\(x\times\dfrac{11}{8}=\dfrac{33}{20}\)

\(x=\dfrac{33}{20}:\dfrac{11}{8}\)

\(x=\dfrac{33}{20}\times\dfrac{8}{11}\)

\(x=\dfrac{6}{5}\)

__________________________

\(5:x=\dfrac{4}{7}\)

    \(x=5:\dfrac{4}{7}\)

   \(x=5\times\dfrac{7}{4}\)

   \(x=\dfrac{35}{4}\)

Chúc bạn học tốt

a: \(\Leftrightarrow x=\dfrac{33}{20}:\dfrac{11}{8}=\dfrac{33}{20}\cdot\dfrac{8}{11}=3\cdot\dfrac{2}{5}=\dfrac{6}{5}\)

b: \(\Leftrightarrow x=5:\dfrac{4}{7}=\dfrac{35}{4}\)

a) =(7/11+4/11)+(3/4+1/4)    b)=>4/5x=12                    c)=>x-6/10=1/10      d)tự làm             e)=>4/x=4/20           f)=>198/33+x/33=21/33

=1+1                                              x=12.5/4                        x=1/10+6/10                                      =>x=20               =>x=21-198

=2                                                     x=15                            x=7/10                                                                          =>x=-177

tick cho em dc ko

x=-36

x=11

x=100

x=14

x=-36

x=11

x=100

x=14

2: \(\Leftrightarrow\left(\dfrac{x+1}{12}-1\right)+\left(\dfrac{x+2}{13}-1\right)=\left(\dfrac{x+3}{14}-1\right)+\left(\dfrac{x+4}{15}-1\right)\)

=>x-11=0

=>x=11

3: \(\Leftrightarrow\left(\dfrac{x-85}{15}-1\right)+\left(\dfrac{x-74}{13}-2\right)+\left(\dfrac{x-67}{11}-3\right)+\left(\dfrac{x-64}{9}-4\right)=0\)

=>x-100=0

=>x=100

11: Ta có: \(\left(x+3\right)^3=125\)

\(\Leftrightarrow x+3=5\)

hay x=2

12: Ta có: \(\left(2x\right)^4=16\)

\(\Leftrightarrow x^4=1\)

hay \(x\in\left\{1;-1\right\}\)

11: Ta có: \left(x+3\right)^3=125(x+3)3=125

$\iff x+3=5$

hay x=2

12: Ta có: \left(2x\right)^4=16(2x)4=16

\Leftrightarrow x^4=1(2x)   = 2   =2  4

           4      

⇔2x=2⇔ x=1

13) 32:(3x-2)=2^3

32:(3x-2)=8

3x-2=32:8=4

3x=4+2=6

x=6:3=2

⇔x=2

Ai biết chỉ mình nha 

1. 11(x-9)=77

x-9=7

x=16

2. 4(x-3)=48

x-3=12

x=15

3.3(x-8)=81

(x-8)=27

x=35

\(40-21:\left(2.x+3\right)=33\)

\(21:\left(2.x+3\right)=40-33\)

\(21:\left(2.x+3\right)=7\)

\(\left(2.x+3\right)=21:7\)

\(\left(2.x+3\right)=3\)

\(2.x=3-3\)

\(2.x=0\)

\(x=0:2\)

\(x=0\)

\(\frac{22}{25}\times\frac{5}{11}-\frac{33}{25}:\frac{11}{5}+\frac{58}{11}\)

\(=\frac{22}{25}\times\frac{5}{11}-\frac{33}{25}\times\frac{5}{11}+\frac{58}{11}\)

\(=\frac{5}{11}\times\left(\frac{22}{25}+\frac{33}{25}\right)+\frac{58}{11}\)

\(=\frac{5}{11}\times\frac{11}{5}+\frac{58}{11}\)

\(=1+\frac{58}{11}\)

\(=\frac{11}{11}+\frac{58}{11}\)

\(=\frac{69}{11}\)

\(8\frac{3}{11}-\left(3\frac{5}{7}-7\frac{8}{11}\right)\)

\(=\frac{91}{11}-\left(\frac{26}{7}-\frac{85}{11}\right)\)

\(=\frac{91}{11}-\frac{26}{7}+\frac{85}{11}\)

\(=\frac{91}{11}+\frac{85}{11}-\frac{26}{7}\)

\(=16-\frac{26}{7}\)

\(=\frac{86}{7}\)

\(\frac{5}{6}x+325\%=\frac{3}{2}x-30,75\)

\(=>\frac{5}{6}x+3,25=\frac{3}{2}x-30,75\)

\(=>\frac{5}{6}x-\frac{3}{2}x=-30,75-3,25\)

\(=>\frac{-2}{3}x=-34\)

\(=>x=-34:\left(-\frac{2}{3}\right)\)

\(=>x=-34.\left(\frac{3}{-2}\right)\)

\(=>x=51\)

Câu 3: 

a: Chọn D

b: Chọn A

Câu 4: B

Câu 5:B

Câu 6: C

Câu 3: 

a: Chọn D

b: Chọn A

Câu 4: B

Câu 5: B

Câu 6: C