X.(2/3)^3=(2/3)^5

=>X = (2/3)^5 : (2/3)^3

=>X=(2/3)^2

|X| - 0.5 = 2

=> |X| = 2.5

=> X  = {-2.5 ; 2.5}

X/3 = 4/6

<=>6:3=4:X

<=>4:X =2

=> X = 4 : 2 = 2

CÁM ƠN MAY QUÁ CÓ BN CỨU KỊP THỜI 

ính bằng cách thuận tiện nhất:

0.5 x 17 x 5 + 0.25 x 520 + 31 x 2.5

=>2,5x17+2.5x52+2,5x31

=2,5(17+52+31)

=2,5x100

=250

\(0,5\times17\times5\times0,25\times520+31\times2,5\)

\(\Rightarrow2,5\times17+2,5\times52+2,5\times31\)

\(\Rightarrow2,5\times\left(17+52+31\right)\)

\(\Rightarrow2,5\times100\)

\(\Rightarrow2500\)

\(\frac{85}{2}\)+ 130+ \(\frac{155}{2}\)

\(\frac{85}{2}\)+\(\frac{260}{2}\)+\(\frac{155}{2}\)

250

x : 1 + x : 0,5 + x : 0,25 + x : 0,125 = 60

=> \(x+x:\frac{5}{10}+x:\frac{25}{100}+x:\frac{125}{1000}=60\)

=> \(x+x\cdot\frac{10}{5}+x\cdot\frac{100}{25}+x\cdot\frac{1000}{125}=60\)

=> \(x+x\cdot2+x\cdot4+x\cdot8=60\)

=> x(1 + 2 + 4 + 8) = 60

=> x.15 = 60

=> x = 4

Bài làm

\(x:1+x:0,5+x:0,25+x:0,125=60\)

\(x:1+x:\frac{5}{10}+x:\frac{25}{100}+x:\frac{125}{1000}=60\)

\(x:\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)=60\)

\(x:\left(\frac{8}{8}+\frac{4}{8}+\frac{2}{8}+\frac{1}{8}\right)=60\)

\(x:\frac{15}{8}=60\)

\(x=60x\frac{15}{8}\)

\(x=112,5\)

Vậy \(x=112,5\)

x:1 + x:0,5 + x:0,25 + x:0,125 =60
=>x + x:(1/2) + x:(1/4) + x:(1/8) = 60
=>x + x.(2/1) + x.(4/1) + x.(8/1) =60
=>x + 2x + 4x + 8x = 60
=>15x = 60
=>x = 60/5 = 4

\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)\(\frac{1}{5}\)

\(3x-\frac{3}{2}-5x-\frac{15}{5}=-x+\frac{1}{5}\)

\(\left(3x-5x\right)-\left(\frac{3}{2}+3\right)=-x+\frac{1}{5}\)                                        

tu lam tiep di nhe

Jenifer giups mk nha

`x/2+x+x/3+x+x+x/4=5 3/4`

`=>3x+x/2+x/3+x/4=23/4`

`=>49/12x=23/4`

`=>x=69/49`

Vậy `x=69/49`

giúp mik với xin các bạn đó mik đnag cần gấp

Soạn đề bằng thanh công cụ cho rõ nha bạn

\(\Leftrightarrow-\dfrac{2}{5}\left(4x-3\right)^2=-\dfrac{5}{18}\)

\(\Leftrightarrow\left(4x-3\right)^2=\dfrac{25}{36}\)

\(\Leftrightarrow4x-3\in\left\{\dfrac{5}{6};-\dfrac{5}{6}\right\}\)

hay \(x\in\left\{\dfrac{23}{24};\dfrac{13}{24}\right\}\)

a) \(x+215=480\)

\(x=480-215\)

\(x=265\)

b) \(725-x=185:5\)

\(725-x=37\)

\(x=725-37\)

\(x=688\)

c) \(x\times\dfrac{1}{3}+x\times\dfrac{4}{3}=\dfrac{2}{3}\)

\(x\times\left(\dfrac{1}{3}+\dfrac{4}{3}\right)=\dfrac{2}{3}\)

\(x\times\dfrac{5}{3}=\dfrac{2}{3}\)

\(x=\dfrac{2}{3}:\dfrac{5}{3}=\dfrac{2}{3}\times\dfrac{3}{5}\)

\(x=\dfrac{2}{5}\)

d) \(\left(\dfrac{13}{5}+\dfrac{2}{3}\right):x=5\)

\(\dfrac{49}{15}:x=5\)

\(x=\dfrac{49}{15}:5=\dfrac{49}{15}\times\dfrac{1}{5}\)

\(x=\dfrac{49}{75}\)

a)x + 215 = 480 

x = 480 - 215 

x = 265 

b) 725 - x = 185 : 5 

    725 - x = 37

              x = 725 - 37 

             x = 688

c, \(x\) \(\times\) \(\dfrac{1}{3}\) + \(x\) \(\times\) \(\dfrac{4}{3}\) = \(\dfrac{2}{3}\)

    \(x\) \(\times\)( \(\dfrac{1}{3}\) + \(\dfrac{4}{3}\)) = \(\dfrac{2}{3}\)

    \(x\) \(\times\) \(\dfrac{5}{3}\)          = \(\dfrac{2}{3}\)

    \(x\)                  = \(\dfrac{2}{3}\) : \(\dfrac{5}{3}\)

    \(x\)                  = \(\dfrac{2}{5}\)

d, (\(\dfrac{13}{5}\) + \(\dfrac{2}{3}\)) : \(x\) = 5

     \(\dfrac{49}{15}\) : \(x\)        = 5

             \(x\)           = \(\dfrac{49}{15}\) : 5

              \(x\)         = \(\dfrac{49}{75}\)

\(\dfrac{3}{5}x-\dfrac{3}{5}+x=5\)

\(\Rightarrow\dfrac{3}{5}x+x-\dfrac{3}{5}=5\)

\(\Rightarrow\dfrac{8}{5}x=5+\dfrac{3}{5}\)

\(\Rightarrow\dfrac{8}{5}x=\dfrac{28}{5}\)

\(\Rightarrow x=\dfrac{28}{5}:\dfrac{8}{5}\)

\(\Rightarrow x=\dfrac{28}{5}.\dfrac{5}{8}\)

\(\Rightarrow x=\dfrac{7}{2}\)

 3/5 x ( X - 1 ) + X = 5 

 (X + 1) + X = 5 - 3/5 

  X + 1 + X = 22/5

 2X + 1 = 22/5 

= 2X = 22/5 - 1

 2X = 17/5 

 X = 17/5 : 2 

 X = 17/10