{5}\times\dfrac{3}{4}\)
\(=\dfrac{3}{2}\times\dfrac{3}{4}\)
\(=\dfrac{9}{8}\)
_________________
\(\dfrac{21}{4}\times\dfrac{16}{14}\times\dfrac{1}{2}\times\dfrac{8}{3}\)
\(=6\times\dfrac{4}{3}\)
\(=8\)
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Tính một cách hợp lý:
aleft(dfrac{1}{2}-1right)left(dfrac{1}{3}-1right)...left(dfrac{1}{100}-1right)) x:dfrac{99}{100}:dfrac{98}{99}:...:dfrac{2}{3}:dfrac{1}{2}
b) dfrac{5-dfrac{5}{3}+dfrac{5}{9}-dfrac{5}{27}}{8-dfrac{8}{3}+dfrac{8}{9}-dfrac{8}{27}}:dfrac{15-dfrac{15}{11}+dfrac{15}{121}}{16-dfrac{16}{11}+dfrac{16}{121}}
c) dfrac{dfrac{1}{9}-dfrac{5}{6}-4}{dfrac{7}{12}-dfrac{1}{36}-10}
d) left(dfrac{1}{2}+1right)left(dfrac{1}{3}+1right)...left(dfrac{1}{99}+1right)
e)
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Tính một cách hợp lý:
a\(\left(\dfrac{1}{2}-1\right)\left(\dfrac{1}{3}-1\right)...\left(\dfrac{1}{100}-1\right)\)) \(x:\dfrac{99}{100}:\dfrac{98}{99}:...:\dfrac{2}{3}:\dfrac{1}{2}\)
b) \(\dfrac{5-\dfrac{5}{3}+\dfrac{5}{9}-\dfrac{5}{27}}{8-\dfrac{8}{3}+\dfrac{8}{9}-\dfrac{8}{27}}:\dfrac{15-\dfrac{15}{11}+\dfrac{15}{121}}{16-\dfrac{16}{11}+\dfrac{16}{121}}\)
c) \(\dfrac{\dfrac{1}{9}-\dfrac{5}{6}-4}{\dfrac{7}{12}-\dfrac{1}{36}-10}\)
d) \(\left(\dfrac{1}{2}+1\right)\left(\dfrac{1}{3}+1\right)...\left(\dfrac{1}{99}+1\right)\)
e)
b) \(\dfrac{5-\dfrac{5}{3}+\dfrac{5}{9}-\dfrac{5}{27}}{8-\dfrac{8}{3}+\dfrac{8}{9}-\dfrac{8}{27}}=\dfrac{5\left(1-\dfrac{1}{3}+\dfrac{1}{9}-\dfrac{1}{27}\right)}{8\left(1-\dfrac{1}{3}+\dfrac{1}{9}-\dfrac{1}{27}\right)}=\dfrac{5}{8}\)
Vì không có thời gian nên mình chỉ làm câu khó nhất thôi, tick mình nhé
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Điền dấu > ; < hoặc = vào chỗ chấm cho thích hợp:
a) \(\dfrac{3}{4}.....\dfrac{4}{5}\) b) \(\dfrac{11}{12}.....\dfrac{7}{8}\) c) \(\dfrac{5}{7}+\dfrac{3}{5}.....\dfrac{6}{7}:\dfrac{5}{8}\) d) \(\dfrac{9}{16}-\dfrac{5}{9}.....\dfrac{1}{16}x\dfrac{1}{9}\)
a, \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}\) b, \(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{5}\)
\(a,\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}=\dfrac{8}{16}+\dfrac{4}{16}+\dfrac{2}{16}+\dfrac{1}{16}=\dfrac{8+4+2+1}{16}=\dfrac{15}{16}\)
\(b,\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{5}=\dfrac{15}{30}+\dfrac{10}{30}+\dfrac{6}{30}=\dfrac{15+10+6}{30}=\dfrac{31}{30}\)
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bài 3 thực hiện phép tínhadfrac{5}{8}+dfrac{3}{17}+dfrac{4}{18}+dfrac{20}{-17}+dfrac{-2}{9}+dfrac{21}{56}bleft(dfrac{9}{16}+dfrac{8}{-27}right)+left(1+dfrac{7}{16}+dfrac{-19}{27}right)cleft(dfrac{13}{5}+dfrac{7}{16}right)+left(dfrac{-15}{16}+dfrac{6}{15}right) d left(6-2dfrac{4}{5}right).3dfrac{1}{8}-1dfrac{3}{5}:dfrac{1}{4}
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bài 3 thực hiện phép tính
a\(\dfrac{5}{8}+\dfrac{3}{17}+\dfrac{4}{18}+\dfrac{20}{-17}+\dfrac{-2}{9}+\dfrac{21}{56}\)
b\(\left(\dfrac{9}{16}+\dfrac{8}{-27}\right)+\left(1+\dfrac{7}{16}+\dfrac{-19}{27}\right)\)
c\(\left(\dfrac{13}{5}+\dfrac{7}{16}\right)+\left(\dfrac{-15}{16}+\dfrac{6}{15}\right)\) d \(\left(6-2\dfrac{4}{5}\right).3\dfrac{1}{8}-1\dfrac{3}{5}:\dfrac{1}{4}\)
a) Ta có: \(\dfrac{5}{8}+\dfrac{3}{17}+\dfrac{4}{18}+\dfrac{20}{-17}+\dfrac{-2}{9}+\dfrac{21}{56}\)
\(=\left(\dfrac{3}{17}-\dfrac{20}{17}\right)+\left(\dfrac{2}{9}-\dfrac{2}{9}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)\)
\(=-1+1=0\)
b) Ta có: \(\left(\dfrac{9}{16}+\dfrac{8}{-27}\right)+\left(1+\dfrac{7}{16}+\dfrac{-19}{27}\right)\)
\(=\left(\dfrac{9}{16}+\dfrac{7}{16}\right)+\left(\dfrac{-8}{27}-\dfrac{19}{27}\right)+1\)
=1-1+1=1
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