\(\dfrac{17}{22}+x=6\)

         \(x=6-\dfrac{17}{22}\)

         \(x=\dfrac{115}{22}\)

x=6-17/22

x=115/22

\(\dfrac{17}{22}+x=6\)

         \(x=6-\dfrac{17}{22}\)

         \(x=\dfrac{115}{22}\)

a: =152,3+7,7+2021,19-2021,19

=160

b: =7/15*3/14*20/13

\(=\dfrac{7}{14}\cdot\dfrac{3}{15}\cdot\dfrac{20}{13}=\dfrac{1}{2}\cdot\dfrac{1}{5}\cdot\dfrac{20}{13}=\dfrac{2}{13}\)

c: \(=\dfrac{7}{4}\left(\dfrac{13}{12}-\dfrac{10}{12}\right)+\dfrac{5}{6}=\dfrac{7}{16}+\dfrac{5}{6}=\dfrac{61}{48}\)

A.3

`3/7xx14/5+32/5xx3/7+3/7xx9/5`

`=3/7xx(14/5+32/5+9/5)`

`=3/7xx55/5`

`=3/7xx5`

`=15/7`

\(=\frac{3}{7}\times[\frac{14}{5}+\frac{32}{5}+\frac{9}{5}]=\frac{3}{7}\times\frac{55}{5}=\frac{3}{7}\times11=\frac{33}{7}\)

\(x-\dfrac{5}{7}=\dfrac{3}{5}.\dfrac{1}{2}\)

\(x-\dfrac{5}{7}=\dfrac{3}{10}\)
\(x=\dfrac{3}{10}+\dfrac{5}{7}=\dfrac{71}{70}\)

\(x-\dfrac{5}{7}=\dfrac{3}{5}\times\dfrac{1}{2}\)

\(x-\dfrac{5}{7}=\dfrac{3}{10}\)

\(x=\dfrac{3}{10}+\dfrac{5}{7}\)

\(x=\dfrac{71}{10}\)

X-5/7=3/5 x 1/2

x - 5/7 = 3/10

x = 3/10   +5/7

x = 71/70

mng giúp với

\(\Leftrightarrow7x\left(x+5\right)+\left(x-5\right)\left(x+5\right)=0\\ \Leftrightarrow\left(x-5\right)\left(7x+x+5\right)=0\\ \Leftrightarrow\left(x-5\right)\left(8x+5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=-\dfrac{5}{8}\end{matrix}\right.\)

\(\Leftrightarrow x^2+x-5x-5-x^2-6x-9-6=0\\ \Leftrightarrow-10x-20=0\\ \Leftrightarrow x=-2\)

a: \(\Leftrightarrow5x=20\)

hay x=4

b: \(\Leftrightarrow x+7=24\)

hay x=17

1) \(5x-7=13\Rightarrow5x=13+7=20\Rightarrow x=20:5=4\)

2) \(\Rightarrow3\left(x+7\right)=95-23=72\)

\(\Rightarrow x+7=72:3=24\Rightarrow x=24-7=17\)

3) \(\Rightarrow2x+27=343\Rightarrow2x=343-27=316\Rightarrow x=316:2=158\)

+) 5x-7=13

5x=13+7

5x=20

x=20:5

x=4

+) 95-3(x+7)=23

3(x+7)=95-23

3(x+7)=72

x+7=72:3

x+7=24

x=24-7

x=17

+) 2x+3\(^2\).3=7\(^5\):7\(^2\)

2x+3\(^3\)=7\(^3\)

2x+27=343

2x=343-27

2x=316

x=316:2

x=158

( x + 3 ) ²  - 3 = 6

( x + 3 ) ²       = 6 + 3 

( x + 3 ) ²       = 9  

=> ( x + 3 ) ² = 3 ² hoặc ( x + 3 ) ² = ( -3 )²

=> x + 3 = 3 hoặc x + 3 = - 3

          x  = 3 - 3          x  = -3 - 3

          x  = 0               x  = -6

Vậy x = 0 hoặc x = -6

(x + 3\(^2\))  - 3 = 6

                    x = 6 + 3 - 3\(^2\)

                    x = 9 - 9

                    x = 0

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\(a,7^{x+3}< 343\\ \Rightarrow7^{x+3}< 7^3\\ \Leftrightarrow x+3< 3\\ \Leftrightarrow x< 0\\ b,\left(\dfrac{1}{4}\right)^x\ge3\\ \Leftrightarrow x\le log_{\dfrac{1}{4}}3\)