=> cái vế  trong ngoặc là 0.

rồi bạn làm tiếp nha

\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)

\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)

\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)

\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)

\(\dfrac{3}{4}-x=\dfrac{91}{66}\)

\(x=\dfrac{-83}{132}\)

a: Ta có: \(-\dfrac{12}{25}\cdot\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)

\(\Leftrightarrow x+\dfrac{83}{132}=0\)

hay \(x=-\dfrac{83}{132}\)

<=> x = 9/22 + 3/11 = 9/22 + 6/22 = 15/22 

x-3/11=9/22

       x =9/22+6/22

        x=15/22

x = 9/22 + 3/11 = 9/22 + 6/22 = 15/22 

`A)15/9=(5 xx 3)/(3 xx 3)=5/3`

`60/(-96)=(5 xx 12)/(12 xx (-8))=-5/8`

`=>5/3=15/9`

Ta thấy trừ cặp `5/3=15/9` thì còn lại không bằng nhau.

`B)60/(-85)=(5 xx 12)/(5 xx (-17))=-12/17`

`-77/56=(7 xx (-11))/(8 xx 7)=-11/8`

`=>-12/17=60/(-85)`

Ta thấy trừ cặp `-12/17=60/(-85)` thì còn lại không bằng nhau.

a) \(\dfrac{15}{9}=\dfrac{5}{3}\)

b) \(-\dfrac{12}{17}=\dfrac{60}{-85}\)

???

a: 12/5:x=11/5

=>x=12/5:11/5=12/5*5/11=11/12

b: 5:x=9/3

=>5:x=3

=>x=5/3

12/5:x=11/5

       X=12/5:11/5

        X=12/11

5:x=9/3 

   X=5:9/3

   X=5/3

a, 5/252

b, 11/90

a)\(=>x=\dfrac{5}{9}:\dfrac{4}{7}=\dfrac{35}{36}\)

b)\(=>x=\dfrac{11}{15}:\dfrac{2}{3}=\dfrac{11}{10}\)

a) \(\dfrac{4}{7}\times x=\dfrac{5}{9}\)

           \(x=\dfrac{5}{9}\div\dfrac{4}{7}\)

          \(x=\dfrac{5}{9}\times\dfrac{7}{4}\)

          \(x=\dfrac{35}{35}\)

b) \(\dfrac{11}{15}\div x=\dfrac{2}{3}\)

     \(x=\dfrac{11}{15}\div\dfrac{2}{3}\)

     \(x=\dfrac{11}{15}\times\dfrac{3}{2}\)

     \(x=\dfrac{33}{30}\)

     \(x=\dfrac{11}{10}\)

\(\dfrac{x}{10}=\dfrac{-3}{5}\\ \Rightarrow x=\dfrac{10.\left(-3\right)}{5}=-6\\ ------------\\ x+\dfrac{5}{12}=\dfrac{-2}{3}\\ x=\dfrac{-2}{3}-\dfrac{5}{12}\\ x=\dfrac{-8}{12}-\dfrac{5}{12}\\ x=\dfrac{-13}{12}\)

`x`=`-6`

`x` = `-13/12`

x/10=-3/5

x/10=-3.2/5.2

x/10=-6/10

x=-6

x+5/12=-2/3

x=-2/3-5/12

x=8/12-5/12

x=3/12

x=1/4

Tom Gọi Minh khi hôm đến

Để cho Minh micro N phone