tim x,y biet:36-y mu 2=8(x-2021) mu 2
tim x y thuoc z biet x mu 2 cong y nhan x cong y mu 2 bang x mu hai nhan y mu hai
tim x y nguyen biet
x mu2 +y mu 2-z mu 2+z+1=2(x+y-xy)
tim so tu nhien x , biet
a, 5x - x = 29 - 36 : 4
b, ( 3x - 48 ) . 6 = 3 mu 3 . 2 mu 2 + 2 mu 3 . 3 mu 2 - 12 mu 2
c, x thuoc B(6) va 22 < x < hoac = 36
a) \(\Leftrightarrow4x=20\Leftrightarrow x=5\)
b) \(\Leftrightarrow18x-288=27.4+8.9-144\)
\(\Leftrightarrow18x=108+72-144+288=324\)
\(\Leftrightarrow x=18\)
c)Ta có:
\(x\in B\left(6\right)\) và \(22< x\le36\)
mà \(B\left(6\right)=\left\{0;6;12;18;24;30;36;42;48;...\right\}\)
\(\Rightarrow x\in\left\{0;6;12;18;24;30;36;42;48;...\right\}\) và \(22< x\le36\)
\(\Rightarrow x\in\left\{24;30;36\right\}\)
Vậy \(x\in\left\{24;30;36\right\}\)
Tim so nguyen x,y biet
a) (x+5) mu 2 + (2y - 8 ) mu 2 = 0
b)(x + 3).(2y - 1 ) = 5
a: \(\left(x+5\right)^2>=0\forall x\)
\(\left(2y-8\right)^2>=0\forall y\)
Do đó: \(\left(x+5\right)^2+\left(2y-8\right)^2>=0\forall x,y\)
Dấu '=' xảy ra khi \(\left\{{}\begin{matrix}x+5=0\\2y-8=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x=-5\\y=4\end{matrix}\right.\)
b: \(\left(x+3\right)\left(2y-1\right)=5\)
=>\(\left(x+3\right)\left(2y-1\right)=1\cdot5=5\cdot1=\left(-1\right)\cdot\left(-5\right)=\left(-5\right)\cdot\left(-1\right)\)
=>\(\left(x+3;2y-1\right)\in\left\{\left(1;5\right);\left(5;1\right);\left(-1;-5\right);\left(-5;-1\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(-2;3\right);\left(2;1\right);\left(-4;-2\right);\left(-8;0\right)\right\}\)
x mu 2 - 3x + 2 = 6
Tim cac so tu nhien x,y biet
\(x^2-3x+2=6\Rightarrow x^2-2x-x+2=6\Rightarrow x\left(x-2\right)-\left(x-2\right)=6\)
\(\Rightarrow\left(x-1\right)\left(x-2\right)=6\) Vì x-1>x-2 nên ta có bảng:
x-1 | -1 | -2 | 6 | 3 |
x-2 | -6 | -3 | 1 | 2 |
x | 0 và 4(loại) | -1(TM) | 7 và 3 | 4(TM) |
Vậy x\(\in\left\{-1,1\right\}\)
2 - 3x + 2 = 6
\(\Rightarrow\)2 - 3x = 6 - 2
\(\Rightarrow\)2 - 3x = 4
\(\Rightarrow\)3x = 4 + 2
\(\Rightarrow\)3x = 6
\(\Rightarrow\)x = 6 : 3
\(\Rightarrow\)x = 2
vậy x = 2
Tim x,y la so nguyen
a) 2x-3y+5= xy
b) x mu 2 +2xy+2x+4y
B2 Tim x,y la so nguyen to
x mu 2 -2y mu 2 =1
B3 Tim so tu nhienx,y
7 .(x-2004) mu 2 = 23- y mu 2
cho A= 2x mu 2-10xy+2016y mu 2+y va B=5x mu 2-7xy+2016y mu 2+7y-2016.tim C biet A+C=B
tim x biet
2 mu x x 2 x 3 mu x +1
1) tim x thuoc n biet:
a) 3 mu 4 - x = 81
b) 5 mu x -1 = 125
c) (2 - x) mu 3=27 mu 0
d)3 mu x + 2 -3 mu x +1=182
e) 2 mu x -1 -2 mu x =16
3 mũ 4-x=81 là viết như này hả bn
\(3^{4-x}=81\) hay viết như này \(3^4-x=81\)
Hoang Thi Thanh Tra
viet nhu cai thu nhat