Tính bằng cách thuận tiện nhất
1 + 2/3 x 1/2 +2/3 x 5/2 - 2/3 x 3/2
Tính bằng cách thuận tiện nhất
1/2 x 2/3 : 5/6 x 5/6
\(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{6}{5}\cdot\dfrac{5}{6}=\dfrac{1}{2}\cdot\dfrac{2}{3}=\dfrac{1}{3}\)
\(\dfrac{1}{2}\times\dfrac{2}{3}:\dfrac{5}{6}\times\dfrac{5}{6}\)
\(=\dfrac{1}{2}\times\left(\dfrac{2}{3}:\dfrac{5}{6}\times\dfrac{5}{6}\right)\)
\(=\dfrac{1}{2}\times\dfrac{2}{3}\)
\(=\dfrac{1}{3}\)
tính bằng cách thuận tiện nhất
1/2 + 1/3 +1/4 +1/5 +4/5 +3/4 + 2/3 + 1/2
1/2 + 1/3 + 1/4 + 1/5 + 4/5 + 3/4 + 2/3 + 1/2
= (1/2 + 1/2) + (1/3 + 2/3) + (1/4 + 3/4) + (1/5 + 4/5)
= 1 + 1 + 1 + 1
= 4
tính bằng cách thuận tiện nhất
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 =
=
=
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1+2+3+4+5+6+7+8+9 = ( 1+9) + ( 2+8) + (3+7) + (4+6) +5
= 10 + 10 + 10 + 10 + 5
= 45
(1+9)+(2+8)+(3+7)+(4+6)+5
=10 + 10 + 10 + 10
=40
tính bằng cách thuận tiện nhất
5/12 x 2/3 + 2/3 x 7/12 +1/3
2/3*(5/12+7/12) +1/3 = 2/3*12/12+1/3
= 2/3+1/3= 1
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Tính bằng cách thuận tiện:
a) 2/3 x 4/9 + 2/3 x 5/9
b, 7/5 x 3/4 - 1/2 x 3/4
c, ( 5/6 + 5/8 ) x 2/3
a.\(\dfrac{2}{3}\times\dfrac{4}{9}+\dfrac{2}{3}\times\dfrac{5}{9}=\dfrac{2}{3}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{2}{3}\times1=\dfrac{2}{3}\)
b.\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{3}{4}\times\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{3}{4}\times\dfrac{9}{10}=\dfrac{27}{40}\)
c.\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
a) 2/3 x 4/9 + 2/3 x 5/9
=2/3 x ( 4/9 + 5/9)
= 2/3 x 1
= 2/3
b, 7/5 x 3/4 - 1/2 x 3/4
= ( 7/5 - 1/2 ) x 3/4
= 9/10 x 3/4
= 21/40
c, ( 5/6 + 5/8 ) x 2/3
= 35/24 x 2/3
= 35/36
a) \(\dfrac{2}{3}\times\dfrac{4}{9}+\dfrac{2}{3}\times\dfrac{5}{9}=\dfrac{2}{3}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{2}{3}\times1=\dfrac{2}{3}\)
b) \(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\left(\dfrac{7}{5}-\dfrac{1}{2}\right)\times\dfrac{3}{4}=\dfrac{9}{10}\times\dfrac{3}{4}=\dfrac{27}{40}\)
c) \(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\left(\dfrac{20}{24}+\dfrac{15}{24}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
Bài 4. (1 điểm). Tính bằng cách thuận tiện nhất.
17/2 x 3/5 + 3/5 x 1/2 + 3/5
TÍNH BẰNG CÁCH THUẬN TIỆN:
2/3 X 2/8 + 2/3 : 8 + 2/3 X 5/8
`2/3 xx 2/8 +2/3 : 8 +2/3 xx 5/8`
`=2/3 xx 2/8 +2/3 xx 1/8 +2/3 xx 5/8`
`=2/3 xx (2/8+1/8+5/8)`
`=2/3 xx 8/8`
`=2/3 xx 1`
`=2/3`
Tính bằng cách thuận tiện nhất :
A=2/1 x 3+2/3 x 5+2/5 x 7+2/7 x 9
A=\(\frac{2}{1}\cdot3+\frac{2}{3}\cdot5+\frac{2}{5}\cdot7+\frac{2}{7}\cdot9\)
A=\(\frac{3}{1}\cdot2+\frac{5}{3}\cdot2+\frac{7}{5}\cdot2+\frac{9}{7}\cdot2\)
A=\(2\cdot\left(3+\frac{5}{3}+\frac{7}{5}+\frac{9}{7}\right)\)
A=\(2\cdot\frac{772}{105}\)
A=\(\frac{1544}{105}\)
A=\(14\frac{74}{105}\)
Tính bằng cách thuận tiện nhất:
17/2 x 3/5 + 3/5 x 1/2 + 3/5
= 17/2 x 3/5 + 3/5 x 1/2 + 3/5 x 1
= 3/5 x ( 17/2 + 1/2 + 1 )
= 3/5 x 10
= 30/5
= 1/6
\(\frac{17}{2}\cdot\frac{3}{5}+\frac{3}{5}\cdot\frac{1}{2}+\frac{3}{5}\)
\(=\left(\frac{17}{2}+\frac{1}{2}+1\right)\cdot\frac{3}{5}\)
\(=\left(\frac{17}{2}+\frac{1}{2}+\frac{2}{2}\right)\cdot\frac{3}{5}\)
\(=10\cdot\frac{3}{5}=6\)
\(\frac{17}{2}\)x \(\frac{3}{5}\)+ \(\frac{3}{5}\)x \(\frac{1}{2}\)+ \(\frac{3}{5}\)= \(\frac{17}{5}\)+ \(\frac{3}{10}\)+ \(\frac{3}{5}\)
= \(\frac{37}{10}\)+ \(\frac{3}{5}\)
= \(\frac{43}{10}\)