5-1+4=8

9+3-7=5

40:8x5=25

6x4:8=3

Chúc em học giỏi nha!!!

K cho chị vs nhé cao nữ minh trang

5-1+4=8

9+3-7=13

40:8x5=25

6x4:8=3

k nha

5 - 1 + 4 = 8

9 + 3 - 7 = 5

40 : 8 x 5 = 25

6 x 4 : 8 = 3

a) 8x⁵ : 4x³ = (8 : 4) . (x⁵ : x³) = 2.x²

b) 120x⁷ : (-24x⁵) = [120 : (-24)] . (x⁷ : x⁵) = -5.x²

c) \(\dfrac{3}{4}{( - x)^3}:\dfrac{1}{8}x = \dfrac{{ - 3}}{4}{x^3}:\dfrac{1}{8}x = \left( {\dfrac{{ - 3}}{4}:\dfrac{1}{8}} \right).({x^3}:x) =  - 6{x^2}\)

d) -3,72x⁴ : (-4x²) = [(-3,72) : (-4)] . (x⁴ : x²) = 0,93x²

\(\frac{7}{8}+\frac{1}{8}\times\frac{3}{8}+\frac{1}{8}\times\frac{5}{8}=\frac{7}{8}+\frac{1}{8}\times\left(\frac{3}{8}+\frac{5}{8}\right)=\frac{7}{8}+\frac{1}{8}\times1\)

\(=\frac{7}{8}+\frac{1}{8}=1\)

=1/8 x ( 7/8 +5/8)

= ...

ban tu lam not nha

       Bài làm :

Ta có :

\(\frac{7}{8}+\frac{1}{8}\times\frac{3}{8}+\frac{1}{8}\times\frac{5}{8}\)

\(=\frac{7}{8}+\frac{1}{8}\times\left(\frac{3}{8}+\frac{5}{8}\right)\)

\(=\frac{7}{8}+\frac{1}{8}\times\frac{8}{8}\)

\(=\frac{7}{8}+\frac{1}{8}\times1\)

\(=\frac{8}{8}=1\)

\(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+\frac{17}{8}\)

= \(\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)

= \(\frac{-5}{8}.\frac{12}{12}+\frac{17}{8}\)

`-5/8xx5/12+5/8xx(-7/12)+17/8`

`=5/8xx(-5/12)+5/8xx(-7/12)+17/8`

`=5/8xx(-5/12-7/12)+17/8`

`=5/8xx(-12)/12+17/8`

`=5/8xx(-1)+17/8`

`=-5/8+17/8`

`=12/8=3/2`

\(-\dfrac{5}{8}\cdot\dfrac{5}{12}+\dfrac{5}{8}\cdot\left(-\dfrac{7}{12}\right)+\dfrac{17}{8}\)
\(=-\dfrac{5}{8}\cdot\dfrac{5}{12}+-\dfrac{5}{8}\cdot\dfrac{7}{12}+\dfrac{17}{8}\)
\(=-\dfrac{5}{8}\left(\dfrac{5}{12}+\dfrac{7}{12}\right)+\dfrac{17}{8}\)
\(=-\dfrac{5}{8}\cdot1+\dfrac{17}{8}\)
\(=-\dfrac{5}{8}+\dfrac{17}{8}\)
\(=\dfrac{12}{8}=\dfrac{3}{2}\)

Cảm ơn hai bn(⌒▽⌒)🥰🥰🥰

a, \(P\left(x\right)=5x^5-4x^2+7x+1;Q\left(x\right)=5x^5-4x^2+3x+8\)

b, \(P\left(x\right)+Q\left(x\right)=10x^5-8x^2+10x+9\)

c, \(P\left(x\right)=Q\left(x\right)\Rightarrow7x+1=3x+8\Leftrightarrow4x=7\Leftrightarrow x=\dfrac{7}{4}\)

a/ \(P\left(x\right)=8x^5+7x-6x^2-3x^5+2x^2+1\)

\(=8x^5-3x^5-6x^2+2x^2+7x+1\)

\(=5x^5-4x^2+7x+1\)

\(Q\left(x\right)=4x^5+3x-2x^2+x^5-2x^2+8\)

\(=4x^5+x^5-2x^2-2x^2+3x+8\)

\(=5x^5-4x^2+3x+8\)

b/ \(P\left(x\right)=5x^5-4x^2+7x+1\)

+  \(Q\left(x\right)=5x^5-4x^2+3x+8\)

____________________________

\(P\left(x\right)+Q\left(x\right)=10x^5-8x^2+10x+9\)

c/ \(P\left(x\right)=Q\left(x\right)\)

\(\Rightarrow5x^5-4x^2+7x+1=5x^5-4x^2+3x+8\)

\(\Rightarrow7x+1=3x+8\)

\(\Rightarrow4x-7=0\)

\(\Rightarrow x=\dfrac{7}{4}\)

Bạn nên viết đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để mn hiểu đề của bạn hơn nhé.

= -13 tick dùm cái nha.

sao lớp ba mà học số âm rồi

\(\frac{8}{5}\) x \(\frac{5}{3}=\frac{8x5}{5x3}=\frac{40}{15}=\frac{8}{3}\)

bằng 40/15 nha

\(\frac{8}{5}x\frac{5}{3}=\frac{8x5}{5x3}=\frac{40}{15}=\frac{8}{3}\)