tính nhanh: (-16).125.(-3).2 mũ 2 - 2.10 mũ 4 1

Nguyen vu dang nguyen

31 tháng 8 2015 lúc 13:20

Tính nhanh:

a.18 mũ 3 chia 9 mũ 3.

b.125 mũ 3 chia 25 mũ 8.

c.mở ngoặc 10mũ 3 cộng 10 mũ 4 cộng 125 mũ 2 đóng ngoặc chia 5 mũ 3.

d.24 mũ 4 chia 3 mũ 4 trừ 32 mũ 12 chia 16 mũ 12.

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Lớp 6 Toán Câu hỏi của OLM

Phạm Trung Hải

31 tháng 8 2015 lúc 16:34

a,18³:9³=(18-9)³=729

b,còn lại tự làm ,làm mẫu đến đây thôi

l.i.k.e cho mình nha Nguyen vu dang nguyen

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Cuong Nguyenvan

31 tháng 8 2016 lúc 17:59

18³: 9³=8

C) 213

D)0

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Yoo si jin 1983

30 tháng 9 2018 lúc 21:36

Tìm x thuộc N. a) 2 mũ x 16 b) 2 mũ x+1 16 c) 5 mũ x +1 125 d) 5 mũ 2x -1125 e) 12x 144f) 3 mũ x-2 81 g) 4 mũ x +2 4 mũ 3* 64h) 5 mũ 2x -2 125*5 mũ 7k) 4 mũ x -1 16*4 mũ 3m) 3 mũ x+1 9 * 3 mũ 2n) 4/2 mũ x -3 125 i) 2x *16 128 j) 3 mũ x * 9 27 u) 2 mũ x : 2 16 s) 5 mũ 2 x -3 - 2* 5 mũ 2 5 mũ 2*3t) ( 2x +1 ) mũ 3 27 v) ( 8x -14) mũ 4 16r) 4 x mũ 3 +15 47y) ( 7 x -11) mũ 3 2 mũ 5 * 5 mũ 2+200ê) 45 x 81 với x là bội của 9

Đọc tiếp

Tìm x thuộc N.

a) 2 mũ x = 16

b) 2 mũ x+1= 16

c) 5 mũ x +1= 125

d) 5 mũ 2x -1=125

e) 12x =144

f) 3 mũ x-2 =81

g) 4 mũ x +2 = 4 mũ 3* 64

h) 5 mũ 2x -2 =125*5 mũ 7

k) 4 mũ x -1 =16*4 mũ 3

m) 3 mũ x+1 =9 * 3 mũ 2

n) 4/2 mũ x -3 =125

i) 2x *16 =128

j) 3 mũ x * 9 =27

u) 2 mũ x : 2 =16

s) 5 mũ 2 x -3 - 2* 5 mũ 2= 5 mũ 2*3

t) ( 2x +1 ) mũ 3 = 27

v) ( 8x -14) mũ 4 =16

r) 4 x mũ 3 +15 =47

y) ( 7 x -11) mũ 3 = 2 mũ 5 * 5 mũ 2+200

ê) 45< x < 81 với x là bội của 9

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Lớp 6 Toán Câu hỏi của OLM

Trần Tiến Pro ✓

30 tháng 9 2018 lúc 21:59

a) 2^x = 16 e) 12^x = 144

2^x = 2⁴ 12^x = 12²

=> x = 4 => x = 2

b) 2^x+1 = 16 các câu còn lại tương tự nhé nhiều quá

2^x+1 = 2⁴

x + 1 = 4

=> x = 3

c) 5^x+1 = 125

5^x+1 = 5³

x + 1 = 3

=> x = 2

d) 5^{2x - 1} = 125

5^2x-1 = 5³

2x - 1 = 3

2x = 4

=> x = 2

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Nguyễn Trịnh Hoài Hưng

30 tháng 9 2018 lúc 22:02

a)Ta có : 2^x = 16

2^x = 2⁴

=> x = 4

b) Ta có: 2^x+1 = 16

2^x+1 = 2⁴

=> x+1 = 4

=> x = 4-1

=> x = 3

Mấy câu sau tương tự vậy đó để hôm khác mình làm tiếp cho bây giờ mình đi ngủ đã buồn ngủ quá hihi ! ^-^

Học tốt nha bạn !

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NIGHTCORE

3 tháng 10 2018 lúc 21:01

dài vậy cha

ai làm cho

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Trịnh Thành Long K9A2 (...

9 tháng 7 2023 lúc 8:23

bài 4 : viết các biểu thức sau dưới dạng tích

a , 25 x mũ 2 -16

b , 16 a mũ 2 - 9 b mũ 2

c , 8 x mũ 3 + 1

d , 125 x mũ 3 + 27 y mũ 3

e , 8 x mũ 3 - 125

g , 27 x mũ 3 - y mũ 3

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Lớp 8 Toán Câu hỏi của OLM

Kiều Vũ Linh CTV

9 tháng 7 2023 lúc 8:32

a) 25x² - 16

= (5x)² - 4²

= (5x - 4)(5x + 4)

b) 16a² - 9b²

= (4a)² - (3b)²

= (4a - 3b)(4a + 3b)

c) 8x³ + 1

= (2x)³ + 1³

= (2x + 1)(4x² - 2x + 1)

d) 125x³ + 27y³

= (5x)³ + (3y)³

= (5x + 3y)(25x² - 15xy + 9y²)

e) 8x³ - 125

= (2x)³ - 5³

= (2x - 5)(4x² + 10x + 25)

g) 27x³ - y³

= (3x)³ - y³

= (3x - y)(9x² + 3xy + y²)

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Nguyễn Đức Trí

9 tháng 7 2023 lúc 8:33

a) $25x^2-16=\left(5x-4\right)\left(5x+4\right)$

b) $16a^2-9b^2=\left(4a-3b\right)\left(4a+3b\right)$

c) $8x^3+1=\left(2x+1\right)\left(4x^2-2x+1\right)$

d) $125x^3+27y^3=\left(5x+3y\right)\left(25x^2-15xy+9y^2\right)$

e) $8x^3-125=\left(2x-5\right)\left(4x^2-10x+25\right)$

g) $27x^3-y^3=\left(3x-y\right)\left(9x^2+3xy+y^2\right)$

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Đoàn Khôi Nguyên

9 tháng 7 2023 lúc 8:39

tao phá olm đêy nè:

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[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉ύ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉β҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉ύ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉β҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉

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Nguyễn Minh Kim

29 tháng 9 2017 lúc 20:54

Bài 1:So sánh hai lũy thừa sau:

a) 31 mũ 11 và 17 mũ 14

b) 25 mũ 16 và 125 mũ 10

c)32 mũ 18 và 64 mũ 12

Bài 2:Tính tổng

C =1+4+4 mũ 2+4 mũ 3+.....+4 mũ 98

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Lớp 6 Toán Câu hỏi của OLM

Nguyễn Minh Ánh

3 tháng 9 2020 lúc 14:50

Viết kết quả các phép tính sau dưới dạng lũy thừa

a. 2 mũ 20 nhân 15 + 2 mũ 10 nhân 85

b. 27 mũ 16 : 9 mũ 10

c. 125 mũ 3 : 25 mũ 4

d. 24 mũ 4 : 3 mũ 4 - 32 mũ 12:16 mũ 12

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Lớp 6 Toán Câu hỏi của OLM

vinacon

16 tháng 6 2023 lúc 16:48

$a,$

$2^{20} .15 + 2^{10} . 85$

$= 2^{20} . 2^{10} . 85 + 15$

$= 2^{30} . 100$

$= 2^{30} {.10}^{2}$

$b,$

$27^{16} : 9^{10}$

$= (3^{3})^{16} : (3^{2})^{1} 0$

$= 3^{48} : 3^{20}$

$= 3^{28}$

$c,$

$125^{3} : 25^{4}$

$= (5^{3})^{5} : (5^{2})^{4}$

$= 5^{15} : 5^{8}$

$= 5^{7}$

$d,$

$24^{4} : 3^{4} - 32^{12} : 16^{12}$

$= (24 : 3)^{4} - (32 : 16)^{12}$

$= 8^{4} - 2^{12}$

$= (2^{3})^{4} - 2^{12}$

$= 2^{12} - 2^{12}$

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Nguyễn Đức Minh

11 tháng 10 2017 lúc 22:01

a.205-{102-[48-(16-14)mux3]}

b.{[10-2.3).5]+2-2.6}:2+(4+5)mũ2

c.(2 mũ3. 9 mũ 4+9 mũ3.45):(9 mũ 2.10-9 mũ 2)

d.18.[(3 mũ 4.24+3 mũ 4.4-27.3 mũ 4)-71.1 mũ 20]-8

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Lớp 6 Toán Câu hỏi của OLM

hong tran

16 tháng 10 2017 lúc 21:21

không biết làm

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Trương Minh Trí

16 tháng 9 2021 lúc 15:29

Viết kết quả mỗi phép tính sau dưới dạng 1 lũy thừa: 2 mũ 10÷64×16 2 mũ 10×8 3 mũ 5÷27 5 mũ 2×125 6 mũ 6÷36

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Lớp 6 Toán Câu hỏi của OLM

Nguyễn Trọng Hoàng Thủy

16 tháng 9 2021 lúc 16:46

2^(10 : 64 x 16) = 2^[(10 x 16) : 64] = 2^(160 : 64) = 2^25

2^(10 x 8) = 2^80 3^(5 : 27) = 3^(5/27) 5^(2 x 125) = 5^250 6^(6 : 36) = 6^(1/6)

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Khách vãng lai đã xóa

BÙI BẢO KHÁNH

10 tháng 8 2023 lúc 15:19

Bài 2: Tìm số tự nhiên x,biết: 1, 2 mũ x 4 2, 2 mũ x 8 3, 2 mũ x 16 4, 2 mũ x 1 5, 3 mũ x 9 6, 3 mũ x 81 7, 3 mũ x 27 8, 5 mũ x 25 9, 5 mũ x 125 10, 8 mũ x 64 11, 3 mũ x + 1 3 mũ 2 12, 2 mũ 2 x + 1 2 mũ 7 13, 5 mũ x - 1 5 mũ 2 14, 5 mũ 2 x - 4 5 mũ 10 15, 6 x + 4 6 mũ 10 16, 2 mũ 2 x - 3 2 mũ 9 17, 7 mũ 2 x - 3 7 mũ 7 18, 8 mũ x - 2 1 19, 9 mũ x - 8 81 20, 10 mũ 2 x - 1 1000 Giúp mình với,mình đang cần gấp !!

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Bài 2: Tìm số tự nhiên x,biết:

1, 2 mũ x = 4

2, 2 mũ x = 8

3, 2 mũ x = 16

4, 2 mũ x = 1

5, 3 mũ x = 9

6, 3 mũ x = 81

7, 3 mũ x = 27

8, 5 mũ x = 25

9, 5 mũ x = 125

10, 8 mũ x = 64

11, 3 mũ x + 1 = 3 mũ 2

12, 2 mũ 2 x + 1 = 2 mũ 7

13, 5 mũ x - 1 = 5 mũ 2

14, 5 mũ 2 x - 4 = 5 mũ 10

15, 6 x + 4 = 6 mũ 10

16, 2 mũ 2 x - 3 = 2 mũ 9

17, 7 mũ 2 x - 3 = 7 mũ 7

18, 8 mũ x - 2 = 1

19, 9 mũ x - 8 = 81

20, 10 mũ 2 x - 1 = 1000

Giúp mình với,mình đang cần gấp !!

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Lớp 6 Toán Câu hỏi của OLM

Lê Phương Mai

16 tháng 7 2021 lúc 20:02

Bài 7. Tính nhanha/ 498mũ 2b/ 93. 107c/ 163 mũ 2+ 74.163 + 37mũ 2d/ 1995 mũ 2 – 1994.1996e/ 9 mũ 8.2 mũ 8 – (18mũ 4 – 1)(18 mũ 4+ 1)f/ 125 mũ 2 - 2. 125. 25 + 25 mũ 2Bài 8. Rút gọn các biểu thức saua/ (x mũ 2+ 3x+ 1)mũ 2 + (3x – 1) mữ 2 – 2(x mũ 2+ 3x+ 1)(3x– 1)b/ (3x mũ 3+ 3x + 1)(3x mũ 3– 3x +1) – (3xmũ 3+1)mũ 2c/ (2xmũ2+ 2x + 1)(2xmũ2 – 2x + 1) – (2xmũ 2+ 1)mũ 2Bài 9. Rút gọn rồi tính giá trị biểu thức a/ A (2x + y)mũ 2 - (2x + y) (2x - y)+ y(x - y) vì x - 2; y 3.b/ B (a - 3b)mũ 2 - (a + 3b...

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Bài 7. Tính nhanh

a/ 498mũ 2

b/ 93. 107

c/ 163 mũ 2+ 74.163 + 37mũ 2

d/ 1995 mũ 2 – 1994.1996

e/ 9 mũ 8.2 mũ 8 – (18mũ 4 – 1)(18 mũ 4+ 1)

f/ 125 mũ 2 - 2. 125. 25 + 25 mũ 2

Bài 8. Rút gọn các biểu thức sau

a/ (x mũ 2+ 3x+ 1)mũ 2 + (3x – 1) mữ 2 – 2(x mũ 2+ 3x+ 1)(3x– 1)

b/ (3x mũ 3+ 3x + 1)(3x mũ 3– 3x +1) – (3xmũ 3+1)mũ 2

c/ (2xmũ2+ 2x + 1)(2xmũ2 – 2x + 1) – (2xmũ 2+ 1)mũ 2

Bài 9. Rút gọn rồi tính giá trị biểu thức

a/ A = (2x + y)mũ 2 - (2x + y) (2x - y)+ y(x - y) vì x= - 2; y= 3.

b/ B = (a - 3b)mũ 2 - (a + 3b)mũ 2 - (a -1)(b -2 ) vì a =1/2; b = -3.

MN GIÚP MIK VS MIK CẦN GẤP

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Lớp 8 Toán Bài 3: Những hằng đẳng thức đáng nhớ

Nguyễn Lê Phước Thịnh CTV

16 tháng 7 2021 lúc 20:40

Bài 9:

a) Ta có: $A=\left(2x+y\right)^2-\left(2x+y\right)\left(2x-y\right)+y\left(x-y\right)$

$=4x^2+4xy+y^2-4x^2+y^2-xy-y^2$

$=3xy-y^2$

$=3\cdot\left(-2\right)\cdot3-3^2=-18-9=-27$

b) Ta có: $B=\left(a-3b\right)^2-\left(a+3b\right)^2-\left(a-1\right)\left(b-2\right)$

$=a^2-6ab+9b^2-a^2-6ab-9b^2-ab+2a+b-2$

$=-13ab+2a+b-2$

$=-13\cdot\dfrac{1}{2}\cdot\left(-3\right)+2\cdot\dfrac{1}{2}+\left(-3\right)-2$

$=\dfrac{31}{2}$

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Nguyễn Lê Phước Thịnh CTV

16 tháng 7 2021 lúc 20:36

Bài 7:

a) $498^2=\left(500-2\right)^2=250000-2000+4=248004$

b) $93\cdot107=100^2-7^2=10000-49=9951$

c) $163^2+74\cdot163+37^2=\left(163+37\right)^2=200^2=40000$

d) $1995^2-1994\cdot1996=1995^2-1995^2+1=1$

e) $9^8\cdot2^8-\left(18^4-1\right)\left(18^4+1\right)$

$=18^8-18^8+1=1$

f) $125^2-2\cdot125\cdot25+25^2=\left(125-25\right)^2=100^2=10000$

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Nguyễn Lê Phước Thịnh CTV

16 tháng 7 2021 lúc 23:20

Bài 8:

a) Ta có: $\left(x^2+3x+1\right)^2-2\left(x^2+3x+1\right)\left(3x-1\right)+\left(3x-1\right)^2$

$=\left(x^2+3x+1-3x+1\right)^2$

$=\left(x^2+2\right)^2$

$=x^4+4x^2+4$

b) Ta có: $\left(3x^3+3x+1\right)\left(3x^3-3x+1\right)-\left(3x^3+1\right)^2$

$=\left(3x^3+1\right)^2-9x^2-\left(3x^3+1\right)^2$

$=-9x^2$

c) Ta có: $\left(2x^2+2x+1\right)\left(2x^2-2x+1\right)-\left(2x^2+1\right)^2$

$=\left(2x^2+1\right)^2-4x^2-\left(2x^2+1\right)^2$

$=-4x^2$

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