⇒ ( 4x + 28 ) . 3 + 55  = 35 . 5

 ⇒ ( 4x + 28 ) . 3 + 55 = 175

  ⇒ ( 4x + 28 ) . 3 = 175 - 55

  ⇒ ( 4x + 28 ) .3 = 120

   ⇒  4x + 28 = 120 : 3

    ⇒ 4x + 28 = 40

   ⇒  4x = 40 -  28

    ⇒ 4x = 12

     ⇒ x = 12: 4

⇔ x = 3.

Vậy x= 3.

\(\left[\left(4x+28\right)\times3+55\right]\div5=35\)

\(\left(4x+28\right)\times3+55=175\)

\(12x+84+55=175\)

\(12x=175-55-84\)

\(12x=36\)

\(x=3\)

`@` `\text {Ans}`

`\downarrow`

`b)`

\([(4x+28).3+55] \div 5=35\)

`=> (4x + 28) * 3 + 55 = 35 * 5`

`=> (4x + 28)*3 + 55 = 175`

`=> (4x + 28)*3 = 175 - 55`

`=> (4x + 28)*3 =120`

`=> 4x + 28 = 120 \div 3`

`=> 4x + 28 = 40`

`=> 4x = 40 - 28`

`=> 4x = 12`

`=> x = 12 \div 4`

`=>x = 3`

Vậy, `x = 3.`

=>[12x+84+55]=175

=>12x=175-84-55=120-84=36

=>x=36/12=3

<=>[12x+84+55]:5=35

<=>[12x+139]:5=35

<=>12x+139=35.5

<=>12x=175-139

<=>x=3

kết quả là-11

x=3 nha ban :))))))))))

t i c k nha

mik tính đc 11 bn nha 

[(4x + 28).3 + 55] : 5 = 35

=> (4x + 28).3 + 55 = 175

=> (4x + 28).3 = 120

=> 4x + 28 = 40

=> 4x = 12

=> x = 3

vậy_

[(4x+28).3+55]:5=35

[(4x+28).3+55]=35.5

[(4x+28).3+55]=175

(4x+28).3=175-55

(4x+28).3=120

4x+28=120:3

4x+28=40

4x=40-28

4x=12

x=12:4

x=3

k cho mik nhoa bn nha!

[ ( 4x + 28 ) . 3 + 55 ] :5 = 35

   ( 4x + 28 ) . 3 + 55       = 175

   ( 4x + 28 ) . 3               = 120

   ( 4x + 28 )                    = 40

      4x                             = 12

        x                              = 3

cảm ơn các bạn giờ thì mình đã biết mình sai ở chỗ nào rồi cảm ơn

a) \(128-3\left(x+4\right)=23\)

\(\Rightarrow3\left(x+4\right)=128-23\)

\(\Rightarrow3\left(x+4\right)=105\)

\(\Rightarrow x+4=35\)

\(\Rightarrow x=35-4\)

\(\Rightarrow x=31\)

b) \(\left[\left(4x+28\right)\cdot3+55\right]:5=35\)

\(\Rightarrow\left(4x+28\right)\cdot3+55=35\cdot5\)

\(\Rightarrow\left(4x+28\right)\cdot3+55=175\)

\(\Rightarrow\left(4x+28\right)\cdot3=120\)

\(\Rightarrow4x+28=40\)

\(\Rightarrow4x=12\)

\(\Rightarrow x=3\)

a, \(128-3\left(x+4\right)=23\)

\(=>3\left(x+4\right)=128-23\)

\(=>3\left(x+4\right)=105\)

\(=>x+4=105:3\)

\(=>x+4=35\)

\(=>x=35-4\)

\(=>x=31\)

b, \(\left[\left(4x+28\right).3+55\right]:5=35\)

\(=>\left(4x+28\right).3+55=35.5\)

\(=>\left(4x+28\right).3+55=175\)

\(=>\left(4x+28\right).3=175-55\)

\(=>\left(4x+28\right).3=120\)

\(=>4x+28=120:3\)

\(=>4x+28=40\)

\(=>4x=40-28\)

\(=>4x=12\)

\(=>x=12:4\)

\(=>x=3\)

\(#WendyDang\)

a) 128 - 3 (x + 4) =23

      3.( x + 4) = 128 -23

      3. ( x + 4) =  105

      x + 4 = 105 :3

      x + 4 =  35

      x = 35 -4

     x = 31

\(\left[\left(4x+28\right).3+55\right]:5=35\)

\(\Rightarrow\left(4x+28\right).3+55=35.5\)

\(\Rightarrow\left(4x+28\right).3+55=175\)

\(\Rightarrow\left(4x+28\right).3=175-55\)

\(\Rightarrow\left(4x+28\right).3=120\)

\(\Rightarrow4x+28=120:3\)

\(\Rightarrow4x+28=40\)

\(\Rightarrow4x=40-28\)

\(\Rightarrow4x=12\)

\(\Rightarrow x=12:4\)

\(\Rightarrow x=3\)

[ ( 4x + 28 ). 3 + 55 ] ÷ 5 = 35

( 4x + 28 ). 3 + 55 = 35.5

( 4x + 28 ). 3 + 55 = 175

( 4x + 28 ). 3 = 175 - 55

( 4x + 28 ). 3 = 120

4x + 28 = 120 : 3

4x + 28 = 40

4x = 40 - 28

4x = 12

x = 12 : 4

x = 3

\(a,128-3.\left(x+4\right)=23\\ \Rightarrow3.\left(x+4\right)=105\\ \Rightarrow x+4=35\\ \Rightarrow x=31\\ b,\left[\left(4x+28\right).3+55\right]:5=35\\ \Rightarrow\left(4x+28\right).3+55=175\\ \Rightarrow4x+28.3=120\\ \Rightarrow4x+28=60\\ \Rightarrow4x=32\\ \Rightarrow x=8.\)

c) \(\left(12x-4^3\right).8^3=4.8^4\)

\(12x-64=4.8^4:8^3\)

\(12x-64=32\)

\(12x=32+64\)

\(12x=96\)

\(x=\dfrac{96}{12}\)

\(x=8\)

d) \(720:\left[41-\left(2x-5\right)\right]:5=35\)

\(720:\left(41-2x+5\right):5=35\)

\(720:\left(46-2x\right)=35.5\)

\(720:\left(46-2x\right)=175\)

\(46-2x=720:175\)

\(46-2x=\dfrac{144}{35}\)

\(2x=46-\dfrac{144}{35}\)

\(2x=\dfrac{1466}{35}\)

\(x=\dfrac{1466}{35}:2\)

\(x=\dfrac{733}{35}\)

lm nốt hộ mik 2 ý cuối vs ạ

a, 128 – 3(x+4) = 23

b,  12 x - 4 3 . 8 3 = 4 . 8 4

c, [(4x+28).3+55]:5 = 35

d, 720:[41 – (2x – 5)] =  2 3 . 5