\(5x^2-10xy+5y^2-20z^2\)

\(=5\left(x^2-2xy+y^2-4z^2\right)\)

\(=5\left[\left(x-y\right)^2-4z^2\right]\)

\(=5\left(x-y-2z\right)\left(x-y+2z\right)\)

5x²-10xy+5y²-20z²

=5(x²-2xy+y²-4z²)

=5[(x²-2xy+y²)-(2z)²]

=5[(x-y)²-(2z)²]

=5[(x-y-2z)(x-y+2z)]

chúc bn hc tốt

Ta có: \(5x^2-10xy+5y^2-20z^2\)

\(=5\cdot\left(x^2-2xy+y^2-4z^2\right)\)

\(=5\cdot\left[\left(x^2-2xy+y^2\right)-\left(2z\right)^2\right]\)

\(=5\cdot\left[\left(x-y\right)^2-\left(2z\right)^2\right]\)

\(=5\cdot\left(x-y-2z\right)\left(x-y+2z\right)\)

\(=x^2+x-6x+6\\ =x\left(x+1\right)-6\left(x+1\right)\\ =\left(x+1\right)\left(x+6\right)\)

5𝑥\(^2\)−17𝑥+6

=5𝑥\(^2\)−2𝑥−15𝑥+6

=𝑥(5𝑥−2)−3(5𝑥−2)

=(𝑥−3)(5𝑥−2)

#Fiona

Chúc bạn học tốt ! 

\(4x^2-5x-6=4x^2-8x+3x-6\)

\(=4x\left(x-2\right)+3\left(x-2\right)\)

\(=\left(x-2\right)\left(4x+3\right)\)

Lời giải:

$2x^2-5x-6=2(x^2-\frac{5}{2}x+\frac{5^2}{4^2})-\frac{73}{8}$

$=2(x-\frac{5}{4})^2-\frac{73}{8}$

$=2(x-\frac{5}{4}-\frac{\sqrt{73}}{4})(x-\frac{5}{4}+\frac{\sqrt{73}}{4})$

e ko bt phân tích đa thức thành nhân tử nên a tham khảo linh này nha

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=&cad=rja&uact=8&ved=2ahUKEwim29i-oIzyAhVSNKYKHZBdCJ4QFjAAegQIBRAD&url=https%3A%2F%2Fh7.net%2Fhoi-dap%2Ftoan-8%2Fphan-h-da-thuc-5x-2-2x-2-2x-5x-2-6-thanh-nhan-tu-faq341450.html&usg=AOvVaw2Kkix8idzI43uM1i2Mitp4

TL:

(5x^2 - 2x)^2+2x-5x^2-6 

=(\(5x^2\)-2x+3)(\(5x^2\)-2x+2)

các bạn làm giúp mik , mik cần gấp . Làm đc mik chọn cho .

=(x-6)(x+1)

x² + 5x - 6 = (x² + 6x) - (x + 6) = x(x + 6) - (x + 6)

= (x + 6)(x - 1)

x² + 5x - 6

= (x² + 6x) - (x + 6)

= x(x + 6) - (x + 6)

= (x + 6)(x - 1)

x² - 5x + 6 

= x² - 2x - 3x + 6

= ( x² - 2x ) - ( 3x - 6 )

= x( x - 2 ) - 3( x - 2 )

= ( x - 3 )( x - 2 )

Tìm x biết:

(x+1)^2 + 2x (x-2) = 3 (x+4) (x+1)

\(x^2-5x+6\)

\(=x^2+x-6x+6\)

\(=x.\left(x-1\right)-6.\left(x-1\right)\)

\(=\left(x-6\right).\left(x-1\right)\)