1) 2Fe + 6H₂SO₄ --> Fe₂(SO₄)₃ + 3SO₂ + 6H₂O

2) 4Mg + 5H₂SO₄ --> 4MgSO₄ + H₂S + 4H₂O

3) 8Al + 30HNO₃ --> 8Al(NO₃)₃ + 3NH₄NO₃ + 9H₂O

4) Mg + 4HNO₃ --> Mg(NO₃)₂ + 2NO₂ + 2H₂O

5) 3Zn + 8HNO₃ --> 3Zn(NO₃)₂ + 2NO + 4H₂O

6) 2P + 5H₂SO₄ --> 2H₃PO₄ + 5SO₂ + 2H₂O

7) S + 2HNO₃ --> H₂SO₄ + 2NO

8) 3H₂S + 4HClO₃ --> 4HCl + 3H₂SO₄

9) 8Fe + 30HNO₃ --> 8Fe(NO₃)₃ + 3N₂O + 15H₂O

10) 5Cu + 12HNO₃ --> 5Cu(NO₃)₂ + N₂ + 6H₂O

5:

a: =>2x+3=3+2căn 2

=>2x=2căn 2

=>x=căn 2

b: =>10+căn 3x=10+4căn 6

=>căn 3x=4căn 6=căn 96

=>3x=96

=>x=32

c: =>3x-2=7-4căn 3

=>3x=9-4căn 3

=>x=3-4/3*căn 3

a: =>\(2\cdot\sqrt{x-5}+\sqrt{x-5}-\sqrt{x-5}=4\)

=>2*căn x-5=4

=>căn x-5=2

=>x-5=4

=>x=9

\(=\dfrac{2^{19}\cdot3^9\cdot5+2^{18}\cdot3^9\cdot5}{2^{19}\cdot3^9-2^{20}\cdot3^{10}}\)

\(=\dfrac{2^{18}\cdot3^9\cdot5\left(2+1\right)}{2^{19}\cdot3^9\left(1-2\cdot3\right)}=\dfrac{1}{2}\cdot\dfrac{5\cdot3}{-5}=-\dfrac{3}{2}\)

\(A=\dfrac{2^{19}\cdot27^3\cdot5-15\cdot\left(-4\right)^9\cdot9^4}{6^9\cdot2^{10}-\left(-12\right)^{10}}\)

\(A=\dfrac{2^{19}\cdot\left(3^3\right)^3\cdot5-3\cdot5\cdot-\left(2^2\right)^9\cdot\left(3^2\right)^4}{2^9\cdot3^9\cdot2^{10}-\left(2^2\right)^{10}\cdot3^{10}}\)

\(A=\dfrac{2^{19}\cdot3^9\cdot5+3^9\cdot2^{18}\cdot5}{2^{19}\cdot3^9-2^{20}\cdot3^{10}}\)

\(A=\dfrac{2^{18}\cdot3^9\cdot5\cdot\left(2+1\right)}{2^{19}\cdot3^9\cdot\left(1-2\cdot3\right)}\)

\(A=\dfrac{1\cdot1\cdot5\cdot3}{2\cdot1\cdot-5}\)

\(A=-\dfrac{1}{2}\cdot3\)

\(A=-\dfrac{3}{2}\)

mở bài là giới thiệu về cụ nha mn em viết lộn ạ 

thân bài là đóng góp ạ