Tính nhanh:

 1+2+3+4+5+6+7+8+9+10

=(1+9)+(2+8)+(3+7)+(4+6)+10+5

=  10  +  10  +  10   + 10  + 10+5

=             50   +   5

=    55

123*45+123*50+123*5

=  123*(45+50+5)

=   123 * 100

=   12300

K mk nha bn

1+2+3+4+5+6+7+8+9+10

= ( 1+10 ) + ( 2+9) + (3+8) + (4+7) + (5+6)

=     11    +      11   +   11    +   11  +    11

=11 x 5 

=55

123 x 45 + 123 x 50 + 123 x 5 

= 123 x ( 45 + 50 +5 )

= 123 x 100

=12300

hok tốt .

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 10 : 2 x 11 = 55

123 x 45 + 123 x 50 + 123 x 5 = 123x ( 45 + 50 + 5) = 123 x 100 = 12300

\(\frac{x+110}{100}+\frac{x+8}{102}+\frac{x+6}{104}=\frac{x+4}{106}+\frac{x+2}{108}\)

\(\Leftrightarrow\frac{x+110}{100}+\left(\frac{x+8}{102}+1\right)+\left(\frac{x+6}{104}+1\right)=\left(\frac{x+4}{106}+1\right)+\left(\frac{x+2}{108}+1\right)\)

\(\Leftrightarrow\frac{x+110}{100}+\frac{x+110}{102}+\frac{x+110}{104}=\frac{x+110}{106}+\frac{x+110}{108}\)

\(\Leftrightarrow\frac{x+110}{100}+\frac{x+110}{102}+\frac{x+110}{104}-\frac{x+110}{106}-\frac{x+110}{108}=0\)

\(\Leftrightarrow\left(x+110\right)\left(\frac{1}{100}+\frac{1}{102}+\frac{1}{104}+\frac{1}{106}+\frac{1}{108}\right)=0\)

\(\Leftrightarrow x+110=0\) (vì \(\frac{1}{100}+\frac{1}{102}+\frac{1}{104}-\frac{1}{106}-\frac{1}{108}>0\))

\(\Leftrightarrow x=-110\)

Vậy \(x=-110\)

mn giải hộ mik ik

`4)x^2-5x+6`

`=x^2-2x-3x+6`

`=x(x-2)-3(x-2)=(x-2)(x-3)`

`5)x^2+7x+10`

`=x^2+5x+2x+10`

`=x(x+5)+2(x+5)=(x+5)(x+2)`

`6)x+7\sqrt{x}+10`    `ĐK: x >= 0`

`=(\sqrt{x})^2+5\sqrt{x}+2\sqrt{x}+10`

`=\sqrt{x}(\sqrt{x}+5)+2(\sqrt{x}+5)=(\sqrt{x}+5)(\sqrt{x}+2)`

`7)3x^4+7x^2+4`

`=3x^4+3x^2+4x^2+4`

`=3x^2(x^2+1)+4(x^2+1)=(x^2+1)(3x^2+4)`

`8)x^2-x-2`

`=x^2-2x+x-2`

`=x(x-2)+(x-2)=(x-2)(x+1)`

`9)x^6-x^3-2`

`=x^6+x^3-2x^3-2`

`=x^3(x^3+1)-2(x^3+1)`

`=(x^3+1)(x^3-2)`.

Phân tích đa thức thành nhân tử:

123 x 4 + 123 x 6 + 123 x 9 + 123

= 123 x 4 + 123 x 6 + 123 x 9 + 123 x 1

= 123 x (4 + 6 + 9 + 1)

= 123 x 20

= 2460

Đáp số : 2460

123 x 4 + 123 x 6 + 123 x 9 +123
= 123 x 4 + 123 x 6 + 123 x 9 +123 x 1
= 123 x (4 + 6 + 9 + 1)
= 123 x 20
= 2460

123x4 +123x6 +123x9 +123

=123 x4 +123x6+ 123x9 +123 x1

=123x (4+6+9+1)

=123x 20

=2460

3(x + 6) = 2(x - 5)

=> 3x + 18 = 2x - 10

=> 3x - 2x = -10 - 18

=> x = -28

vay_

c, |3x - 7| = 6

=> 3x - 7 = 6 hoac 3x - 7 = -6

=> 3x = 13 hoac 3x = 1

=> x = 13/3 hoac x = 1/3

vay_

3(x + 6) = 2(x - 5)

=> 3x + 18 = 2x - 10

=> 3x - 2x = -10 - 18

=> x = -28

Vậy x = -28

c, |3x - 7| = 6

=> 3x - 7 = 6 hoac 3x - 7 = - 6

=> 3x = 13 hoac 3x = 1

=> x = \(\frac{13}{3}\) hoac x = \(\frac{1}{3}\)

Vậy \(x\in\left\{\frac{3}{13};\frac{1}{3}\right\}\)

=123x10=1230

\(=123\times\left(6+3+1\right)\)
\(=123\times10\)
\(=1230\)

\(123\times6+123+3\times123\\ =123\times\left(6+1+3\right)\\ =123\times10\\ =1230\)