\(=\dfrac{5^4\cdot5^4\cdot2^8}{5^{10}\cdot2^{10}}=\dfrac{1}{5^2}\cdot\dfrac{1}{2^2}=\dfrac{1}{100}\)

\(\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.4^4.5^4}{5^{10}.4^5}=\frac{5^8.4^4}{5^8.5^2.4^4.4}=\frac{1}{25.4}=\frac{1}{100}\)

a) \(A=\frac{5^4.20^4}{25^5.4^5}=\frac{5^4.\left(2^2.5\right)^4}{5^{2^5}.\left(2^2\right)^5}=\frac{5^8.2^8}{5^{10}.2^{10}}=\frac{1}{\left(5^{10}:5^8\right).\left(2^{10}:2^8\right)}=\frac{1}{5^2.2^2}=\frac{1}{25.4}=\frac{1}{100}\)

b) \(B=\frac{2^{30}.5^7+2^{13}.5^{27}}{2^{27}.5^7+2^{10}.5^{27}}\)\(=\frac{2^3+2^3}{1}=\frac{8+8}{1}=16\)

c) \(C=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...........+\frac{1}{2^{100}}\)

\(\Rightarrow2C=1+\frac{1}{2}+\frac{1}{2^2}+..........+\frac{1}{2^{99}}\)

\(\Rightarrow2C-C=\left(1+\frac{1}{2}+\frac{1}{2^2}+.........+\frac{1}{2^{99}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...........+\frac{1}{2^{100}}\right)\)

\(\Rightarrow C=1-\frac{1}{2^{100}}\)

d) \(D=1+\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+.........+\frac{1}{5^{100}}\)

\(\Rightarrow5D=5+1+\frac{1}{5^2}+\frac{1}{5^3}+...........+\frac{1}{5^{101}}\)

\(\Rightarrow5D-D=\left(5+1+\frac{1}{5^2}+\frac{1}{5^3}+.........+\frac{1}{5^{101}}\right)-\left(1+\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+..........+\frac{1}{5^{100}}\right)\)

\(\Rightarrow4D=5-\frac{1}{5^{101}}\)

\(\Rightarrow D=\frac{5-\frac{1}{5^{101}}}{4}\)

a) \(A=\frac{5^4x20^4}{25^5x4^5}=\frac{5^4x\left(2^2x5\right)^4}{\left(5^2\right)^5x\left(2^2\right)^5}=\frac{5^8.2^8}{5^{10}.2^{10}}=\frac{1}{5^2x2^2}=\frac{1}{25.4}=\frac{1}{100}\)

b) \(B=\frac{2^{30}x5^7+2^{13}x5^{27}}{2^{27}x5^7+2^{10}x5^{27}}=\frac{2^{13}.5^7.\left(2^{17}+5^{20}\right)}{2^{10}.5^7.\left(2^{17}+5^{20}\right)}=2^3=8\)

c) \(C=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{100}}\)

\(\Rightarrow2C=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{99}}\)

\(\Rightarrow2C-C=1-\frac{1}{2^{100}}\)

\(C=1-\frac{1}{2^{100}}\)

phần d bn lm tương tự như phần c nha!
 

Có bn nào lm giùm mik cách khác cho câu D được không?

Lời giải:

\(\frac{4}{9}\times \frac{3}{7}\times \frac{7}{4}=\frac{1}{3}\)

\(\frac{6}{5}\times \frac{4}{5}\times \frac{25}{16}=\frac{3}{2}\)

\(\frac{7}{8}\times \frac{16}{9}\times \frac{3}{14}=\frac{1}{3}\)

27 x 3 + 36 : 4 : 3 x 5 - 25 : 5 x 4

= 81 + 36: 4 : 3 x 5 - 5 x 4

= 81 + 9 : 3 - 20

= 81 + 3 - 20

= 84 - 20

= 64

27 x 3 + 36 : 4 : 3 x 5 - 25 : 5 x 4

= 81 + 36: 4 : 3 x 5 - 5 x 4

= 81 + 9 : 3 - 20

= 81 + 3 - 20

= 84 - 20

= 64

a) (100-4)*20-15+25:5                                                              

=94*20-15+5

=1880-30

=1850

b) 100-(4*20)-15+25:5

=100-80-15+5

=10

Nhớ k cho mình nha bạn !

4/5x3/7+4/5+6/7x6/7-4/5x4/14

= ( 3/7 + 6/7 + 4/14) x 4/5 

= 11/7 x 4/5 

= 44/35

44/35

4/5x3/7+4/5+6/7x6/7-4/5x4/14 ⇒ ( 3/7 + 6/7 + 4/14) x 4/5 ⇒ 11/7 x 4/5 ⇒ 44/35

vvvvvvvvvvvvvvvv

8/13+4/9+1/3+5/13+3=

(8/13+5/13)+(4/9+3/9)+3=

1+7/9+3=4 7/9

8/5x4/7+4/7x2/5=

4/7x(8/5+2/5)

=4/7x2=8/7

a) kết quả bằng  43/9

b) hiện tại chưa tính ra

\(a,\dfrac{7}{9}\times\dfrac{3}{14}:\dfrac{5}{8}=\dfrac{7}{9}\times\dfrac{3}{14}\times\dfrac{8}{5}=\dfrac{4}{15}\)

\(b,\dfrac{3}{5}\times\dfrac{4}{21}\times\dfrac{25}{3}=\dfrac{20}{21}\)

\(c,\dfrac{15}{16}:\dfrac{5}{8}\times\dfrac{3}{4}=\dfrac{15}{16}\times\dfrac{8}{5}\times\dfrac{3}{4}=\dfrac{9}{8}\)

\(d,\dfrac{21}{4}\times\dfrac{16}{14}\times\dfrac{1}{2}\times\dfrac{8}{3}=8\)