\(25^6\).\(125^3\)
3.(-7)^2+(-6).7-|-125|:(-25)
=3.49+-42-125:-25
=3.49+-42--5
=3.49+-42+5
=147+-42+5
=105+5
=110
Bai 1 Tinh nhanh
25.(6-125)+125.(25-6)
Bai 2 Tim so nguyen n sao cho
a)13⋮(n+1)
b)(4n+3)⋮(n-2)
Bài 1.2: Tính nhanh:
5+ 5 + 5 + 5+ 5 + 5 +5+ 5 + 5 +5
25 + 25 + 25 + 25 + 25 + 25 +25 + 25
45 + 45 + 45 + 45 + 15 + 15 + 15 + 15
2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18
125 + 125 + 125 + 125 - 25 - 25 - 25 - 25
5+ 5 + 5 + 5+ 5 + 5 +5+ 5 + 5 +5=5x10=50
25 + 25 + 25 + 25 + 25 + 25 +25 + 25=25x8=200
45 + 45 + 45 + 45 + 15 + 15 + 15 + 15=(45x4)+(15x4)=180+60=240
5+ 5 + 5 + 5+ 5 + 5 +5+ 5 + 5 +5
= 5 x 10
= 50
25 + 25 + 25 + 25 + 25 + 25 +25 + 25
= 25 x 8
= 200
45 + 45 + 45 + 45 + 15 + 15 + 15 + 15
= 45 x 4 + 15 x 4
= 180 + 60
= 240
2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18
= (2 + 18) + (4 + 16) + (8 + 12) + (6 + 14) + 10
= 20 + 20 + 20 + 20 + 10
= 20 x 4 + 10
= 80 + 10
= 90
125 + 125 + 125 + 125 - 25 - 25 - 25 - 25
= 4 x (125 - 25)
= 4 x 100
= 400
(Tick cho mk pls ^^)
Thực hiện phép tính
a)\(\dfrac{5^{16}.27^{7}}{125^{5}.9^{11}}\)
b)\((-0,2)^{2}.5-\dfrac{2^{13}.27^{3}}{4^{6}.9^{5}}\)
c)\(\dfrac{5^{6}+2^{2}.25^{3}+2^{3}.125^{2}}{26.5^{6}}\)
\(a,\dfrac{5^{16}\cdot27^7}{125^5\cdot9^{11}}=\dfrac{5^{16}\cdot\left(3^3\right)^7}{\left(5^3\right)^5\cdot\left(3^2\right)^{11}}\)
\(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)
\(b,\left(-0,2\right)^2\cdot5-\dfrac{2^{13}\cdot27^3}{4^6\cdot9^5}\)
\(=0,04\cdot5-\dfrac{2^{13}\cdot\left(3^3\right)^3}{\left(2^2\right)^6\cdot\left(3^2\right)^5}\)
\(=0,2-\dfrac{2^{13}\cdot3^9}{2^{12}\cdot3^{10}}\)
\(=0,2-\dfrac{2}{3}\)
\(=-\dfrac{7}{15}\)
\(c,\dfrac{5^6+2^2\cdot25^3+2^3\cdot125^2}{26\cdot5^6}\)
\(=\dfrac{5^6+2^2\cdot\left(5^2\right)^3+2^3\cdot\left(5^3\right)^2}{5^6\cdot26}\)
\(=\dfrac{5^6+4\cdot5^6+8\cdot5^6}{5^6\cdot26}\)
\(=\dfrac{5^6\left(1+4+8\right)}{5^6\cdot26}\)
\(=\dfrac{13}{26}\)
\(=\dfrac{1}{2}\)
#\(Toru\)
\(a,\dfrac{5^{16}.27^7}{125^5.9^{11}}=\dfrac{\left(5^2\right)^8.9^7.3^7}{25^5.5^5.9^{11}}\\ =\dfrac{25^8.9^7.\left(3^2\right)^3.3}{25^5.\left(5^2\right)^2.5.9^{11}}=\dfrac{25^8.9^7.9^3.3}{25^5.25^2.5.9^{11}}\\ =\dfrac{25^8.9^{10}.3}{25^7.5.9^{11}}=\dfrac{25^7.9^{10}.25.3}{25^7.9^{10}.5.9}\\ =\dfrac{25.3}{5.9}=\dfrac{5.5.3}{5.3.3}=\dfrac{5}{3}\)
bài 2 viết mỗi tích, thương sau dưới dạng luỹ thừa
a) 4^10 x 2^30 b) 9^25 x 27^4 x 81^3 c) 25^50 x 125^5 d) 64^3 x 4^8 x 16^4
e)3^8:3^6 ; 2^10:8^3 ; 12^7 :6^7 ; 31^5 ; 81^3
f) 5^8 : 25^2 ; 4^9:64^2 ; 2^25 : 32^4 ; 125^3 : 25^4
a, 410. 230=220.230=250
b,925.274.813= 350.312.312=374
Tương tự các câu khác....
a, 410.230 = (22)10.230 = 220.230 = 250
b, 925.274.813 = (32)25.(33)4.(34)3 = 350.312.312 = 374
c, 2550.1255 = (52)50.(53)5 = 5100.515 = 5115
d, 643.48.164 = (26)3.(22)8.(24)4 = 218.216.216 = 250
e, 38 : 36 = 32
210 : 83 = 210 : (23)3 = 210 : 29 = 2
127 : 67 = (12 : 6)7 = 27
@Dương Tuyết Mai
Viết các biểu thức sau dưới dạng một lũy thừa:
1,125 x 27
2, 12^3 x 64
3, 25^6 x 8^3
4, 25^6 x 125^3
5, 625^5 : 25^7
`a, = 5^3 xx 3^3 = 15^3`
`b, = 12^3 xx 4^3 = 48^3`
`c, = 625^3 xx 8^3 = 5000^3`
`d, = 625 ^3 xx 125^3 = 78125^3`
`e, = 5^20 : 5^14 = 5^6`
1,\(125\cdot27=5^3\cdot3^3=\left(5\cdot3\right)^3=15^3\)
2, \(12^3\cdot64=12^3\cdot4^3=\left(12\cdot4\right)^3=48^3\)
3, \(25^6\cdot8^3=\left(5^2\right)^6\cdot\left(2^3\right)^3=5^8\cdot2^9\)
4, \(25^6\cdot125^3=\left(5^2\right)^3\cdot\left(5^3\right)^3=5^6\cdot5^9=5^{15}\)
5,\(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\)
12 x 62 x 3 + 6 mũ 2 x 38 - 125: 25
\(12.62.3+6^2.38-125:25\\ =36.62+36.38-5\\ =36.\left(62+38\right)-5\\ =36.100-5\\ =3600-5\\ =3595.\)
\(12\cdot62\cdot3+6^2\cdot38-125:25\)
\(=12\cdot62\cdot3+36\cdot38-5\)
\(=2232+1368-5\)
\(=3595\)
Tính :
1) ( -35 ). 18 + 28. 35
2) 53. 29 - 47. ( -29 )
3) 125. ( -24 ) + 24. 225
4) 26. ( -121 ) - 121. ( -36 )
5) 65. ( -25 ) + 25. ( -23 )
6) 237. ( -26 ) + 26. 137
7) 30. ( -125 ) + 25. 30
8) ( -37 ). 69 + ( -31 ). 37
9) 31. 72 - 31. 70 - 31.2
10) ( -12 ). 47 + ( -12 ) . 52 + ( -12 )
1) $(-35)\cdot18+28\cdot35$
$=35\cdot(-18)+28\cdot35$
$=35\cdot(-18+28)$
$=35\cdot10$
$=350$
2) $53\cdot29-47\cdot(-29)$
$=53\cdot29-47\cdot(-1)\cdot29$
$=53\cdot29+47\cdot29$
$=29\cdot(53+47)$
$=29\cdot100$
$=2900$
3) $125\cdot(-24)+24\cdot225$
$=(-125)\cdot24+24\cdot225$
$=24\cdot(-125+225)$
$=24\cdot100$
$=2400$
4) $26\cdot(-121)-121\cdot(-36)$
$=-121\cdot[26+(-36)]$
$=-121\cdot(26-36)$
$=-121\cdot(-10)$
$=121\cdot10$
$=1210$
5) $65\cdot(-25)+25\cdot(-23)$
$=-65\cdot25+25\cdot(-23)$
$=25\cdot(-65-23)$
$=25\cdot(-88)$
$=-2200$
6) $237\cdot(-26)+26\cdot137$
$=-237\cdot26+26\cdot137$
$=26\cdot(-237+137)$
$=26\cdot(-100)$
$=-2600$
7) $30\cdot(-125)+25\cdot30$
$=30\cdot(-125+25)$
$=30\cdot(-100)$
$=-3000$
8) $(-37)\cdot69+(-31)\cdot37$
$=37\cdot(-69)+37\cdot(-31)$
$=37\cdot(-69-31)$
$=37\cdot(-100)$
$=-3700$
9) $31\cdot72-31\cdot70-31\cdot2$
$=31\cdot(72-70-2)$
$=31\cdot(2-2)$
$=31\cdot0$
$=0$
10) $(-12)\cdot47+(-12)\cdot52+(-12)$
$=-12\cdot(47+52+1)$
$=-12\cdot100$
$=-1200$
$\text{#}Toru$
Bài 2: Thực hiện phép tính:
a) 125 + (-4).6 – (-3).(-25)
b) (-26).7 + 2.[(-18) + 15 – 20]
c) 24 – (-12).2 + (-3).(-6) \
d) (-18) – 6.[25 – 17.(-9) + 12]
mn giuos mình vs
bài 3 chuyển đổi các phân số sau thành số thập phân 7/5 ; 34/20 ; 25/50 ; 6/25 ; 24/125
\(\dfrac{7}{5}=1,4\\ \dfrac{34}{20}=1,7\\ \dfrac{25}{50}=0,5\\ \dfrac{6}{25}=0,24\\ \dfrac{24}{125}=0,192\)
`7/5 =7:5=1,4`
`34/20 = 34:20=1,7`
`25/50=25:50=0,5`
`6/25=6:25=0,24`
`24/125=0,192`
\(\dfrac{7}{5}\)=1,4;\(\dfrac{34}{20}\)=1,7;\(\dfrac{25}{50}\)=0,5;\(\dfrac{6}{25}\)=0,24;\(\dfrac{24}{125}\)=0,192.