1.

a) = 354

b) = -54

c) = -167

2.

A= -37

\(A=\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+\left(1-\frac{1}{12}\right)+....+\left(1-\frac{1}{90}\right)+\left(1-\frac{1}{110}\right)+\frac{10}{11}\)

\(=10-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{10.11}\right)+\frac{10}{11}=10-\left(1-\frac{1}{11}\right)+\frac{10}{11}=10\)

(99-97)+(95-93)+.....................+(7-5)+(3-1)

=>(99-1):2+1+50

<=>50:2=25

mà 25x2=50

Bài 3: 

a: \(=-8\left(72+19-1\right)=-8\cdot90-720\)

b: \(=-27\left(1011-12-1\right)=-27\cdot998=-26946\)

c: \(=17\cdot\left[29+111\right]+29\cdot\left(-17\right)\)

\(=17\left(29+111-29\right)=17\cdot111=1887\)

d: \(=43\cdot\left(-1\right)+40=-43+40=-3\)

a) \(\left(-17\right)\cdot32+17\cdot\left(-68\right)-17\)

\(=17\cdot\left(-32-68-1\right)\)

\(=17\cdot\left(-101\right)\)

\(=17\cdot\left(-100-1\right)\)

\(=-1700-17\)

\(=-1717\)

b) \(25\cdot\left(34-89\right)+25\cdot89\)

\(=25\cdot\left(34-89+89\right)\)

\(=25\cdot34\)

\(=850\)

c) \(-145\cdot\left(13-57\right)+57\cdot\left(10-145\right)\)

\(=-145\cdot13+145\cdot57+57\cdot10-145\cdot57\)

\(=-145\cdot\left(13+57\right)+57\cdot\left(145+10\right)\)

\(=-145\cdot70+57\cdot155\)

\(=-10150+8835\)

\(=-1315\)

`@` `\text {Ans}`

`\downarrow`

`a)`

\((- 17) . 32 + 17 . (- 68) – 17 \)

`= (-17). (32 + 68 + 1) `

`= (-17). 101`

`= -1717`

`b)`

\(25 . (34 – 89) + 25 . 89\)

`= 25. (34 - 89 + 89)`

`= 25. 34`

`= 850`

`c)`

\(– 145. (13 – 57) + 57. (10 – 145)\)

`= (-145). 13 - (-145). 57 + 57.10 + 57. (-145)`

`= (-145). (13 - 57 + 57) + 57.10`

`= (-145). 13 + 570`

`= -1885 + 570 = -1315`

mn giúp mình v

=[11+89]x[10+2+3+5]

=100x20

=2000

=110 + 89 * (5+3+2)

=110 + 89 * 10

= 110 + 890 

=1000