Help me
4x :17 = 0
7x - 8 = 713
8(x - 3) = 0
Đặt tính rồi tính:
75318 + 7138 62970 - 5958 2405 x 9 6592 : 8
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7.x-x=5 mũ 21:5 mũ 19 +3 . 2 mũ 2 - 7 mũ 0
7x-2x=6 mũ 17 . 6 mũ 15 + 44 :11
Nghiệm của hệ phương trình 3 y − 5 + 2 x − 3 = 0 7 x − 4 + 3 x + y − 1 − 14 = 0 là (x; y).
Tính x 2 + y 2 .
A. 8
B. 34
C. 21
D. 24
Ta có 3 y − 5 + 2 x − 3 = 0 7 x − 4 + 3 x + y − 1 − 14 = 0 ⇔ 3 y − 15 + 2 x − 6 = 0 7 x − 28 + 3 x + 37 − 3 − 14 = 0 ⇔ 2 x + 3 y = 21 10 x + 3 y = 45
⇔ 3 y = 21 − 2 x 10 x + 21 − 2 x = 45 ⇔ 3 y = 21 − 2 x 8 x = 24 ⇔ x = 3 3 y = 15 ⇔ x = 3 y = 5
Vậy hệ phương trình có nghiệm duy nhất (x; y) = (3; 5)
⇒ x 2 + y 2 = 32 + 52 = 34
Đáp án: B
Đặt tính rồi tính:
21567 + 42385 ; 89205 – 63582 ; 7138 x 6 ; 64974 : 2
Tìm số tự nhiên x, biết:
a) x : 13 = 41; b) 1428 : x = 14; c) 4x : 17 = 0;
d) 7x - 8 = 713; e) 8(x - 3) = 0; g) 0 : x = 0.
help me pleas !!!
a) \(x:13=41\) .
\(\Rightarrow x=41.13=533\)
b) \(1428:x=14\)
\(\Rightarrow x=1428:14=102\)
c) \(4x:17=0\)
\(\Rightarrow4x=0\)
\(\Rightarrow x=0\)
d) \(7x-8=713\)
\(7x=721\)
\(\Rightarrow x=103\)
e) \(8\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
g) \(0:x=0\)
\(\Rightarrow x\in R\)
Tìm số nguyên x , biết :
a ) x-(17-8)=5+(10-3x)
b) 25-(30+x) = x-(27-8)
c) lx+5l = 7
d) x . (x-1)=0
HELP ME
a. x - (17 - 8) = 5 + (10 - 3x)
x - 9 = 5 + 10 - 3x
x - 9 = 15 - 3x
x + 3x = 15 + 9
4x = 24
x = 24 : 4
x = 6
b. 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 19
-5 - x = x - 19
-5 + 19 = x + x
14 = 2x
14 : 2 = x
7 = x
c. |x + 5| = 7
\(\Rightarrow\left\{\begin{matrix}x+5=7\\-\left(x+5\right)=7\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=2\\-x-5=7\end{matrix}\right.\)
\(\Rightarrow\left\{\begin{matrix}x=2\\x=-12\end{matrix}\right.\)
d. x(x - 1) = 0
\(\Rightarrow\left\{\begin{matrix}x=0\\x-1=0\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=0\\x=1\end{matrix}\right.\)
a) x-(17-8)=5+(10-3x)
x-9=5+10-3x
x-9=15-3x
x+3x=15+9
4x=24
x=6
4.x:17=0 ; 7.x-8=713 ; 8.(x-3)=0 . mong moi nguoi giup do :))
4.x:17= 0
4.x=0:17
4.x=0
x=0:4
x=0
7.x-8=713
7.x=713+8
7.x=721
x=721:7=103
x-3=0:8
x.3=0
x=0:3
x=0
Tìm x, biết:
a) 3/(x+2)(x+5) + 5/(x+5)(x+10) + 7/ (x+10)(x+7) = x/(x+2)(x+17) với x thuộc {-2,-5,-10,-17}
b) 2/(x-1)(x-3 + 5/(x-3)(x-8) + 12/(x-8)(x-20) -1/x-20 =-3/4 với x thuộc {1,3,8,,20}
HELP ME!!!!
a: \(\Leftrightarrow\dfrac{1}{x+2}-\dfrac{1}{x+5}+\dfrac{1}{x+5}-\dfrac{1}{x+10}+\dfrac{1}{x+10}-\dfrac{1}{x+17}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
=>\(\dfrac{x+17-x-2}{\left(x+2\right)\left(x+17\right)}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
=>x=15
b: \(\Leftrightarrow-\dfrac{1}{x-1}+\dfrac{1}{x-3}-\dfrac{1}{x-3}+\dfrac{1}{x-8}-\dfrac{1}{x-8}+\dfrac{1}{x-20}-\dfrac{1}{x-20}=\dfrac{-3}{4}\)
=>1/x-1=3/4
=>x-1=4/3
=>x=7/3
4x :17=0
7x -8=713
8(x-3)=0
0 :x=0
4x :17=0
4x=0x17
4x=0
x=0:4
x=0
7x -8=713
7x=713+8
7x=721
x=721:7
x=103
8(x-3)=0
(x-3)=0:8
(x-3)=0
x=0+3
x=3
0:x=0
x=0:0
x=0;1;2;3;4;5;6;7...
\(4x:17=0\) \(7x-8=713\) \(8\left(x-3\right)=0\)
\(4x=0\) \(7x=721\) \(x-3=0\)
\(x=0\) \(x=103\) \(x=3\)
\(0:x=0\)
\(x=0\)