Tính nhanh : H= (2004*2015 + 2016*10 +2005) / (2015*2020 - 2004*2005)
Những câu hỏi liên quan
CMR 1/10.(2017^2016^2015-2003^2004^2005) là một số tự nhiên
Cho \(\left(2x_1-3y_1\right)^{2004}+\left(2x_2-3y_2\right)^{2004}+...+\left(2x_{2015}-3y_{2015}\right)^{2004}\)
C/M rằng \(\frac{x_1+x_2+x_3...+x_{2004}+x_{2005}}{y_1+y_2+y_3+...+y_{2005}+y_{2005}}=\frac{3}{2}\)
Giải phương trình :
a) \(\frac{x+1}{2020}+\frac{x+2}{2019}+\frac{x+3}{2018}=\frac{x+4}{2017}+\frac{x+5}{2016}+\frac{x+6}{2015}\)
b) \(\frac{2-x}{2004}-1=\frac{1-x}{2005}-\frac{x}{2006}\)
a, Làm
\(\frac{x+1}{2020}+\frac{x+2}{2019}+\frac{x+3}{2018}=\frac{x+4}{2017}+\frac{x+5}{2016}+\frac{x+6}{2015}\)
<=>\(\frac{x+2021}{2020}+\frac{x+2021}{2019}+\frac{x+2021}{2018}=\frac{x+2021}{2017}+\frac{x+2021}{2016}+\frac{x+2021}{2015}\)
<=>\(\left(x+2021\right)\left(\frac{1}{2020}+\frac{1}{2019}+\frac{1}{2018}-\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\right)=0\)
<=> x+2021=0
<=> x=-2021
Kl:......................
b, Làmmmmm
\(\frac{2-x}{2004}-1=\frac{1-x}{2005}-\frac{x}{2006}\)
<=> \(\frac{2006-x}{2004}=\frac{2006-x}{2005}+\frac{2006-x}{2006}\)
<=> \(\left(2006-x\right)\left(\frac{1}{2004}-\frac{1}{2005}-\frac{1}{2006}\right)=0< =>2006-x=0\)
<=> x=2006
Kl:..............
Tinh nhanh :
a) Tu so : 2005*2007-1
Mau so : 2004+2005*2006
b) Tu so : 2003*2004+2005*10+1994
Mau so: 2005*2004-2003*2004
a) \(\frac{2005.2007-1}{2004+2005.2006}=\frac{\left(2014+1\right).2007-1}{2004+2005.2006}=\frac{2004+2005.2007-1}{2004+2005-2006}=\frac{2004+2005.2006}{2004+2005.2006}=1\)
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Tìm x biết: x+2015 / 2004 + x+2015/2005 = x+2015/x+2006 + x+2015/x+2007
A) 2004 * 2005 + 2016 x 6 - 6
2005 x 197 + 4 x 2005
b) 2006 nhân 2005 - 6
2000 + 2006 x 2004
Ai làm nhanh nhất mình tick cho!
Tính nhanh 2004*2004+2006 / 2005*2005-1003
So sánh: \(A=\frac{2015^{2005}+1}{2005^{2006}+1}\) và \(B=\frac{2005^{2004}+1}{2005^{2005}+1}\)
Giúp với Toán 6 đó!
A=\(\frac{2005^{2005}+1}{2005^{2006}+1}\) < 1 => \(\frac{2005^{2005}+1}{2005^{2006}+1}\) < \(\frac{2005^{2005}+1+2004}{2005^{2006}+1+2004}\) = \(\frac{2005^{2005}+2005}{2005^{2006}+2005}\)= \(\frac{2005.\left(2005^{2004}+1\right)}{2005.\left(2005^{2005}+1\right)}\) = \(\frac{2005^{2004}+1}{2005^{2005}+1}\) = B => A<B.
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Ta thấy:A=\(\frac{2005^{2005+1}}{2005^{2006}+1}\)<1
Ta có:A=\(\frac{2005^{2005}+1}{2005^{2006}+1}\)<\(\frac{2005^{2005}+1+2004}{2005^{2006}+1+2004}\)=\(\frac{2005\left(2005^{2004}+1\right)}{2005\left(2005^{2005}+1\right)}\)=b
Vậy A<B
Chắc chắn 100%
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Xem thêm câu trả lời
Tính \(\left(S-P\right)^{2015}+\left(S+P\right)^{2016}\)
\(S=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+......+\frac{1}{2003}-\frac{1}{2004}+\frac{1}{2005}\)
\(P=\frac{1}{1008}+\frac{1}{1009}+.........+\frac{1}{2014}+\frac{1}{2015}\)
Giúp mình nhanh nhé!