\(\left(2x-1\right)^3=125\)

\(\Leftrightarrow\left(2x-1\right)^3=5^3\)

\(\Leftrightarrow2x-1=5\Leftrightarrow x=3\)

             \(------\)

\(\left(2x-1\right)^5=x^5\)

\(\Leftrightarrow2x-1=x\)

\(\Leftrightarrow x=1\)

a)\(\left(2x+1\right)^3=5^3\)

\(\Rightarrow2x+1=5\)

\(2x=5-1\)

\(2x=4\)

\(x=4:2\)

\(x=2\)

\(b,\left(2x-1\right)^3=125\)

\(\Rightarrow2x-1=5\)

\(2x=5+1\)

\(2x=6\)

\(x=6:2=3\)

b) \(\left(2x-1\right)^3=125\)

\(\left(2x-1\right)^3=5^3\)

\(2x-1=5\)

\(2x=5+1\)

\(2x=6\)

\(x=6:2\)

\(x=3\)

c) \(4x^3+15=19\)

\(4x^3=19+15\)

\(4x^3=34\)

\(x^3=\frac{34}{4}=\frac{17}{2}\)

Chỗ này có vẻ hơi sai sai ạ :33

a) \(\left(2x-1\right)^4=16\)

\(\)TH1: \(\left(2x-1\right)^4=2^4\)

\(=>2x-1=2\)

\(2x=2+1\)

\(2x=3\)

\(x=\dfrac{3}{2}\)

TH2: \(\left(2x-1\right)^4=\left(-2\right)^4\)

\(=>2x-1=-2\)

\(2x=-2+1\)

\(2x=-1\)

\(x=\dfrac{-1}{2}\)

Vậy x = \(\dfrac{3}{2}\) hoặc x = \(\dfrac{-1}{2}\)

________--

b) \(\left(2x+1\right)^3=125\) ( mình nghĩ đề bài đúng là vầy )

\(\left(2x+1\right)^3=5^3\)

\(=>2x+1=5\)

\(2x=5-1\)

\(2x=4\)

\(x=4:2\)

\(x=2\)

Vậy x = \(2\)

Đề yêu cầu gì em? Tìm x hả?

\(\left(2x+1\right)^3=125=5^3\\ \Leftrightarrow2x+1=5\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=2\)

=>S={2}

\(\left(2x+1\right)^3=125\)
\(\Rightarrow2x+1=5^{ }\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)

\(\Rightarrow\left(2x+1\right)=5^3\\ \Rightarrow2x=5-1\\ \Rightarrow2x=4\\ \Rightarrow x=4:2\\ \Rightarrow x=2\)

\(\left(2x-1\right)^4=16=\left(\pm2\right)^4\\ =>\left[{}\begin{matrix}2x-1=2\\2x-1=-2\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)

\(\left(2x+1\right)^3=125=5^3\\ =>2x+1=1\\ =>x=2\)

???????

\(\left(2x-1\right)^4=16\)

\(\left(2x-1\right)^4=2^4\)

\(2x-1=2\)

\(2x=3\)

\(x=\dfrac{3}{2}\)

\(\left(2x+1\right)^3=125\)

\(\left(2x+1\right)^3=5^3\)

\(2x+1=5\)

\(2x=4\)

\(x=2\)

\(\left(2x+1\right)^3=125\)

\(\Leftrightarrow2x+1=5\)

hay x=2

Giải:

\(\left(2x+1\right)^3=125\)

\(\Rightarrow\) \(\left(2x+1\right)^3=5^3\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow2x=5-1\)

\(\Rightarrow2x=4\)

\(\Rightarrow4:2\)

Vậy \(x=2\)

\(\left(2x-1\right)^3=125\)

\(\Rightarrow2x-1=5\Rightarrow2x=6\Rightarrow x=3\)

(2x - 1)³ = 125

<=> (2x - 1)³ = 5³

<=> 2x - 1 = 5

<=> 2x = 6

<=> x = 3

\(\Rightarrow2x-1=5\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=3\)

\(\left(2x+1\right)^3=125\)

\(\Rightarrow\left(2x+1\right)^3=5^3\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow2x=5-1\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=\dfrac{4}{2}\)

\(\Rightarrow x=2\)

Vậy: x=2

( 2x + 1 ) mũ 3 = 125 

( 2x + 1 ) mũ 3 = 5 mũ 3

2x + 1 = 5

2x = 5 - 1

2x = 4

x = 4 : 2

x = 2

a) Ta có:  ( 2 x + 1 ) 3 = 3 3 nên 2x + 1 = 3. Do đó x = 1.

b) Ta có: ( 2 x - 1 ) 3 = 5 3 nên 2x - 1 = 5. Do đó x = 3.