`x/2+x+x/3+x+x+x/4=5 3/4`
`=>3x+x/2+x/3+x/4=23/4`
`=>49/12x=23/4`
`=>x=69/49`
Vậy `x=69/49`
giúp mik với xin các bạn đó mik đnag cần gấp
Soạn đề bằng thanh công cụ cho rõ nha bạn
Ta có: \(\dfrac{x}{2}+\dfrac{x+x}{3}+\dfrac{x+x+x}{4}=5\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{1}{2}x+\dfrac{2}{3}x+\dfrac{3}{4}x=\dfrac{23}{4}\)
\(\Leftrightarrow\dfrac{23}{12}x=\dfrac{23}{4}\)
hay x=3
Vậy: x=3
Giải:
\(\dfrac{x}{2}+x+\dfrac{x}{3}+x+x+\dfrac{x}{4}=5\dfrac{3}{4}\)
\(x.\left(\dfrac{1}{2}+1+\dfrac{1}{3}+1+1+\dfrac{1}{4}\right)=\dfrac{23}{4}\)
\(x.\dfrac{49}{12}=\dfrac{23}{4}\)
\(x=\dfrac{23}{4}:\dfrac{49}{12}\)
\(x=\dfrac{69}{49}\)
