Rút gọn phân số:
C=\(\dfrac{3469-54}{6938-108}=\dfrac{3415}{6830}=\dfrac{3415\div3415}{6830\div3415}=\dfrac{1}{2}\)
D=\(\dfrac{2468-98}{3702-147}=\dfrac{2370}{3555}=\dfrac{2370\div1185}{3555\div1185}=\dfrac{2}{3}\)
Ta có: C=
\(\dfrac{3469-54}{6938-108}=\dfrac{3469-54}{2.3469-2.54}=\dfrac{3469-54}{2.\left(3469-54\right)}=\dfrac{1}{2}\)
D=\(\dfrac{2468-98}{3702-147}\)=\(\dfrac{2.1234-2.49}{3.1234-3.49}=\dfrac{2.\left(1234-49\right)}{3.\left(1234-49\right)}=\dfrac{2}{3}\)
Ta có: C=\(\dfrac{1}{2}=\dfrac{3}{6}\)
D=\(\dfrac{2}{3}=\dfrac{4}{6}\)
Vì \(\dfrac{3}{6}< \dfrac{4}{6}\)
\(\Rightarrow C< D\)
