x= 13/21

\(x+-\dfrac{1}{9}=-\dfrac{1}{6}\)

\(\Rightarrow x-\dfrac{1}{9}=-\dfrac{1}{6}\)

\(\Rightarrow x=-\dfrac{1}{6}+\dfrac{1}{9}\)

\(\Rightarrow x=-\dfrac{1}{18}\)

_______________

\(5x-3x-\dfrac{5}{6}=\dfrac{2}{3}\)

\(\Rightarrow2x-\dfrac{5}{6}=\dfrac{2}{3}\)

\(\Rightarrow2x=\dfrac{2}{3}+\dfrac{5}{6}\)

\(\Rightarrow2x=\dfrac{3}{2}\)

\(\Rightarrow x=\dfrac{3}{2}:2\)

\(\Rightarrow x=\dfrac{3}{4}\)

=>2x=2/3

hay x=1/3

\(\dfrac{9}{7}\times x+\dfrac{5}{7}\times x=\dfrac{2}{3}\)

\(\dfrac{14}{7}\times x=\dfrac{2}{3}\)

\(x=\dfrac{2}{3}:2=\dfrac{1}{3}\)

2x=2/3

hay x=1/3

đề hỏi tìm gì mình không biết

<=>\(\left|\dfrac{1}{2}-2x\right|=\dfrac{5}{3}< =>\left[{}\begin{matrix}\dfrac{1}{2}-2x=\dfrac{5}{3}\\\dfrac{1}{2}-2x=\dfrac{-5}{3}\end{matrix}\right.< =>\left[{}\begin{matrix}2x=\dfrac{-7}{6}\\2x=\dfrac{13}{6}\end{matrix}\right.< =>\left[{}\begin{matrix}x=\dfrac{-7}{12}\\x=\dfrac{13}{12}\end{matrix}\right.\)

\(\left|\dfrac{1}{2}+2x\right|+\dfrac{2}{3}=\dfrac{7}{3}\)

\(\left|\dfrac{1}{2}+2x\right|=\dfrac{7}{3}-\dfrac{2}{3}=\dfrac{5}{3}\)

⇔\(\left[{}\begin{matrix}\dfrac{1}{2}+2x=\dfrac{5}{3}\\\dfrac{1}{2}+2x=-\dfrac{5}{3}\end{matrix}\right.\)

⇔ \(\left[{}\begin{matrix}x=\dfrac{7}{12}\\x=-\dfrac{13}{12}\end{matrix}\right.\)

Vậy ...

⎡⎢ ⎢⎣x=712x=−1312[x=712x=−1312

Vậy ...

a: =5/6(1/8+2/3)=5/6*19/24=95/144

b: =3/4(7/5-1/2)=27/40

c: =35/24*2/3=35/36

12,5+2,6=15,1

37,81-23,5=14,31

4,2x1,4=5,88

17,55:3=5,85

12,5+2,6=15,1

37,81-23,5=14,31

4,2x1,4=5,88

17,55:3=5,85

tách nhỏ ra

\(\dfrac{6}{8}-\dfrac{2}{7}=\dfrac{42}{56}-\dfrac{16}{56}=\dfrac{26}{56}=\dfrac{13}{28}\)

\(=-7\cdot\left[16+\left(-36\right):\left(-9\right)\right]+125=-77\cdot20+125=-140+125=-15\)

\(-7.\left[\left(-2\right)^4+\left(-36\right):\left(-3\right)^2\right]-\left(-5\right)^3\\ =-7.\left[16+\left(-36\right):9\right]+125\\ =-7.\left[16+\left(-4\right)\right]+125\\ =-7.12+125\\ =-84+125\\ =41\)