A

A

A nha 

There are many ways to keep our body fit. There are a lot of activities to do. You can ride bike, go jogging, skipping, or some other activities. You need to do exercises that can help you gain sweat. Moreover, you can also have a healthy diet. A healthy diet is really important. If you give in your body a large amount of fat, that can make your body bigger. Besides, don't eat to much sweets and fast foods. That doesn't let you to losing weight, moreover you can gain weight. So in my opinion, we need to exercise recently and have a good diet each day. That can make your body fit!

1.

⇒ He doesn't work as hard as me

⇒ He is lazier than me.

2. 

⇒ Your bedroom is more uncomforable than my bedroom.

⇒ Your bedroom is not as comfortable as my bedroom.

3. 

⇒ Mary speaks English better than John.

⇒ Mary doesn't speak English as worse as John.

4. No boy in my class are as intelligent as Jack.

5. They suggest that he should play football.

1. -> He doesn't work as hard as me.

    -> He works lazier than me.

2. -> Your bedroom isn't as comfortable as mine.

    -> Your bedroom is uncomfortable than mine.

3. -> Mary speaks English better than John.

   -> Mary doesn't speak English as bad as John.

4. -> No boy is as intelligent as Jack in my class.

5. -> They suggest playing football. 

Bài 5: 

\(A=2A-A=2^2+2^3+...+2^{107}-2-2^2-...-2^{2016}=2^{107}-2\)

\(2\left(A+2\right)=2^{2x}\\ \Rightarrow2\left(2^{107}-2+2\right)=2^{2x}\\ \Rightarrow2^{108}=2^{2x}\\ \Rightarrow2x=108\\ \Rightarrow x=54\)

Bài 3:

Gọi số học sinh lớp 7A, 7B lần lượt là a,b

Ta có: \(\left\{{}\begin{matrix}\dfrac{x}{8}=\dfrac{y}{9}\\y-x=5\end{matrix}\right.\)

Áp dụng TCDTSBN ta có:

\(\dfrac{x}{8}=\dfrac{y}{9}=\dfrac{y-x}{9-1}=\dfrac{5}{1}=5\)

\(\dfrac{x}{8}=5\Rightarrow x=40\\ \dfrac{y}{9}=5\Rightarrow y=45\)

Vậy số học sinh lớp 7A, 7B lần lượt là 40, 45 học sinh

Giúp mik trl nốt bài 1 và bài 4 vs ạ

\(M=\sqrt{\dfrac{4}{\left(2-\sqrt{5}\right)^2}}-\sqrt{\dfrac{4}{\left(2+\sqrt{5}\right)^2}}=\dfrac{2}{\left|2-\sqrt{5}\right|}-\dfrac{2}{\left|2+\sqrt{5}\right|}\)

\(=\dfrac{2}{\sqrt{5}-2}-\dfrac{2}{\sqrt{5}+2}=\dfrac{2\left(\sqrt{5}+2\right)-2\left(\sqrt{5}-2\right)}{\left(\sqrt{5}-2\right)\left(\sqrt{5}+2\right)}\)

\(=\dfrac{8}{1}=8\)

Lm ơn giúp mik đii mà mik bt ơn bn đó nhiều lắm . Mik đang rất cần

Lần sau có đăng em tách nhỏ ra nhé! Mong mấy bạn thấy bài này giúp bạn ấy nhanh chóng hoàn thành, các em chia nhau ra làm giúp bạn nha! ^^

Ta có: MN là đường trung bình

nên MN//CD

mà CD\(\perp\)AH

nên AH\(\perp\)MN

Ta có:MN là đường trung bình của ΔACD

⇒MN//CD

mà AH⊥CD(đường cao AH)

⇒AH⊥MN