\(5830+\left(-993\right)+170+4007\\ =4837+170+4007\\ =5007+4007\\ =9014\)

(5830 + 170) + ( - 993 + 4007 )
= 6000 + 3014
= 9014

= (5830+170) + (-993-4007)

= 6000 + (-5000)

=1000

h: =7000-6000

=1000

a,  

\(\frac{14}{6}+\frac{1}{9}+\frac{19}{13}+\frac{17}{9}+\frac{7}{13}+\frac{4}{6}\)

\(=\left(\frac{14}{6}+\frac{4}{6}\right)+\left(\frac{1}{9}+\frac{17}{9}\right)+\left(\frac{19}{13}+\frac{7}{13}\right)\)

\(=\frac{18}{6}+\frac{18}{9}+\frac{26}{13}\)

  \(=3+2+2\)

\(=7\)

b,

\(\frac{995}{997}x\frac{990}{993}x\frac{997}{990}x\frac{993}{995}x\frac{97}{95}\)

\(=\frac{995x990x997x993x97}{997x993x990x995x95}\)
\(=\frac{97}{95}\)

(Cùng triệt tiêu 995 ; 990 ; 997 ; 993 )

    993 x 11 + 77

=993 x 11 + 7x 11

= 11 x ( 993 + 7 )

= 11x 1000

= 11000

ĐÚng cho mình nha 

Lời giải:

a. $99^3+1+3(99^2+99)=99^3+3.99^2.1+3.99.1^2+1^3=(99+1)^3=100^3=1000000$

b. $11^3-1-3(11^2-11)=11^3-3.11^2.1+3.11.1^2-1^3=(11-1)^3=10^3=1000$

\(A=1-2-3+4+5-6-7+8...+993-994-995+996+997\)

\(A=\left(1-2-3+4\right)+\left(5-6-7+8\right)...+\left(993-994-995+996\right)+997\)

\(A=0+0+...+0+997=997\)

a) ( 100   –   1 ) 3  = 970299.                          b) ( 91   +   9 ) 3   =   100 3 .

c) ( 1000   +   1 ) 3  = 1003003001.                d) ( 102   –   2 ) 3   =   100 3 .