(2x - 7) + 17 = 6

=> 2x - 7 = 6 - 17

=> 2x - 7 = -11

=> 2x = -11 + 7

=> 2x = -4

=> x = -4 : 2

=> x = -2

+) 12 -2(3 - 3x)= -2

=> 2(3 - 3x) = 12 + 2

=> 2(3 - 3x) = 14

=> 3 - 3x = 14 : 2

=> 3 - 3x = 7

=> 3x = 3 - 7

=> 3x = -4

=> x = -4/3

\(\left(x+1\right)\left(x-3\right)=0\)

=> \(\orbr{\begin{cases}x+1=0\\x-3=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=-1\\x=3\end{cases}}\)

Vậy...

\(\left(2x-7\right)+17=6\)

\(\left(2x-7\right)=6-17\)

\(2x-7=-11\)

\(2x=-11+7\)

\(2x=-4\)

\(x=-4:2\)

\(\Rightarrow x=-2\)

\(V\text{ậy x = -2}\)

1. 3y = 0

=> y = 0

2. 1+x = 0

<+ x = -1

3.

\(1-2t=0\)

\(\Leftrightarrow2t=1\)

\(\Leftrightarrow\dfrac{1}{2}\)

4. 2x +x + 3 =0

\(\Leftrightarrow3x+3=0\)

\(\Leftrightarrow x=-3\)

5.

\(25x-20=0\)

\(\Leftrightarrow25x=20\)

\(\Leftrightarrow x=\dfrac{4}{5}\)

7.

2x-3 = x+5

<=> 2x - x = 5+3

<=> x = 8

8.

x-8=2x+3

<=> x - 2x = 3+8

<=> -x = 11

<=> x = -11

9. 17-2x = 3x-5

<=> -2x-3x = -5-17

<=> -5x = -22

<=> x = \(\dfrac{22}{5}\)

10.

2x+x+22=0

<=> 3x+22=0

<=> 3x = -22

<=> x = \(\dfrac{-22}{3}\)

Mấy bài kia tự giải tương tự nhá!!!

11.

x-3=3x+5

<=> x-3x=5+3

<=> -2x=8

<=> x = -4

12. 15x + 1/2 = 0

<=> 15x = -1/2

<=> x = -1/30

13.

3x+1 = 7x-11

<=> 3x-7x = -11-1

<=> -4x=-12

<=> x = 3

14.

5-3x = 6x + 7

<=> -3x-6x = 7-12

<=> -9x = -5

<=> x = 5/9

15.

11-2x=x-1

<=> -2x-x = -1-11

<=> -3x = -12

<=> x = 4

16.

15 - 8x = 9-5x

<=> -8x+5x = 9 - 15

<=> -3x = -6

<=> x=2

17.

25-3x=4x-5

<=> -3x-4x = -5-25

<=> -7x = -30

<=> x = 30/7

18.

0,25x+1,5=0

<=> 0,25x = -1,5

<=> x = -6

19.

3x-5/6 = 1/2

<=> 3x - 5/6 = 3/6

<=> 3x-5=3

<=> 3x = 8

<=> x = 8/3

20.

-2x + 14 =0

<=> -2x = -14

<=> x = 7

b) Ta có: \(\left(x^2-7\right)\left(x+2\right)-\left(2x-1\right)\left(x-14\right)+x\left(x^2-2x-22\right)+35\)

\(=x^3+2x^2-7x-14-\left(2x^2-28x-x+14\right)+x^3-2x^2-22x+35\)

\(=2x^3-29x+21-2x^2+29x-14\)

\(=2x^3-2x^2+7\)

\(a,\Rightarrow2^{x-1}=24-\left(16-3\right)-3\\ \Rightarrow2^{x-1}=24-13-3\\ \Rightarrow2^{x-1}=8=2^3\\ \Rightarrow x-1=3\Rightarrow x=4\\ b,\Rightarrow\left(19x+50\right):14=25-16=9\\ \Rightarrow19x+50=126\\ \Rightarrow x=4\)

1.

a,  \(x-14=3x+18\)                                                                       

\(\Rightarrow x-3x=18+14\)                                                                 

\(\Rightarrow-2x=32\Rightarrow x=\frac{32}{-2}=-16\)

b, \(\left(x+7\right).\left(x-9\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+7=0\\x-9=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-7\\x=9\end{cases}}}\)

c, \(\left|2x-5\right|-7=22\)                                                                     

\(\Rightarrow\left|2x-5\right|=22+7\)

\(\Rightarrow\left|2x-5\right|=29\)

\(\Rightarrow\orbr{\begin{cases}2x+5=29\\2x-5=29\end{cases}}\Rightarrow\orbr{\begin{cases}2x=24\\2x=34\end{cases}\Rightarrow}\orbr{\begin{cases}x=12\\x=17\end{cases}}\)

d,  \(\left(\left|2x\right|-5\right)-7=22\)

\(\Rightarrow\left(\left|2x\right|-5\right)=29\)

\(\Rightarrow\left|2x\right|=29+5\Rightarrow\left|2x\right|=34\Rightarrow x=\pm17\)

e, \(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|=4x\)

Vì \(\left|x+3\right|\ge0;\left|x+9\right|\ge0;\left|x+5\right|\ge0;4x\ge0\)

Nên \(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|=4x\ge0\)

\(\Rightarrow\left|x+3\right|>0\Rightarrow\left|x+3\right|=x+3\)

     \(\left|x+9\right|>0\Rightarrow\left|x+9\right|=x+9\)

      \(\left|x+5\right|>0\Rightarrow\left|x+5\right|=x+5\)

Ta có : 

\(x+3+x+9+x+5=4x\)

\(\Rightarrow3x+\left(3+9+5\right)=4x\)

\(\Rightarrow4x-3x=17\)

\(\Rightarrow x=17\)

2. a , b sai đề bn 

c, \(\left(5x+1\right).\left(y-1\right)=4\)

\(\Rightarrow\left(5x+1\right).\left(y-1\right)\inƯ\left(4\right)\)

\(\text{ }Ư\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\)

Ta có bảng sau : 

d, \(5xy-5x+y=5\)

\(\Rightarrow\left(5xy-5x\right)+y=5\)

\(\Rightarrow5x.\left(y-1\right)+y=5\)

\(\Rightarrow\left(5x+1\right).\left(y-1\right)=4\)

\(\Rightarrow\left(5x+1\right).\left(y-1\right)\inƯ\left(4\right)\)

\(Ư\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\)

Ta có bảng sau : 

x - 14 = 3x + 18

x - 3x = 18 + 14

-2x= 32

x= 32 : (-2)

x=-16

a) x – 12 = 14

x = 14 +12

x = 26

b) 2x – 13 = 3.17

2x = 51 + 13

2x = 64

x = 64 : 2

x = 32

c) x – 43 = 2.18

x = 36 +43

x = 79

d) (x – 14).39 = 0

x – 14 = 0

x = 14

e) (13 – x).28 = 28

13 – x = 1

13 – x = 1

x = 13 – 1

x = 12

f) 22.(35 – x) = 22

35 – x = 1

x = 35 – 1

x = 34

g) x – 24 : 2 = 18

x – 12 = 18

x = 39

h) 400 + (275 – x) = 570

275 – x = 570 – 400

275 – x = 170

x = 275 – 170

x = 105

a) \(\left(2x+1\right)\left(1-2x\right)+\left(2x-1\right)^2=22\)

\(\Rightarrow\left(1+2x\right)\left(1-2x\right)+\left[\left(2x\right)^2-2.2x+1^2\right]=22\)

\(\Rightarrow1^2-\left(2x\right)^2+\left(4x^2-4x+1\right)=22\)

\(\Rightarrow1-4x^2+4x^2-4x+1=22\)

\(\Rightarrow2-4x=22\)

\(\Rightarrow-4x=22-2=20\)

\(\Rightarrow x=20:\left(-4\right)=-5\)

b/ \(\left(x-5\right)^2+\left(x-3\right)\left(x+3\right)-2.\left(x+1\right)^2=0\)

\(\Rightarrow\left(x^2-2.x.5+5^2\right)+\left(x^2-3^2\right)+2.\left(x^2+2.x.1+1^2\right)=0\)

\(\Rightarrow x^2-10x+25+x^2-9-2\left(x^2+2x+1\right)=0\)

\(\Rightarrow x^2-10x+25+x^2-9-2x^2-4x-2=0\)

\(\Rightarrow-14x+14=0\)

\(\Rightarrow-14x=0-14=-14\)

\(\Rightarrow x=\left(-14\right):\left(-14\right)=1\)

b/\(\left(x-5\right)^2+\left(x-3\right)\left(x+3\right)-2\left(x+1\right)^2=0\)

\(\Leftrightarrow x^2-10x+25+x^2-3^2-2\left(x^2+2x+1\right)=0\)

\(\Leftrightarrow x^2-10x+25+x^2-9-2x^2-4x-2=0\)

\(\Leftrightarrow14x=14\Leftrightarrow x=1\)

c/\(\left(2x+3\right)^2+\left(2x-3\right)^2-2\left(4x^2-9\right)=0\)

\(\Leftrightarrow4x^2+12x+9+4x^2-12x+9-8x^2+18=0\)

\(\Leftrightarrow0x=-36\Leftrightarrow x=0\)

a/\(\left(2x+1\right).\left(1-2x\right)+\left(2x-1\right)^2=22\Leftrightarrow2x-4x^2+1-2x+4x^2-4x+1=22\Leftrightarrow-4x=20\Leftrightarrow x=-5\)