8x7+8x3+8+2
tính bằng cách thuận tiện nhất:
a 1+2+3+4+5+6+7+8+9
b 8x3+8x7
c 8x172-8x72
a)1+2+3+4+5+6+7+8+9
=(1+9)+(2+8)+(3+7)+(4+6)+5
=10+10+10+10+5
=10x4+5=45
b)8x3+8x7
=8x(3+7)
=8x10=80
c)8x172-8x72
=8x(172-72)
=8x100=800
a. 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 +9
= (1 + 9) + (2 + 8) + (3 + 7) + ( 4 + 6) + 5
= 10 + 10 + 10 + 10 + 5
= 45
Bài 1: \(\dfrac{1}{3}\) + \(\dfrac{2}{4}\) + \(\dfrac{3}{5}\) ...........................3(>,<,=)
A.>
B.<
C.=
Bài 2: \(\dfrac{8x7-8x3}{8x2}\) = ?
A.2
B.3
C.4
D.5
8x1=
8x2=
8x3=
8x4=
8x5=
8x6=
8x7=
8x8=
8x9=
8x10=
8x1=8
8x2=16
8x3=24
8x4=32
8x5=40
8x6=48
8x7=56
8x8=64
8x9=72
8x10=80
8x1=8
8x2=16
8x3=24
8x4=32
8x5=40
8x6=48
8x7=56
8x8=64
8x9=72
8x10=80
minh nhanh nhat k nha
8x1=
8x2=
8x3=
8x4=
8x5=
8x6=
8x7=
8x8=
8x9=
8x10=
8x1=8
8x2=16
8x3=24
8x4=32
8x5=40
8x6=48
8x7=56
8x8=64
8x9=72
8x10=80
8 x 1 = 8
8 x 2 = 16
8 x 3 = 24
8 x 4 = 32
8 x 5 = 40
8 x 6 = 48
8 x 7 = 56
8 x 8 = 64
8 x 9 = 72
8 x 10 = 80
8x1=8
8x2=16
8x3=24
8x4=32
8x5=40
8x6=48
8x7= 56
8x8=64
8x9= 72
8x10=80
Tính giá trị biểu thức:
A=72006-8x72005+8x72004-.........+8x72-8x7
-5/8x5/12+-5/8x7/12+17/8
\(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+\frac{17}{8}\)
= \(\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)
= \(\frac{-5}{8}.\frac{12}{12}+\frac{17}{8}\)
5/8x20/9+5/8x7/9+ 1 và 5/8
\(\dfrac{5}{8}\times\dfrac{20}{9}-\dfrac{5}{8}\times\dfrac{7}{9}+1\)
\(=\dfrac{5}{8}\times\left(\dfrac{20}{9}-\dfrac{7}{9}\right)+1\)
\(=\dfrac{5}{8}\times\dfrac{13}{9}+1\)
\(=\dfrac{65}{72}\)
Ta có: \(\dfrac{5}{8}=\dfrac{45}{72}\)
Mà: \(65>45\)
Vậy: \(\dfrac{65}{72}>\dfrac{45}{72}\) hay \(\dfrac{5}{8}\times\dfrac{20}{9}+\dfrac{5}{8}\times\dfrac{7}{9}+1>\dfrac{5}{8}\)
Tính nhanh: (8x7-16-5x8)x(1+2+3+4+5+6+7+8+9)
=(8*7-8*2-8*5)*((1+9)+(2+8)+(3+7)+(4+6)+5)
=(8*(7-2-5))*(10+10+10+10+5)
=(8*0)*(10+10+10+10+5)
=0*(10+10+10+10+5)
=0
Câu 3: Điền vào chỗ trống :
A.2x3 - 1 B.8x3 - 1 C. 8x3 + 1 D.8 - x3