x x 36 = 1692
1316 : x = 282 : 6
1) 444 x 5 = 222 x 2 x 5 = 222 x 10 = 2220
a.Đúng b.Sai
2) 282 x 5 = 280 + 2 x 5 = 280 x 10 = 2800
a.Đúng b. Sai
3) 4 x 8 x 7 x 25 = (8 x 7) x (25 x4) = 56 x 100 = 5600
a.Đúng b.Sai
4) 25 x 8 x 9 = (25 x 4) x (4 x 9) = 100 x 36 = 3600
a.Đúng b.Sai
1. 444 x 5 = 222 x 2 x 5 = 222 x 10 = 2220
2. 282 x 5 = 280 + 2 x 5 = 280 x 10 = 2800
3. 4 x 8 x 7 x 25 = (8 x 7) x (25 x4) = 56 x 100 = 5600
4. 25 x 8 x 9 = (25 x 4) x (4 x 9) = 100 x 36 = 3600
a.Đúng b.Sai
Đúng ghi Đ, sai ghi S
13 x 3 - 2 = 13
180 + 30 : 6 = 35
30 + 60 x 2 = 180
282 - 100 : 2 = 232
13 x 3 - 2 = 13 : S
180 + 30 : 6 = 35 : S
30 + 60 x 2 = 180 : S
282 - 100 : 2 = 232 : Đ
Đúng ghi Đ, sai ghi S
37 - 5 x 5 = 12
180 : 6 + 30 = 60
30 + 60 x 2 = 150
282 - 100 : 2 = 91
37 - 5 x 5 = 12 : Đ
180 : 6 + 30 = 60 : Đ
30 + 60 x 2 = 150 : Đ
282 - 100 : 2 = 91 : S
X x 282 - 270 x X = 1512
\(x\times282-270\times x=1512\\ x\times\left(282-270\right)=1512\\ x\times12=1512\\ x=1512:12\\ x=126\)
x×282−270×x=1512
x×(282−270)=1512
x×12=1512
x=1512:12
x=126
Chúc cậu học tốt nha :3Tính nhanh:
13360 - 36 x 6 - 36 x 4
14460 - 46 x 6 - 46 x 4
câu 1= 13288
câu 2=14368
chúc bạn học giỏi
1, Tìm x, biết \(x^2\) – 36 = 0
A. x = 6. B. x = -6.
C. x = 6; x = -6. D. x = 36 hoặc x = - 36.
2, Tìm x, biết \(x^3\) – 3\(x^2\) + 3x - 1 = 0
A. x = 1. B. x = -1. C. x = 0. D. x = 2.
Tìm x :
(x x 45) - 123 = 282
x x 45 =282 +123=405
x = 405/45 =9 k nha
( X x 45 ) - 123 = 282
X x 45 = 282 -123
X x 45 = 405
X = 405 : 45
X = 9
Tìm x:
a) X : 8 = 101
....................
....................
b) X : 5 = 117
....................
....................
c) X : 3 = 282
....................
....................
a) X : 8 = 101
X = 101 x 8
X = 808
b) X : 5 = 117
X = 117 x 5
X = 585
c) X : 3 = 282
X = 282 x 3
X = 846
giải phương trình
\(\dfrac{36}{x-6}+\dfrac{36}{x+6}=4,5\)
\(\Leftrightarrow36\left(x+6\right)+36\left(x-6\right)=\dfrac{9}{2}\left(x^2-36\right)\)
\(\Leftrightarrow x^2\cdot\dfrac{9}{2}-162-72x=0\)
\(\Leftrightarrow9x^2-144x-324=0\)
\(\Leftrightarrow x^2-16x-36=0\)
=>(x-18)(x+2)=0
=>x=18 hoặc x=-2
ĐKXĐ:\(x\ne\pm6\)
\(\dfrac{36}{x-6}+\dfrac{36}{x+6}=4,5\\ \Leftrightarrow36\left(\dfrac{1}{x-6}+\dfrac{1}{x+6}\right)=4,5\\ \Leftrightarrow\dfrac{x+6}{\left(x-6\right)\left(x+6\right)}+\dfrac{x-6}{\left(x-6\right)\left(x+6\right)}=\dfrac{1}{8}\\ \Leftrightarrow\dfrac{x+6+x-6}{x^2-36}=\dfrac{1}{8}\\ \Leftrightarrow\dfrac{2x}{x^2-36}=\dfrac{1}{8}\\ \Leftrightarrow x^2-36=16x\\ \Leftrightarrow x^2-16x-36=0\\ \Leftrightarrow\left(x^2+2x\right)-\left(18x+36\right)=0\\ \Leftrightarrow x\left(x+2\right)-18\left(x+2\right)=0\\ \Leftrightarrow\left(x+2\right)\left(x-18\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\left(tm\right)\\x=18\left(tm\right)\end{matrix}\right.\)