a)(19x+2.52)/14=(18-8)2-42
b)2.3x=10.312+8.274
Tìm số tự nhiên x biết
a) (19x + 2.52):14 = (13 – 8)2 – 42
b) 2.3x = 10.312 + 8.274
help meeeeeeeeeeee
a, ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42
( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 16
( 19x + 2.52 ) : 14 = 52 - 16
( 19x + 2.52 ) : 14 = 25 - 16
( 19x + 2.52 ) : 14 = 9
( 19x + 2.25 ) : 14 = 9
( 19x + 2.25 ) = 9 . 14
( 19x + 2.25 ) = 126
( 19x + 50 ) = 126
19x = 126 - 50
19x = 76
x = 76 : 19
x = 4
Vậy x = 4
b, 2 . 3x = 10 . 312 + 8 . 274
2 . 3x = 10 . 274 + 8 . 274
2 . 3x = 274 . ( 10+8 )
2 . 3x = 274 . 18
2 . 3x = 9565938
3x = 9565938 : 2
3x = 4782969
3x = 314
=> x = 14
Vậy x = 14
Đây nha bạn!!!
Chúc bạn học tốt!!!
a, ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42
( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 16
( 19x + 2.52 ) : 14 = 52 - 16
( 19x + 2.52 ) : 14 = 25 - 16
( 19x + 2.52 ) : 14 = 9
( 19x + 2.25 ) : 14 = 9
( 19x + 2.25 ) = 9 . 14
( 19x + 2.25 ) = 126
( 19x + 50 ) = 126
19x = 126 - 50
19x = 76
x = 76 : 19
x = 4
Vậy x = 4
b, 2 . 3x = 10 . 312 + 8 . 274
2 . 3x = 10 . 274 + 8 . 274
2 . 3x = 274 . ( 10+8 )
2 . 3x = 274 . 18
2 . 3x = 9565938
3x = 9565938 : 2
3x = 4782969
3x = 314
=> x = 14
Vậy x = 14
Tìm số tự nhiên x biết
a) (19x + 2.52):14 = (13 – 8)2 – 42
b) 2.3x = 10.312 + 8.27
ai rảnh giúp mk với nhé
a) \(\left(19x-2.52\right):14=\left(13-8\right).2-42\)
\(\left(19x-50\right):14=10-42\)
\(\left(19x-50\right):14=-32\)
\(19x-50=-448\)
\(19x=-398\)
\(x=-\dfrac{398}{19}\)
2.3x=10.312+8.274
\(2.3^x=10.3^{12}+8.\left(3^3\right)^4\)
\(2.3^x=10.3^{12}+8.3^{12}\)
\(2.3^x=3^{12}.\left(10+8\right)\)
\(2.3^x=3^{12}.18\)
\(3^x=3^{12}.18:2\)
\(3^x=3^{12}.9\)
\(3^x=3^{12}.3^2\)
\(3^x=3^{14}\)
\(\Rightarrow x=14\)
2.3x=10.312+8.274
2.3x=10.312+23.312
2.3x=312.18
2.3x=312.32.2
2.3x=314.2
=>x=14
2.3x =10.312 +8.274
tìm x
\(\Rightarrow6x=5312\)
\(\Rightarrow x=5312:6\)
\(\Rightarrow x=885,3333333\)
tíc nha
\(2.3x=10.312+8.274\)
\(=2.3x=3120+2192\)
\(2.3x=5312\)
\(3x=5312:2\)
\(3x=2656\)
\(x=2656:3\)
\(x=\frac{2556}{3}\)
2.3x=10.312+ 8.274
làm giùm mình với ạ mình đang cần gấp
\(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)
\(\Rightarrow2\cdot3^x=10\cdot3^{12}+8\cdot\left(3^3\right)^4\)
\(\Rightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}\)
\(\Rightarrow2\cdot3^x=18\cdot3^{12}\)
\(\Rightarrow3^x=\dfrac{18\cdot3^{12}}{2}\)
\(\Rightarrow3^x=9\cdot3^{12}\)
\(\Rightarrow3^x=3^2\cdot3^{12}\)
\(\Rightarrow3^x=3^{14}\)
\(\Rightarrow x=14\)
BT1 : Tìm x biết :
a, (7x - 11)3 = 25.52 + 200
b, 720 : (41 - ( 2x - 5 )) = 23.5
c, 2.3x = 10.312 + 8.274
Bài 1: Tìm x
a) Ta có: \(\left(7x-11\right)^3=2^5\cdot5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=32\cdot25+200=1000\)
\(\Leftrightarrow7x-11=10\)
\(\Leftrightarrow7x=21\)
hay x=3
Vậy: x=3
b) Ta có: \(720:\left(41-\left(2x-5\right)\right)=2^3\cdot5\)
\(\Leftrightarrow720:\left(41-2x+5\right)=8\cdot5=40\)
\(\Leftrightarrow-2x+46=18\)
\(\Leftrightarrow-2x=18-46=-28\)
hay x=14
Vậy: x=14
c) Ta có: \(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)
\(\Leftrightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}\)
\(\Leftrightarrow2\cdot3^x=18\cdot3^{12}\)
\(\Leftrightarrow3^x=\dfrac{18\cdot3^{12}}{2}=9\cdot3^{12}\)
\(\Leftrightarrow3^x=3^2\cdot3^{12}=3^{14}\)
hay x=14
Vậy: x=14
A (7x-11)3=25.52+200
(7x-11)3=800+200
(7x-11)3=1000
(7x-11)3=103
7x-11=10
7x=10+11
7x=21
x=21:7
x=3
B 720:(41-(2x-5))=23.5
720:(41-(2x-5))=40
41-(2x-5)=720:40
41-(2x-5)=18
2x-5=41-18
2x-5=23
2x=23+5
2x=28
x=28:2
x=14
C 2.3x=10.312+8.274
2.3x=10.312+8.(33.4)
2.3x=10.312+8.312
2.3x=312.(10+8)
2.3x=312.18
3x=( 312.18):2
3x=312.9
3x=312 .32
3x=314
3x=14
x=14
( 19x + 2.52 ) : 14= (13 - 8)2 - 4 tìm x
\(...\Rightarrow\left(19x+50\right):14=5^2-4\Rightarrow\left(19x+50\right):14=21\Rightarrow\left(19x+50\right)=21.14\)
\(\Rightarrow19x+50=294\Rightarrow19x=244\Rightarrow x=\dfrac{244}{19}\)
Tìm x
(19x+2.52) :14= (13-8)2 - 42
\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=5^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=9\)
\(\Rightarrow19x+50=126\)
\(\Rightarrow19x=76\)
\(\Rightarrow x=4\)
Vậy x = 4
#Kễnh
a) 3+2x-1 = 24 - [ 42-(22-1) ]
b) (19x+2.52):14 = (13-8)2-42
a) 3+2x-1 = 24 - [ 42-(22-1) ]
b) (19x+2.52):14 = (13-8)2 - 42
\(a,\Rightarrow2^{x-1}=24-\left(16-3\right)-3\\ \Rightarrow2^{x-1}=24-13-3\\ \Rightarrow2^{x-1}=8=2^3\\ \Rightarrow x-1=3\Rightarrow x=4\\ b,\Rightarrow\left(19x+50\right):14=25-16=9\\ \Rightarrow19x+50=126\\ \Rightarrow x=4\)