=> 3.|5-2x|=7,5-(-4,5)

=>3|5-2x|=7,5+4,5=12

=>|5-2x|=12:3=4

=>5x-2=4 (luôn luôn lớn hơn hoặc bằng 0)

=>5x=4+2=6

=>x=6:5 

Vậy x=1,2

7,5 - 3 |5 - 2x| = -4,5 => -3 |5 - 2x| = -12 => |5 - 2x| = 4

=> 5 - 2x = 4 hoặc -4

=> -2x = -1 hoặc -9

=> x = 0,5 hoặc x = 4,5

\(7,5-3\left|5-2x\right|=-4,5\)

\(\Leftrightarrow3\left|5-2x\right|=7,5-\left[-4,5\right]\)

\(\Leftrightarrow3\left|5-2x\right|=7,5+4,5\)

\(\Leftrightarrow3\left|5-2x\right|=12\)

\(\Leftrightarrow\left|5-2x\right|=4\)

\(\Leftrightarrow\orbr{\begin{cases}5-2x=4\\5-2x=-4\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{9}{2}\end{cases}}\)

\(7,5-3\left|5-2x\right|=-4,5\)

\(\Leftrightarrow3\left|5-2x\right|=7,5-\left(-4,5\right)\)

\(\Leftrightarrow3\left|5-2x\right|=7,5+4,5\)

\(\Leftrightarrow3\left|5-2x\right|=12\)

\(\Leftrightarrow\left|5-2x\right|=12:3\)

\(\Leftrightarrow\orbr{\begin{cases}5-2x=4\\5-2x=-4\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=5-4\\2x=5-\left(-4\right)\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=1\\2x=9\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=1:2\\x=9:2\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{9}{2}\end{cases}}\)

~ Rất vui vì giúp đc bn ~

\(3|5-2x|=7,5-\left(-4,5\right)\)

\(3\left|5-2x\right|=12\)

     \(\left|5-2x\right|=12:3\)

      \(\left|5-2x\right|=4\)

\(\Rightarrow\)\(\hept{\begin{cases}5-2x=4\\5-2x=-4\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}2x=5-4\\2x=5-\left(-4\right)\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}2x=1\\2x=9\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=1:2\\x=9:2\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=0,5\\x=4,5\end{cases}}\)

Vậy \(x=0,5\)hoặc \(x=4,5\)

b) x = 1,75

câu a bạn chưa ghi x

cậu làm ơn ghi rõ lời giải ra đi

để tớ viết lại câu a

7,5 . 1 3/4=6 2/5

a: Ta có: \(\left|\dfrac{2}{5}-x\right|+\dfrac{1}{2}=3.5\)

\(\Leftrightarrow\left|x-\dfrac{2}{5}\right|=3\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{2}{5}=3\\x-\dfrac{2}{5}=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{17}{5}\\x=-\dfrac{13}{5}\end{matrix}\right.\)

b: Ta có: \(\dfrac{21}{5}+3:\left|\dfrac{x}{4}-\dfrac{2}{3}\right|=6\)

\(\Leftrightarrow3:\left|\dfrac{1}{4}x-\dfrac{2}{3}\right|=6-\dfrac{21}{5}=\dfrac{9}{5}\)

\(\Leftrightarrow\left|\dfrac{1}{4}x-\dfrac{2}{3}\right|=\dfrac{5}{3}\)

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{4}x-\dfrac{2}{3}=\dfrac{5}{3}\\\dfrac{1}{4}x-\dfrac{2}{3}=-\dfrac{5}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{4}x=\dfrac{7}{3}\\\dfrac{1}{4}x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{28}{3}\\x=-4\end{matrix}\right.\)