\(b,=x^4-2x^3-x^3+2x^2+3x^2-6x-3x+6\\ =\left(x-2\right)\left(x^3-x^2+3x-3\right)\\ =\left(x-2\right)\left(x-1\right)\left(x^2+3\right)\\ c,=x^4-2x^3+4x^3-8x^2+4x^2-8x+3x-6\\ =\left(x-2\right)\left(x^3+4x^2+4x+3\right)\\ =\left(x-2\right)\left(x^3+3x^2+x^2+3x+x+3\right)\\ =\left(x-2\right)\left(x+3\right)\left(x^2+x+1\right)\)

b) 3x⁴-3x³+9x³-9x²-24x²+24x-48x+48

=3x³(x-1)+9x²(x-1)-24x(x-1)-48(x-1)

=(x-1)(3x³+9x²-24x-48)

=3(x-1)(x³+3x²-8x-16)

a: \(12x^3-6x^2+3x\)

\(=3x\cdot4x^2-3x\cdot2x+3x\cdot1\)

\(=3x\left(4x^2-2x+1\right)\)

b: \(\dfrac{2}{5}x^2+5x^3+x^2y\)

\(=x^2\cdot\dfrac{2}{5}+x^2\cdot5x+x^2\cdot y\)

\(=x^2\left(\dfrac{2}{5}+5x+y\right)\)

c: \(14x^2y-21xy^2+28x^2y^2\)

\(=7xy\cdot2x-7xy\cdot3y+7xy\cdot4xy\)

\(=7xy\left(2x-3y+4xy\right)\)

3x² + 10x +3

=> 3x² + 9x +x +3

=> (3x² +x )+ ( 9x +3)

=> x(3x +1) +3( 3x+1)

=>(3x+1) (x+3)

Tự làm tiếp nhé

a, ta có: 3x^2 +10x+3= 3x^2 + 9x +x +3 = 3x(x+3)+(x+3)=(x+3)+(3x+1)

2 câu còn lại đang trong qtrinhf suy nghĩ

a) \(3x^2+10x+3=3x^2+9x+x+3\)

\(=3x\left(x+3\right)+\left(x+3\right)\)

\(=\left(x+3\right)\left(3x+1\right)\)

b)\(5x^2+14x-3=5x^2+15x-x-3\)

\(=5x\left(x+3\right)-\left(x+3\right)\)

\(=\left(5x-1\right)\left(x+3\right)\)

c)\(6x^2+7x-3=6x^2+9x-2x-3\)

\(=3x\left(2x+3\right)-\left(2x+3\right)\)

\(=\left(3x-1\right)\left(2x+3\right)\)

a) bạn ktra lại đề nhé

b)  \(3x^4+7x^3+8x^2+9x+15\)

\(=\left(3x^4-2x^3+5x^2\right)+\left(9x^3-6x^2+15x\right)+\left(9x^2-6x+15\right)\)

\(=x^2\left(3x^2-2x+5\right)+3x\left(3x^2-2x+5\right)+3\left(3x^2-2x+5\right)\)

\(=\left(x^2+3x+3\right)\left(3x^2-2x+5\right)\)

\(4x^2+8xy-3x-6y=4x\left(x+2y\right)-3\left(x+2y\right)=\left(4x-3\right)\left(x+2y\right)\)

\(x^4y-3x^3y^2+3x^2y^3-xy^4=xy\left(x^3-3x^2y+3xy^2-y^3\right)=xy\left(x-y\right)^3\)

\(x^3-5x^2-14x=x\left(x^2-5x-14\right)=x\left(x^2-7x+2x-14\right)=x\left[x\left(x-7\right)+2\left(x-7\right)\right]=x\left(x-7\right)\left(x+2\right)\)

\(x^4+4y^4=\left(x^2\right)^2+2\times x^2\times2y^2+\left(2y^2\right)^2-4x^2y^2=\left(x^2+2y^2\right)^2-\left(2xy\right)^2=\left(x^2-2xy+2y^2\right)\left(x^2+2xy+2y^2\right)\)

KO LÀM ĐC

vào cốc cốc math cứ thế ấn, nó sẽ ra nghiệm

 <=>\(\left(5x-2\right)\left(x^2-2x+2\right)\)

`a)7x^3y^2+14x^2y^3+7xy^4`

`=7xy^2(x^2+2xy+y^2)`

`=7xy^2(x+y)^2`

______________________________________________

`b)x^2-xy+5x-5y`

`=x(x-y)+5(x-y)`

`=(x-y)(x+5)`

______________________________________________

`c)3x^2-6xy-12+3y^2`

`=3(x^2-2xy-4+y^2)`

`=3[(x-y)^2-4]`

`=3(x-y-2)(x-y+2)`

a)7x³y²+14x²y³+7xy⁴

=7xy²(x²+2xy+y²)

=7xy²(x+y)²

b)x²-xy + 5x - 5y

=x(x-y) + 5(x-y)

=(x-y) (x+5)

p

\(3x^3-14x^2+4x+3\)

\(=\left(3x^3-15x^2+9x\right)+\left(x^2-5x+3\right)\)

\(=3x\left(x^2-5x+3\right)+\left(x^2-5x+3\right)\)

\(=\left(3x+1\right)\left(x^2-5x+3\right)\)

3x^3 - 14x^2 + 4x + 3
= (3x^3+x^2) - 15^2- 5x+ 9x+ 3
= x^2(3x+1)- 5x(3x+1)+ 3(3x+1)
= (x^2- 5x+ 3)(3x+1)