8/11 +8/33 nhân 3/4
11/4 nhân -5/9 nhân 8/33 cho lời giải chi tiết
\(\dfrac{11}{4}.\dfrac{-5}{9}.\dfrac{8}{33}\) \(=\dfrac{-55}{36}.\dfrac{8}{33}=\dfrac{-10}{27}\)
= (11/4 x 8/33) x -5/9
= 2/3 x -5/9
= -10/27
= (11/4 x 8/33) x -5/9
= 2/3 x -5/9
= -10/27
câu trả lời cho câu hỏi của Huong Le Thị Lan: 1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32.
=(1+32)+(2+31)+(3+30)+(4+29)+(5+28)+(6+27)+(7+26)+(8+25)+(9+24)+(10+23)+(11+22)+(12+21)+(13+20)+(14+19)+(15+18)+(16+17)
=33+33+33+33+33+33+33+33+33+33+33+33+33+33+33+33. =33.16 (dấu chấm là dấu nhân)=528
wow! mù mắt. Ido tính toán có khác!
C2:(32+1)x32:2=528
bạn tính thử xem đúng đấy.
1/72 nhân 7^4 nhân 11^2 nhân 77^4 nhân 1^8/7^2 nhân(7^8)^3 nhân (-11)^3 nhân 7^15 nhân 11^8
8/11 + 8/33 x 3/4
\(\dfrac{8}{11}+\dfrac{8}{33}\times\dfrac{3}{4}=\dfrac{8}{11}+\dfrac{2}{11}=\dfrac{10}{11}\)
4/-33-5/11+-4/-33+-8/3
\(\dfrac{4}{-33}-\dfrac{5}{11}+\dfrac{-4}{-33}+\dfrac{-8}{3}\)
\(=\dfrac{4}{-33}-\dfrac{5}{11}+\dfrac{4}{33}+-\dfrac{8}{3}\)
\(=\left(\dfrac{4}{-33}+\dfrac{4}{33}\right)+\left(-\dfrac{5}{11}+\dfrac{-8}{3}\right)\)
\(=0+\left(\dfrac{-15}{33}+\dfrac{-88}{33}\right)\)
\(=0+\dfrac{-103}{33}=\dfrac{-103}{33}\)
6 nhân 8 nhân 11
33 nhân 16
6 nhân 8 nhân 11 bằng 528
33 nhân 16 bằng 528
Tìm x
a) x nhân 11/8 = 33/20 b) 5 : x = 4/7
Ai xong trước thì tui mới kich đúng
a: \(\Leftrightarrow x=\dfrac{33}{20}:\dfrac{11}{8}=\dfrac{33}{20}\cdot\dfrac{8}{11}=3\cdot\dfrac{2}{5}=\dfrac{6}{5}\)
b: \(\Leftrightarrow x=5:\dfrac{4}{7}=\dfrac{35}{4}\)
Tính:
\(\dfrac{8}{11}-\dfrac{8}{33}\) χ \(\dfrac{3}{4}\)
\(\dfrac{8}{11}-\dfrac{8}{44}\times\dfrac{3}{4}=\dfrac{8}{11}-\dfrac{8\times3}{33\times4}=\dfrac{8}{11}-\dfrac{2}{11}=\dfrac{6}{11}\)
\(\dfrac{8}{11}\) - \(\dfrac{8}{33}\) x \(\dfrac{3}{4}\) = \(\dfrac{8}{11}\) - \(\dfrac{2}{11}\) = \(\dfrac{6}{11}\)
\(\dfrac{11}{8}.\left[\left(-\dfrac{5}{11}:\dfrac{13}{8}-\dfrac{5}{11}:\dfrac{13}{15}\right)+\dfrac{-6}{33}\right]+\dfrac{-3}{4}\)
\(\dfrac{11}{8}\cdot\left[\left(-\dfrac{5}{11}:\dfrac{13}{8}-\dfrac{5}{11}:\dfrac{13}{15}\right)+\dfrac{-6}{33}\right]+\dfrac{-3}{4}\)
\(=\dfrac{11}{8}\cdot\left[\left(-\dfrac{5}{11}\cdot\dfrac{8}{13}-\dfrac{5}{11}\cdot\dfrac{15}{13}\right)-\dfrac{2}{11}\right]-\dfrac{3}{4}\)
\(=\dfrac{11}{8}\cdot\left[-\dfrac{5}{11}\cdot\left(\dfrac{8}{13}+\dfrac{15}{13}\right)-\dfrac{2}{11}\right]-\dfrac{3}{4}\)
\(=\dfrac{11}{8}\cdot\left(-\dfrac{5}{11}\cdot\dfrac{23}{13}-\dfrac{2}{11}\right)-\dfrac{3}{4}\)
\(=\dfrac{11}{8}\cdot\left(-\dfrac{115}{143}-\dfrac{2}{11}\right)-\dfrac{3}{4}\)
\(=\dfrac{11}{8}\cdot\dfrac{-141}{143}-\dfrac{3}{4}\)
\(=-\dfrac{141}{104}-\dfrac{3}{4}\)
\(=-\dfrac{219}{104}\)