\(\frac{56-x}{34}=\frac{144}{96}=\frac{3}{2}\)

\(\Rightarrow\left(56-x\right)2=34\cdot3=102\)

\(\Rightarrow56-x=102\div2\)

\(\Rightarrow56-x=51\)

\(\Rightarrow x=56-51\)

\(\Rightarrow x=5\)

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34=3706\)

\(\Rightarrow x=3706\div2\)

\(\Rightarrow x=1853\)

\(56-\frac{x}{34}=\frac{144}{96}=\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=56-\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34=3706\)

\(\Rightarrow x=3706\div2=1853\)

giả giúp mình nhé

Sửa đề xí nha:

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{3706}{34}\Rightarrow x=3706\)

◥ὦɧ◤ŤŔầŃ VăŃ ĤùŃĞ™​ sai đáp số rồi kìa

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{56\cdot2-3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34\)

\(\Rightarrow2x=3706\)

\(\Rightarrow x=3706:2=1853\)

Vậy x = 1853

X/34 = 56 - 144/96

X/34 = 109/2

X/34 = 3706/34

=> X= 3706

X/34 = 56 - 144/96

X/34=109/2

X/34 = 3706/34

=>x=3706

x là 1853

         x/34 = 56 - 144/96

         x/34 = 109/2

         x/34 = 1853/34

=> x = 1853

X/34=56-144/96

x/34=109/2

x=109x34:2=1853

\(\frac{56-x}{34}=\frac{144}{96}\)

\(=\frac{56-x}{34}=\frac{3}{2}\)

\(=\frac{56-x}{34}=\frac{51}{34}\)

\(\Rightarrow56-x=51\)

\(=-x=51-56\)

\(\Rightarrow x=5\)

x bang 2

56-x.96=34.144

1/109

2/1.6029411764705882352941176470588

1/ 109

1/109 nha bạn

 x= 56 *96 / 34 * 144

x=5376/4896

5 nha e

giúp mik k lun nhé cả cách làm và đáp số

a) \(96-7\left(x+1\right)=14^4:14^3\)

\(\Rightarrow96-7\left(x+1\right)=14^{4-3}\)

\(\Rightarrow96-7\left(x+1\right)=14\)

\(\Rightarrow7\left(x+1\right)=96-14\)

\(\Rightarrow7\left(x+1\right)=82\)

\(\Rightarrow x+1=\dfrac{82}{7}\)

\(\Rightarrow x=\dfrac{82}{7}-1\)

\(\Rightarrow x=\dfrac{75}{7}\)

b) \(\left(5x+3^4\right)\cdot2^4=2^6\cdot7^2\)

\(\Rightarrow5x\cdot2^4+3^4\cdot2^4=2^6\cdot7^2\)

\(\Rightarrow5x\cdot2^4+6^4=\left(2^3\cdot7\right)^2\)

\(\Rightarrow80x+1296=3136\)

\(\Rightarrow80x=1840\)

\(\Rightarrow x=\dfrac{1840}{80}\)

\(\Rightarrow x=23\)

a: =>96-7(x+1)=14

=>7(x+1)=82

=>x+1=82/7

=>x=75/7

b =>5x+81=2^2*7^2=196

=>5x=115

=>x=23

a) \(96-7\left(x+1\right)=14^4:14^3\\ \Leftrightarrow96-7\left(x+1\right)=14\\ \Leftrightarrow7\left(x+1\right)=82\\ \Leftrightarrow x+1=\dfrac{82}{7}\\ \Leftrightarrow x=\dfrac{75}{7}\)

b) \(\left(5x+3^4\right)\cdot2^4=2^6\cdot7^2\\\Leftrightarrow5x+81=196\\ \Leftrightarrow5x=115\\ \Leftrightarrow x=23 \)

Tìm x biết : 144 chia hết cho x; 96 chia hết cho x và x<16

Giải: Theo bài ra ta có:

Vì 144 chia hết cho x mà 96 cũng chia hết cho x nên x\(\in\)ƯC(144,96)

Vì x<16 nên x\(\in\){-48,-24,-16,-12,-8,-6,-4,-3,-2,-1,1,2,3,4,6,8,12}

Vậy.......................................................