\(a,=12x^2+18x-12x^2+x+1=19x+1\)

\(a,=12x^2+18x-12x^2+x+1=19x+1\\ b,=4x^3y^4-3xy^2-\dfrac{3}{2}x\)

Bài 2

A =  (x + 2)^ 2 - x - 3 x (x + 1) = x² + 4x + 4 - x² + 2x + 3 = 6x + 7

B = x^3 - 2x² + 5x - 10 = x² x (x - 2) + 5 x (x - 2) = (x - 2) x (x² + 5)

Vậy x^3 - 2x² + 5x - 10 : (x - 2) = x² + 5

Đề bài lỗi rồi bạn, bạn xem lại nhé!

a: Ta có: \(x\left(2-3x\right)+\left(3x^3-x^2\right):x\)

\(=2x-3x^2+3x^2-x\)

=x

b: Ta có: \(2x\left(x-3y\right)-\left(8x^3y-12x^2y^2\right):2xy\)

\(=2x^2-6xy-4x^2+6xy\)

\(=-2x^2\)

a) \(3xy^3\left(-2x^2yz^3\right)=-6x^3y^4z^3\)

b) \(xy\left(-8xy^4\right)=-8x^2y^5\)

c) \(x^3y\left(-5y^2z\right)=-5x^3y^3z\)

d) \(-x\left(-3x^3y\right)=3x^4y\)

a,  -6x³y⁴z³        ;            b,  -8x²y⁵           ;              c,  -5x³y³z           ;             c,   3x⁴y

a)3⁶:3²+2³.2²-3³.3 

= 3⁴+2⁵-3⁴

=2⁵

=32

b)3⁸:3⁴-9⁵:9³

= 3⁴-9²

= 3⁴-3⁴

= 0

c)2³.15+2³.35

= 2³(15+35)

= 8.50

= 400

a: \(3^6:3^2+2^3\cdot2^2-3^3\cdot3\)

\(=3^4+32-3^4\)

=32

b: \(3^8:3^4-9^5:9^3\)

\(=3^4-9^2\)

=0

c: Ta có: \(2^3\cdot15+2^3\cdot35\)

\(=8\cdot50\)

=400

c: \(=4x^2-12x+9-4x^2+x=-11x+9\)

\(a,=2x^2-10x+x^2+x-6=3x^2-9x-6\\ b,=x^2+4x+4-x^2+8x-15=12x-11\\ c,=4x^2-12x+9-4x^2+x=-11x+9\)