160 - (2³ . 5² - 6 . 25)

= 160 - (8 . 25 - 6 . 25

= 160 . [ 25 . (8-6) ]

= 160 . 50

= 8000

\(160-\left[2^3.5^2-6.25\right]\)

\(=160-\left[8.25-6.25\right]\)

\(=160-\left[25.\left(8-6\right)\right]\)

\(=160-\left[25.2\right]\)

\(=160-50\)

\(=110\)

 a. \(160 - \left( {{2^3}{{.5}^2} - 6.25} \right)\)

\(\begin{array}{l} = 160 - \left( {8.25 - 6.25} \right)\\ = 160 - 25.\left( {8 - 6} \right)\\ = 160 - 25.2\\ = 160 - 50\\ = 110\end{array}\)

Ta có: 110 = 2.5.11

b. \(37.3 + 225:{15^2}\)

\(\begin{array}{l} = 37.3 + 225:225\\ = 37.3 + 1\\ = 111 + 1\\ = 112\end{array}\)

Ta có: \(112 = 2^4.7\)

c. \(5871:103 - 64:{2^5}\)

\(\begin{array}{l} = 5871:103 - 64:32\\ = 57 - 2 = 55\end{array}\)

Ta có: 55 = 5. 11

d. \(\left( {1 + 2 + 3 + 4 + 5 + 6 + 7 + 8} \right){.5^2} - 850:2\)

\(\begin{array}{l} = \left[ {\left( {1 + 8} \right) + \left( {2 + 7} \right) + \left( {3 + 6} \right) + \left( {4 + 5} \right)} \right]{.5^2} - 850:2\\ = \left( {9 + 9 + 9 + 9} \right){.5^2} - 850:2\\ = {9.4.5^2} - 850:2\\ = {36.5^2} - 425\\ = {36.5^2} - {5^2}.17\\ = {5^2}.\left( {36 - 17} \right)\\ = {5^2}.19=475\end{array}\)

Ta có: \(475 = 5^2.19\)

a: \(160-\left(2^3\cdot5^2-6\cdot25\right)\)

\(=160-\left(8\cdot25-150\right)\)

\(=160-200+150=10=2\cdot5\)

b: \(=111+225:225=112=2^4\cdot7\)

c: \(=57-64:32=57-2=55=5\cdot11\)

d: \(=\left(9\cdot\dfrac{8}{2}\right)\cdot25-425=36\cdot25-425=25=5^2\)

\(160-\left(2^3.5^3-6.25\right)\)

\(=160-8.125+6.25\)

\(=160-1000+150\)

\(=210-1000\)

\(=-790\)

160-(2^3.5^3-6.25)

= 160 - ( 8.125.150 )

= 160 - 150000

= - 149840

160-(2^3.5^3-6.25)

= 160 - ( 8. 125 - 150)

= 160 - ( 1000 - 150)

= 160 - 850

= -690

160-(2³.5²-6.25)

=160-(8*25-6*25)

=160-25*(8-6)

=160-25*2

=160-50

=110

Phân tích ra thừa số nguyên tố là:2x5x11

\(=\)\(\frac{2^{12}.5^7+2^{12}.5^6}{2^{15}.5^6+2^{12}.5^6}\)

\(=\)\(\frac{2^{12}.5^6.\left(1+5\right)}{2^{12}.5^6.\left(2^3+1\right)}\)

\(=\)\(\frac{6}{9}\)\(=\)\(\frac{2}{3}\)

chúc học tốt

0,5555897934

\(\frac{2^{12}\cdot5^7+4^6\cdot25^3}{8^5\cdot25^3+\left(2^2\cdot5\right)^6}\)

\(=\frac{2^{12}.5^7+2^{12}\cdot5^6}{2^{15}\cdot5^6+2^{12}\cdot5^6}\)

\(=\frac{2^{12}\cdot5^6\cdot\left(1\cdot5+1\right)}{2^{12}\cdot5^6\cdot\left(2^3\cdot1+1\right)}\)

\(=\frac{6}{9}\)

\(=\frac{2}{3}\)

\(\frac{2^{12}.5^7+4^6.25^3}{8^5.25^3+\left(2^2.5\right)^6}=\frac{2^{12}.5^7+\left(2^2\right)^6.\left(5^2\right)^3}{\left(2^3\right)^5.\left(5^2\right)^3+\left(2^2\right)^6.5^6}=\frac{2^{12}.5^7+2^{12}.5^6}{2^{15}.5^6+2^{12}.5^6}\)

                                 \(=\frac{2^{12}.5^6.\left(5+1\right)}{2^{12}.5^6.\left(2^3+1\right)}=\frac{6}{9}=\frac{2}{3}\)

56+7.(-5)+(-9).(-2)

\(\text{56+ 7. (-5)+ (-9). (-2)}\)

\(=56+\left(-35\right)+18\)

\(=39\)

học tốt

\(56+7.\left(-5\right)+\left(-9\right).\left(-2\right)\)

\(=56+\left(-35\right)+18\)

\(=39\)

chúc bạn học tốt!