A=1/2=3/6

B=2/3=4/6

cách làm bạn à

\(A=\dfrac{3469-54}{6938-108}\)

\(A=\dfrac{3415}{6830}\)

\(A=\dfrac{3415}{6830}=\dfrac{3415:3415}{6830:3415}=\dfrac{1}{2}=\dfrac{3}{6}\)

\(B=\dfrac{2468-98}{3702-147}\)

\(B=\dfrac{2370}{3555}\)

\(B=\dfrac{2370}{3555}=\dfrac{2370:1185}{3555:1185}=\dfrac{2}{3}=\dfrac{4}{6}\)

Dấu '/' đọc là phần nha! <3

A= 3469 - 54 / 6938 -108 = 3469 -54 / 2*(1234 -49) = 1/2

B= 2468 - 98 / 3702 - 147 = 2*(1234-49) / 3*(1234-49) =2/3

Sau khi rút gọn p/s ta đc: 1/2 và 2/3 => MC=6

Rồi quy đồng nha bạn 

KQ: 3/6 và 4/6

Ta có: \(A=\dfrac{3469-54}{6938-108}\)

\(=\dfrac{3469-54}{2\left(3469-54\right)}=\dfrac{1}{2}\)

\(=\dfrac{3}{6}\)

Ta có: \(B=\dfrac{2468-98}{3702-147}\)

\(=\dfrac{2\left(1234-49\right)}{3\left(1234-49\right)}=\dfrac{2}{3}\)

\(=\dfrac{4}{6}\)

\(\frac{3469-54}{6928-108}=\frac{3469-54}{2.\left(3469-54\right)}=\frac{1}{2}\)

\(\frac{2468-98}{3702-147}=\frac{2\left(1234-49\right)}{3\left(1234-49\right)}=\frac{2}{3}\)

A = \(\frac{3469-54}{6938-108}\)

= \(\frac{3469-54}{2\left(3469-54\right)}\)

= \(\frac{1}{2}\)

B = \(\frac{2468-98}{3702-147}\)

= \(\frac{2\left(1234-49\right)}{3\left(1234-49\right)}\)

= \(\frac{2}{3}\)

BCNN(2,3) = 6

\(\frac{1}{2}=\frac{1.3}{2.3}=\frac{3}{6}\)

\(\frac{2}{3}=\frac{2.2}{3.2}=\frac{4}{6}\)

\(A=\frac{3469-54}{6938-108}=\frac{3469-54}{3469.2-54.2}=\frac{3469-54}{2.\left(3469-54\right)}=\frac{1}{2}=\frac{1.3}{2.3}=\frac{3}{6}\)

\(B=\frac{2468-98}{3702-147}=\frac{1234.2-49.2}{1234.3-49.3}=\frac{2.\left(1234-49\right)}{3.\left(1234-49\right)}=\frac{2}{3}=\frac{2.2}{3.2}=\frac{4}{6}\)

A=3469-54/6938-108=3469-54/2*(3469-54)=1/2

B=2468-98/3702-147=2*(1234-49)/3*(1234-49)=2/3

quy đồng:1/2=3/6 ;2/3=4/6 .

mình không viết được phân số như bạn nhưng mong bạn thông cảm

Rút gọn phân số:

C=\(\dfrac{3469-54}{6938-108}=\dfrac{3415}{6830}=\dfrac{3415\div3415}{6830\div3415}=\dfrac{1}{2}\)

D=\(\dfrac{2468-98}{3702-147}=\dfrac{2370}{3555}=\dfrac{2370\div1185}{3555\div1185}=\dfrac{2}{3}\)

Ta có: C=

\(\dfrac{3469-54}{6938-108}=\dfrac{3469-54}{2.3469-2.54}=\dfrac{3469-54}{2.\left(3469-54\right)}=\dfrac{1}{2}\)

D=\(\dfrac{2468-98}{3702-147}\)=\(\dfrac{2.1234-2.49}{3.1234-3.49}=\dfrac{2.\left(1234-49\right)}{3.\left(1234-49\right)}=\dfrac{2}{3}\)

Ta có: C=\(\dfrac{1}{2}=\dfrac{3}{6}\)

D=\(\dfrac{2}{3}=\dfrac{4}{6}\)

Vì \(\dfrac{3}{6}< \dfrac{4}{6}\)

\(\Rightarrow C< D\)

\(A=\frac{3469-54}{6938-108}\)

\(=\frac{3415}{6830}\)

\(=\frac{3415}{6830}=\frac{3415:3415}{6830:3415}=\frac{1}{2}=\frac{3}{6}\)

\(B=\frac{2468-89}{3720-147}\)

\(=\frac{2370}{3555}\)

\(=\frac{2370}{3555}=\frac{2370:1185}{3555:1185}=\frac{2}{3}=\frac{4}{6}\)

bn ơi còn C,D