b) Ta có: \(\dfrac{x-2}{4}=\dfrac{2x+1}{3}\)

\(\Leftrightarrow3\left(x-2\right)=4\left(2x+1\right)\)

\(\Leftrightarrow3x-6=8x+4\)

\(\Leftrightarrow3x-8x=4+6\)

\(\Leftrightarrow-5x=10\)

hay x=-2

Vậy: x=-2

a) x³-9x²-4x-36=0

⇔ x²(x-9)-4(x-9)=0

⇔ (x-9)(x²-4)=0

⇒ Xảy ra 2 trường hợp:

- TH1: x-9=0 ⇔ x=9

- TH2: x²-4=0 ⇔ x=2 hoặc x=-2

Vậy x=9 hoặc x=2 hoặc x=-2.

a)3(x-2)+2(x-3)=5

=>3x-6+2x-6=5

=>5x=17

=>x=17/5

b)(2x-8)^2=16

TH1:2x-8=4=>x=6

TH2:2x-8=-4=>x=2

\(a,\Leftrightarrow3x-6+2x-6=5\\ \Leftrightarrow5x-12=5\\ \Leftrightarrow x=\dfrac{17}{5}\\ b,\left(2x-8\right)^2-16=0\\ \Leftrightarrow\left(2x-12\right)\left(2x-4\right)=0\\ \Leftrightarrow4\left(x-6\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=6\\x=2\end{matrix}\right.\\ c,\Leftrightarrow4x^2-4x+1-4x^2+11x+3=3\\ \Leftrightarrow7x=-1\\ \Leftrightarrow x=-\dfrac{1}{7}\)

`@` `\text {Ans}`

`\downarrow`

`a)`

`3x ( 12x - 4 ) - 9x( 4x - 3 ) = 30`

`=> 3x (12x-4) - 3*3x (4x - 3) = 30`

`=> 3x [12x - 4 - 3(4x-3)] = 30`

`=> 3x (12x - 4 - 12x + 9) = 30`

`=> 3x (-4+9)=30`

`=> 3x*5=30`

`=> 3x=6`

`=> x=2`

Vậy, `x=2`

`b)`

`x( 5 - 2x) + 2x( x - 1)`

`=> x(5-2x) + 2x^2 - 2x=15`

`=> 5x - 2x^2 + 2x^2 - 2x =15`

`=> 3x = 15`

`=> x=5`

Vậy, `x=5.`

a: =>36x^2-12x-36x^2+27x=30

=>15x=30

=>x=2

b: =>5x-2x^2+2x^2-2x=15

=>3x=15

=>x=5

a) \(2^x:4=16\\ \Rightarrow2^x=64\\ \Rightarrow2^x=2^6\\ \Rightarrow x=6\)

b) \(4^{x-3}=256\\ \Rightarrow4^{x-3}=4^4\\ \Rightarrow x-3=4\\ \Rightarrow x=7\)

c) \(\left(2x+1\right)^3=343\\ \Rightarrow\left(2x+1\right)^3=7^3\\ \Rightarrow2x+1=7\\ \Rightarrow x=3\)

d) \(10+2x=4^5:4^3\\ \Rightarrow10+2x=16\\ \Rightarrow x=3\)

a,2^x:4=16            

2^x=16.4=64

2^x=2^6

=>x=6

b,4^x-3=256

4^x-3=4^4

=>x-3=4

x=4+3=7

c,(2x+1)^3=343

(2x+1)^3=7^3

=>2x+1=7

2x=7-1=6

x=6:2=3

d,10+2x=4^5:4^3

10+2x=4^2=16

2x=16-10=6

x=6:2=3

vc đăng bài giống nhau ạ

a, 2^x : 4 = 16

⇒ 2^x : 2² = 2⁴

⇒ x - 2 = 4

⇒ x       = 6

b, 4^x-3 = 256 

⇒ 4^{x - 3} =  4⁴

⇒ x - 3 = 4

⇒ x       = 7

c, (2x + 1)³ = 343

⇒ (2x + 1)³ = 7³

⇒  2x + 1 = 7

⇒ 2x        = 6

⇒ x          = 3

d, 10 + 2x = 4⁵ : 4³

⇒ 10 + 2x = 16

⇒          2x = 6

⇒             x = 3

3.4x-2+4x-1+4x=92

4x(3+1+1)-2-1=92

4x.5-2-1=92

4x.5 =92+1+2

4x.5 =95

4x  =95:5

4x   =19 

3.4x-2+4x-1+4x=92

4x(3+1+1)-2-1=92

4x.5-2-1=92

4x.5 =92+1+2

4x.5 =95

4x  =95:5

4x   =19 

đây em nhé

\(3\cdot4^{x-2}+4^{x-1}+4^x=92\)

\(4^{x-2}\left(3+4+4^2\right)=92\)

\(4^{x-2}\cdot23=92\)

\(4^{x-2}=4\)

\(x-2=1\)

\(x=3\)

a: =>8x^2-20x+20x-50+4x(4x^2-12x+9)=0

=>8x^2-50+8x^3-48x^2+36x=0

=>8x^3-40x^2+36x-50=0

=>\(x\simeq4,29\)

b: =>(2x-3-3x-1)(2x-3+3x+1)=0

=>(-x-4)(5x-2)=0

=>x=2/5 hoặc x=-4

`c)1/4x+2/5=7/5`

`=>1/4x=7/5-1/5=1`

`=>x=1:1/4=4`

Vậy `x=4` 

`a)2x-2/3=-3/4`

`=>2x=-3/4+2/3=-1/12`

`=>x=-1/24`

Vậy `x=-1/24`

`b)x:3/4+1/4=-2/3`

`=>x:3/4=-2/3-1/4=-11/4`

`=>x=-11/4 xx 3/4=-33/16`

Vậy `x=-33/16`