\(2^{x-1}+2^x=48\)
\(\Rightarrow2^x\cdot\dfrac{1}{2}+2^x=48\)
\(\Rightarrow2^x\left(\dfrac{1}{2}+1\right)=48\)
\(\Rightarrow2^x\cdot\dfrac{3}{2}=48\)
\(\Rightarrow2^x=32\)
\(\Rightarrow x=5\)
Vậy x = 5 
#gboy2mai

\(2^{2x}+2^{2x+1}=48\)

\(2^{2x}+2^{2x}.2=48\)

\(2^{2x}.\left(1+2\right)=48\)

\(2^{2x}.3=48\)

\(2^{2x}=48:3\)

\(2^{2x}=16\)

\(2^{2x}=2^4\)

\(\Rightarrow2x=4\)

\(x=4:2\)

\(x=2\)

\(2^{2x}+2^{2x+1}=48\\ \Rightarrow2^{2x}+2.2^{2x}=48\\ \Rightarrow\left(1+2\right).2^{2x}=48\\ \Leftrightarrow3.2^{2x}=48\\ \Leftrightarrow2^{2x}=16\\ \Leftrightarrow2^{2x}=2^4\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=2\)

Vậy x = 2

x = 2 

(2x² + 1)(x-3)=0

\(\Rightarrow\orbr{\begin{cases}2x^2+1=0\\x-3=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}2x^2=-1\Rightarrow x^2=-\frac{1}{2}\left(vl\right)\\x=3\end{cases}}\)

Vậy x=3

48-(15-x)⁵=48

     (15-x)⁵=48-48

     (15-x)⁵=0

=>  15-x   =0

           x    =15-0

           x    =15

Vậy x=15

a: Ta có: \(x\left(2-x\right)+\left(x^2+x\right)=7\)

\(\Leftrightarrow2x-x^2+x^2+x=7\)

\(\Leftrightarrow3x=7\)

hay \(x=\dfrac{7}{3}\)

b: Ta có: \(\left(2x+1\right)^2-x\left(4-5x\right)=17\)

\(\Leftrightarrow4x^2+4x+1-4x+5x^2=17\)

\(\Leftrightarrow9x^2=16\)

\(\Leftrightarrow x^2=\dfrac{16}{9}\)

hay \(x\in\left\{\dfrac{4}{3};-\dfrac{4}{3}\right\}\)

c: Ta có: \(\left(x-4\right)^2-\left(2x+1\right)^2=0\)

\(\Leftrightarrow\left(x-4-2x-1\right)\left(x-4+2x+1\right)=0\)

\(\Leftrightarrow\left(x+5\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=1\end{matrix}\right.\)

d: ta có: \(\dfrac{2x^3-8x^2+10x}{2x}=0\)

\(\Leftrightarrow x^2-4x+5=0\)

\(\Leftrightarrow\left(x-2\right)^2+1=0\)(vô lý)

=>(2x-1)^2=24^2

=>2x-1=24 hoặc 2x-1=-24

=>x=-23/2 hoặc x=25/2

\(\dfrac{2x-1}{-12}=\dfrac{48}{1-2x}\) (ĐK: \(x\ne\dfrac{1}{2}\))

\(\Leftrightarrow\dfrac{2x-1}{12}=\dfrac{48}{2x-1}\)

\(\Leftrightarrow-12\cdot48=\left(2x-1\right)\left(2x-1\right)\)

\(\Leftrightarrow567=\left(2x-1\right)^2\)

\(\Leftrightarrow24^2=\left(2x-1\right)^2\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=-24\\2x-1=24\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x=-23\\2x=25\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{23}{2}\left(tm\right)\\x=\dfrac{25}{2}\left(tm\right)\end{matrix}\right.\)

\(\Leftrightarrow\dfrac{2}{2.4}+\dfrac{2}{4.6}+...+\dfrac{2}{\left(2x-2\right).2x}=\dfrac{11}{24}\)

\(\Leftrightarrow\dfrac{4-2}{2.4}+\dfrac{6-4}{4.6}+...+\dfrac{2x-\left(2x-2\right)}{\left(2x-2\right).2x}=\dfrac{11}{24}\)

\(\Leftrightarrow\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+...+\dfrac{1}{2x-2}-\dfrac{1}{2x}=\dfrac{11}{24}\)

\(\Leftrightarrow\dfrac{1}{2}-\dfrac{1}{2x}=\dfrac{11}{24}\)

\(\Leftrightarrow\dfrac{1}{2x}=\dfrac{1}{2}-\dfrac{11}{24}\)

\(\Leftrightarrow\dfrac{1}{2x}=\dfrac{1}{24}\)

\(\Rightarrow2x=24\)

\(\Rightarrow x=12\)

\(2^{x+1}-1=63\\ 2^{x+1}=64\\ 2^{x+1}=2^6\\ =>X+1=6\\ =>x=5\)

\(\left(X-3\right)\cdot4^5=4^8\\ X-3=64\\ =>X=67\)

740:(x+10)=10²-2.13