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a: =(6x)^2-(3x-2)^2

=(6x-3x+2)(6x+3x-2)

=(9x-2)(3x+2)

d: \(=\left[\left(x+1\right)^2-\left(x-1\right)^2\right]\left[\left(x+1\right)^2+\left(x-1\right)^2\right]\)

\(=4x\cdot\left[x^2+2x+1+x^2-2x+1\right]\)

=8x(x^2+1)

e: =(4x)^2-2*4x*3y+(3y)^2

=(4x-3y)^2

f: \(=-\left(\dfrac{1}{4}x^4-2\cdot\dfrac{1}{2}x^2\cdot2y^3+4y^6\right)\)

\(=-\left(\dfrac{1}{2}x^2-2y^3\right)^2\)

g: =(4x)^3+1^3

=(4x+1)(16x^2-4x+1)

k: =x^3(27x^3-8)

=x^3(3x-2)(9x^2+6x+4)

l: =(x^3-y^3)(x^3+y^3)

=(x-y)(x+y)(x^2-xy+y^2)(x^2+xy+y^2)

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\(\dfrac{3}{4}.x+125\)%\(=-4\)

\(\Rightarrow\dfrac{3}{4}.x+\dfrac{125}{100}=-4\)

\(\Rightarrow\dfrac{3}{4}.x+\dfrac{5}{4}=-4\)

\(\Rightarrow\dfrac{3}{4}.x=\left(-4\right)-\dfrac{5}{4}\)

\(\Rightarrow\dfrac{3}{4}.x=-\dfrac{21}{4}\)

\(\Rightarrow x=-\dfrac{21}{4}:\dfrac{3}{4}\)

\(\Rightarrow x=-\dfrac{21}{4}.\dfrac{4}{3}\)

\(\Rightarrow x=-7\)

Vậy \(x\) = -7

\(4\cdot2^x-3=125\)
\(\Rightarrow4\cdot2^x=125+3\)
\(\Rightarrow4\cdot2^x=128\)
\(\Rightarrow2^x=128:4\)
\(\Rightarrow2^x=32\)
\(\Rightarrow x=5\)

\(\Leftrightarrow4.2^x=125+3=128\)

\(\Leftrightarrow2^x=128:4=32\)

\(\Rightarrow x=5\)

các bạn cho mik hỏi sao tự nhiên 2^x = 32 xong x = 5 v

(75% + 0,65 + 1/4 + 35% ) x ( 5/4 + 125 x 3 + 12 x 0,625 )

=( \(\frac{3}{4}+0,65+\frac{1}{4}+3,5\) ) x ( \(\frac{5}{4}+125\)x 3 + 7,5 )

= ( 1 + 4,15 ) x ( \(\frac{5}{4}\) + 375 + 7,5 )

= 5,15 x 383,75

= 1976,3125

thank you dương tiến dũng  nhiều nha . hihihi